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Subsampling for supervised learning in reproducing kernel Hilbert spaces

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Subsampling for supervised learning in reproducing kernel Hilbert spaces

Eyal Vayness & Maxime Sangnier Affiliation: Sorbonne Université, LPSM, Paris, France
August 10, 2026
Abstract

In the era of big data, subsampling became a common practice in statistical learning. By selecting a subgroup of individuals based on which the learner is trained, subsampling aims at reducing the computational cost and time of the estimation step, and ideally leads to a decrease of its energy consumption and carbon footprint. This work focuses on a nonparametric setting, in which the hypotheses set lies in a reproducing kernel Hilbert space, and the estimator is a minimizer of an empirical risk reweighted à la Horvitz-Thompson. By studying the asymptotic properties of this estimator, we reveal an optimal subsampling scheme (regarding the trace of the covariance operator) and show that it can be used via plug-in. A numerical study on synthetic and real-world datasets shows the practicability and the benefit of the proposed approach.

1 Introduction

As of the last couple decades, the overwhelming data accumulation in various domains such as medical research, road safety, bioinformatics, physics, genetics and social media, led scientists to rethink standard statistical learning methods. Beyond the computational barrier (in time and memory) induced by the data deluge and the economic cost of training models on large datasets, the overconsumption of energy resources also became a concerning topic for the scientific community. With this in mind, it is of interest to reduce the computational cost of learning methods, particularly regarding their training phase, which often involves minimizing an objective function and is more demanding than inference.

A first thought to limit the computational burden of training procedures, is to leverage more efficient optimization algorithms, such as active set strategies (24), stochastic gradient methods (3; 7) and random coordinate descents (39; 14), to cite only a few. However, these approaches still work on the whole training set, which may include either redundant or quite uninformative observations. Data set reduction methods can then be used in order to reduce the effective size of the dataset, while producing only informative datapoints. Sketching, for instance, is a way to reduce the dataset by generating new individuals, which are linear combinations of the original ones (30; 32; 47). Another approach is the coreset technique, which randomly pick points from de dataset in order to uniformly approximate the objective function (22; 29; 25; 35; 5). Nonuniform subsampling of points can also be implemented thanks to their leverage scores (28; 9; 49; 27), which are based on the covariates but not on the target values. Stepping back, subsampling can also be analyzed for general inclusion probabilities, from the excess risk point of view (8; 18) and the estimator asymptotic distribution side (44; 46; 19). In the latter case, it is even possible to exhibit an optimal subsampling scheme, which minimizes the trace of the limit covariance matrix. Several other approaches exist, such as sampling with influence functions (41) and leveraging minimum enclosing ball from computational geometry (42).

At this step, we remark that many methods, such as stochastic optimization and sketching, are task-agnostic, which leaves an area of improvement. Moreover, if coreset techniques propose data-dependent sampling procedures, these ones are aimed at uniform approximation the objective function and consequently often leverage intractable probabilities (29; 5). On the contrary, optimal subsampling proposes an easy-to-implement way to extract informative individuals from the original dataset, such that the trace of the asymptotic covariance matrix is minimal (46).

In this work, we focus on nonparametric supervised learning, and in particular on kernel methods, where the hypotheses lie in a reproducing kernel Hilbert space (RKHS) (2). In this case, few of the methods described above can be used (they have been mainly designed for parametric inference), the most notable being sketching (50; 12; 11) and specific approaches tailored for support vector machines, such as minimum enclosing balls (42) and stochastic subgradient algorithm (38). However, kernel learning can rely on kernel approximation techniques to lighten the numerical training cost, which consists in replacing either the Gram matrix by a low-rank approximation (for instance, thanks to the Nyström method (48; 10; 33)), or the feature map by a finite-dimensional mapping (thanks to random Fourier features (RFF) (31; 4; 34; 26)). Since the computational cost of a kernel method is mainly function of the size of the optimization problem to solve (which is basically represented by the spatial complexity of the design or Gram matrix of the effective dataset), the appeal of the Nyström method, RFF and sketching is to cut down the computational burden from O⁡(n2)O(n^{2}) (for an initial dataset of size nn) to O⁡(n​m)O(nm), where mm an approximation parameter (the dimension of the subspace for the Nyström method, the number of random projections for RFF, the number of linear combinations for the sketching approach). If this is a big gain, we remark that the computational cost still depends on the size nn of the original dataset, which may be very large in practice. On the contrary, subsampling ss datapoints would lead to a O⁡(s2)O(s^{2}) cost, which is largely less.

We thus aim at designing a data-dependent subsampling procedure for nonparametric supervised learning in RKHSs. From the methodological side, we follow the line of research initiated by 44 (then followed by numerous papers including (45; 46; 19; 40)), which determines the subsampling scheme minimizing the trace of the asymptotic covariance matrix of a M-estimator of an empirical risk reweighted à la Horvitz-Thompson. From the theoretical side, we study asymptotics in RKHSs with tools coming from functional random probability spaces (6; 21) with pieces of elements from martingale theory (17). These two aspects distinguish our work from that by 46 since we place ourself in a particular nonparametric setting and employ different techniques of proof. The latter are also different from the empirical process techniques used by 16; 36 for analyzing usual empirical risk minimizers (ERMs).

In Section 2, we first revisit asymptotic normality of the ERM in RKHSs, based on the asymptotically finite-dimensional property (21; 43). This result corroborates the ones presented in (16; 36) and comes with a complementary technique of proof. Then, in Section 3, the subsampled risk minimizer (SRM) is presented as well as its convergence and asymptotic distribution. Section 4 exhibits the optimal subsampling scheme and Section 5 presents a way to implement it in practice. Le latter strategy is numerically evaluated on synthetic and real-world datasets in Section 6, and favorably compared to state-of-the-art approximation techniques for kernel methods.11 1 The Python source code for reproducing the numerical experiments is provided at https://gitlab.com/Yaloude/rkhs-subsampling. All proofs are gathered in Appendix A.

2 Background

Let Z∈𝒵⊂ℝd+1Z\in\mathcal{Z}\subset\mathbb{R}^{d+1} be the random variable of interest with unknown distribution. We focus here on supervised learning and assume that ZZ has a canonical decomposition: Z=(X,Y)∈𝒳×𝒴⊂ℝd×ℝZ=(X,Y)\in\mathcal{X}\times\mathcal{Y}\subset\mathbb{R}^{d}\times\mathbb{R} where XX is the vector of covariates and YY is the response. Denote ℓ:ℝ×𝒴→ℝ\ell:\mathbb{R}\times\mathcal{Y}\rightarrow\mathbb{R} the loss function associated to the learning task of interest, and assume that ℓ\ell is non-negative, convex and twice-differentiable in its first argument. The setting defined this way suits both binary classification: 𝒴={±1}\mathcal{Y}=\{\pm 1\} and for instance ℓ⁡(y^,y)=log⁡(1+exp⁡(−y​y^))\ell(\hat{y},y)=\log(1+\exp(-y\hat{y})) for logistic regression (where y^∈ℝ\hat{y}\in\mathbb{R} is a prediction compared to y∈𝒴y\in\mathcal{Y}); as well as regression: 𝒴=ℝ\mathcal{Y}=\mathbb{R} and for example ℓ⁡(y^,y)=1p​|y^−y|p\ell(\hat{y},y)=\frac{1}{p}|\hat{y}-y|^{p} for LpL^{p} regression.

The working set of predictors is ℍ\mathbb{H}, the RKHS induced by some kernel k:𝒳×𝒳→ℝk:\mathcal{X}\times\mathcal{X}\rightarrow\mathbb{R} (i.e. a symmetric and positive definite function). In other words, ℍ\mathbb{H} is the closure of the span of the map by kk of elements of 𝒳\mathcal{X}, i.e.

ℍ=defspan⁡{Kx:x∈𝒳}¯,\mathbb{H}\overset{\mathrm{def}}{=}\overline{\spn\{K_{x}:x\in\mathcal{X}\}},

where Kx=k⁡(x,⋅)K_{x}=k(x,\cdot) for all x∈𝒳x\in\mathcal{X}.

Given the previous elements, the population risk function of the learning task considered is:

L:h∈ℍ↦𝔼⁡[ℓ⁡(h⁡(X),Y)],\addcontentsline{lla}{section}{\numberline q:true_{l}oss}{L}:h\in\mathbb{H}\mapsto\mathbb{E}\left[\ell(h(X),Y)\right], (1)

which could be minimized so as to obtain an optimal predictor. However two problems arise: first, the distribution of Z=(X,Y)Z=(X,Y) is assumed unknown (such that the expectation in (1) cannot be computed); second, the current assumptions do not ensure existence of a minimizer of LL in ℍ\mathbb{H}. To solve those problems, we turn towards the empirical version of (1):

Ln​(h)​=def​1n​∑i=1nℓ⁡(h⁡(Xi),Yi),\addcontentsline{lla}{section}{\numberline q:empirical_{l}oss}{L}_{n}(h)\overset{\mathrm{def}}{=}\frac{1}{n}\sum_{i=1}^{n}\ell(h(X_{i}),Y_{i}), (2)

based on a dataset 𝒟n={Z1,…,Zn}={(X1,Y1),…,(Xn,Yn)}{\mathcal{D}_{n}}=\{Z_{1},\dots,Z_{n}\}=\{(X_{1},Y_{1}),\dots,(X_{n},Y_{n})\} made of independent and identically distributed (i.i.d.) random variables sharing the same distribution as Z=(X,Y)Z=(X,Y), and add a ridge penalization tuned by some parameter λ0>0{\lambda_{0}}>0 for the true risk and by λn>0{\lambda_{n}}>0 (a possibly random parameter) for the empirical one. The objective functions, namely the true and empirical regularized risks now read:

ℛ⁡(h)​=def​L​(h)+λ02​‖h‖ℍ2,\addcontentsline{lla}{section}{\numberline q:true_{r}isk}{\mathcal{R}}(h)\overset{\mathrm{def}}{=}{L}(h)+\frac{{\lambda_{0}}}{2}\|h\|_{\mathbb{H}}^{2}, (3)

and

ℛn​(h)​=def​Ln​(h)+λn2​‖h‖ℍ2.\addcontentsline{lla}{section}{\numberline q:empirical_{r}isk}{\mathcal{R}}_{n}(h)\overset{\mathrm{def}}{=}{L}_{n}(h)+\frac{{\lambda_{n}}}{2}\|h\|_{\mathbb{H}}^{2}. (4)

Let us remark that minimizing ℛ{\mathcal{R}} (respectively ℛn{\mathcal{R}}_{n}) is equivalent to minimizing LL (respectively LnL_{n}) inside a ball of ℍ\mathbb{H}, the radius of which depending both on the penalization parameter λ0{\lambda_{0}} (respectively λn{\lambda_{n}}) and the data (see for example (36)). In addition, the framework above offers the chance to take λn≠λ0{\lambda_{n}}\neq{\lambda_{0}}, which makes sens in practice since penalizing is also a way to prevent overfitting, on the condition that the penalization parameter λn{\lambda_{n}} is tuned with respect to the sample size nn and the data (roughly speaking, the less the data, the stronger the penalization).

Now, by convexity of the loss ℓ\ell (with respect to its first argument) and λ0>0{\lambda_{0}}>0, the true regularized risk ℛ{\mathcal{R}} is lower semi-continuous and strongly convex, and admits a unique minimizer in ℍ\mathbb{H}, denoted h0{h_{0}} (6, Lemma 2.15). The same holds true for the empirical regularized risk ℛn{\mathcal{R}}_{n} (since λn>0{\lambda_{n}}>0), the minimizer of which is denoted h^n∈ℍ{\hat{h}_{n}}\in\mathbb{H}.

2.1 Assumptions

Before introducing the proposed subsampling estimator, we aim at presenting the asymptotic distribution of h^n{\hat{h}_{n}} as a stepping stone to our main result. This requires a few assumptions, which will be needed all along our analysis.

Assumption 1.

The kernel k:𝒳×𝒳→ℝk:\mathcal{X}\times\mathcal{X}\rightarrow\mathbb{R} is continuous and bounded: there exists κ>0\kappa>0 such that supx∈𝒳k⁡(x,x)≤κ\sup_{x\in\mathcal{X}}\sqrt{k(x,x)}\leq\kappa.

Assumption 1 is standard in the analysis of estimators lying in RKHSs (see for instance (1)). In particular, the continuity of kk (jointly with 𝒳\mathcal{X} being separable) leads the RKHS ℍ\mathbb{H} to be separable (6, Lemma 4.33). This means that there exists a complete orthonormal system (ej)j∈ℕ(e_{j})_{j\in\mathbb{N}} of ℍ\mathbb{H} (i.e. ‖ej‖ℍ=1\|e_{j}\|_{\mathbb{H}}=1 and ⟨ej,ek⟩ℍ=0\langle e_{j},e_{k}\rangle_{\mathbb{H}}=0 for all j,k∈ℕj,k\in\mathbb{N}, k≠jk\neq j), which will enable to define the trace of a linear operator in ℍ\mathbb{H} in Section 3. The bound κ\kappa, as for it, leads to bounded predictors (sup𝒙∈𝒳|h⁡(𝒙)|<∞\sup_{\bm{x}\in\mathcal{X}}|h(\bm{x})|<\infty, for all h∈ℍh\in\mathbb{H}) (6, Lemma 4.28), which helps in obtaining convergence of empirical quantities (see Appendix A).

Henceforth, let ℓ′\ell^{\prime} and ℓ′′\ell^{\prime\prime} be respectively the first and second partial derivatives of ℓ\ell with respect to its first variable.

Assumption 2.

For all y∈𝒴y\in\mathcal{Y} and B>0B>0, the loss ℓ\ell and its derivatives, ℓ′\ell^{\prime} and ℓ′′\ell^{\prime\prime}, are ϕB​(y)\phi_{B}(y)-Lipschitz in their first variable on [−B,B][-B,B], i.e. for k∈{0,1,2}k\in\{0,1,2\}:

|ℓ(k)​(y^1,y)−ℓ(k)​(y^2,y)|≤ϕB​(y)​|y^1−y^2|,|\ell^{(k)}(\hat{y}_{1},y)-\ell^{(k)}(\hat{y}_{2},y)|\leq\phi_{B}(y)|\hat{y}_{1}-\hat{y}_{2}|,

for all y^1,y^2∈[−B,B]\hat{y}_{1},\hat{y}_{2}\in[-B,B].

Assumption 3.

For all B>0B>0 and k∈{0,1,2}k\in\{0,1,2\}, 𝔼⁡[ϕB​(Y)4]\mathbb{E}\left[\phi_{B}(Y)^{4}\right] and 𝔼⁡[ℓ(k)​(0,Y)4]\mathbb{E}\left[\ell^{(k)}(0,Y)^{4}\right] exists and are finite.

Assumption 2 asks for ℓ\ell and its derivatives to be locally Lipschitz continuous in their first argument. For simplicity, we consider the same Lipschitz coefficient ϕB​(⋅)\phi_{B}(\cdot) for all derivatives. In particular, if ℓ\ell is thrice-differentiable, then one may choose, for all y∈𝒴y\in\mathcal{Y} and B>0B>0, ϕB​(y)=max⁡supt∈[−B,B]k∈{1,2,3}⁡ℓ(k)​(t,y)\phi_{B}(y)=\max_{k\in\{1,2,3\}}\sup_{t\in[-B,B]}\ell^{(k)}(t,y). Assumption 3 as for it, is a common moment assumption in asymptotic analyses, except that it is required up to the degree 44 in order to handle the Horvitz-Thompson reweighting introduced in Section 3. In addition, Assumptions 2 and 3 (with Assumption 1) yields that ℓ′​(h0​(X),Y)​KX\ell^{\prime}({h_{0}}(X),Y)K_{X} and ℓ′′​(h0​(X),Y)​KX\ell^{\prime\prime}({h_{0}}(X),Y)K_{X} have a finite fourth order moment.

At last, Assumption 4 asks for the convergence of the regularization parameter λn{\lambda_{n}} towards λ0{\lambda_{0}} at a rate greater than 1/n1/\sqrt{n}, which is basically that of Ln​(h)L_{n}(h) towards L⁡(h)L(h), for any h∈ℍh\in\mathbb{H}.

Assumption 4.

The (random) regularization parameter sequence (λn)n>0({\lambda_{n}})_{n>0} verifies that λn>0{\lambda_{n}}>0 almost surely for all n>0n>0 and

n​(λn−λ0)​⟶n→∞ℙ​0.\sqrt{n}({\lambda_{n}}-{\lambda_{0}})\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.

2.2 Asymptotic normality of ERM

With the assumptions stated above, our first step is to derive gradients of the regularized risks. Indeed, since ℓ∈𝒞2\ell\in\mathscr{C}^{2}, the empirical regularized risk ℛn{\mathcal{R}}_{n} is twice-differentiable and its minimizer h^n{\hat{h}_{n}} verifies the following stationarity condition:

∇ℛn(h^n)=0⇔λnh^n=−∇Ln(h^n),\nabla{\mathcal{R}}_{n}({\hat{h}_{n}})=0\quad\Leftrightarrow\quad{\lambda_{n}}{\hat{h}_{n}}=-\nabla{L}_{n}({\hat{h}_{n}}), (5)

with

∇Ln​(h)=1n​∑i=1nℓ′​(h⁡(Xi),Yi)​KXi,\nabla{L}_{n}(h)=\frac{1}{n}\sum_{i=1}^{n}\ell^{\prime}(h(X_{i}),Y_{i})K_{X_{i}}, (6)

for all h∈ℍh\in\mathbb{H}. In addition, letting “⊗\otimes” being the outer product in ℍ\mathbb{H} (i.e. for all h,f∈ℍh,f\in\mathbb{H}, (h⊗f)(h\otimes f) is a linear operator from ℍ\mathbb{H} to ℍ\mathbb{H} such that, for all g∈ℍg\in\mathbb{H}, (h⊗f)​g​=def​⟨f,g⟩ℍ​h(h\otimes f)g\overset{\mathrm{def}}{=}\langle f,g\rangle_{\mathbb{H}}h) one may also compute the Hessian operators of the empirical risks:

∇2Ln​(h)=1n​∑i=1nℓ′′​(h⁡(Xi),Yi)​KXi⊗KXiand∇2ℛn​(h)=∇2Ln​(h)+λn​idℍ,\nabla^{2}{L}_{n}(h)=\frac{1}{n}\sum_{i=1}^{n}\ell^{\prime\prime}(h(X_{i}),Y_{i})K_{X_{i}}\otimes K_{X_{i}}\quad\text{and}\quad\nabla^{2}{\mathcal{R}}_{n}(h)=\nabla^{2}{L}_{n}(h)+{\lambda_{n}}\mathrm{id}_{\mathbb{H}}, (7)

where idℍ\mathrm{id}_{\mathbb{H}} is the identity operator in ℍ\mathbb{H}.

The same applies to the true regularized risk ℛ{\mathcal{R}}: according to Lemma A.1, under Assumptions 1, 2 and 3, ℛ{\mathcal{R}} is twice differentiable at h0{h_{0}}, with:

∇ℛ​(h0)=∇L​(h0)+λ0​h0and∇2ℛ​(h0)=∇2L​(h0)+λ0​idℍ,\nabla{\mathcal{R}}({h_{0}})=\nabla{L}({h_{0}})+{\lambda_{0}}{h_{0}}\quad\text{and}\quad\nabla^{2}{\mathcal{R}}({h_{0}})=\nabla^{2}{L}({h_{0}})+{\lambda_{0}}\mathrm{id}_{\mathbb{H}},

where

∇L​(h0)=𝔼⁡[ℓ′​(h0​(X),Y)​KX]and∇2L​(h0)=𝔼⁡[ℓ′′​(h0​(X),Y)​KX⊗KX].\nabla{L}({h_{0}})=\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)K_{X}\right]\quad\text{and}\quad\nabla^{2}{L}({h_{0}})=\mathbb{E}\left[\ell^{\prime\prime}({h_{0}}(X),Y)K_{X}\otimes K_{X}\right].

Let us remark that ∇2ℛ\nabla^{2}{\mathcal{R}} is continuous at h0{h_{0}} and that ∇2ℛ​(h0)\nabla^{2}{\mathcal{R}}({h_{0}}) is invertible (16, Lemma A.5).

We are now ready to state asymptotic normality of h^n{\hat{h}_{n}}. For this purpose, let us recall that we say that HH is a Gaussian process in ℍ\mathbb{H} with mean 00 and covariance operator Σ:ℍ→ℍ\Sigma:\mathbb{H}\to\mathbb{H}, denoted H∼𝒢⁡(0,Σ)H\sim\mathcal{G}(0,\Sigma), if for any positive integer mm and h1,…,hm∈ℍh_{1},\dots,h_{m}\in\mathbb{H}, (⟨H,h1⟩ℍ,…,⟨H,hm⟩ℍ)⊤∼𝒩⁡(0,(⟨Σ​hi,hj⟩ℍ)1≤i,j≤m)(\langle H,h_{1}\rangle_{\mathbb{H}},\dots,\langle H,h_{m}\rangle_{\mathbb{H}})^{\top}\sim\mathcal{N}(0,(\langle\Sigma h_{i},h_{j}\rangle_{\mathbb{H}})_{1\leq i,j\leq m}).

Theorem 2.1 (Asymptotic normality of h^n{\hat{h}_{n}}).

Under Assumptions 1, 2, 3 and 4, one has

n​∇2ℛ​(h0)​(h^n−h0)​⟶n→∞d​𝒢​(0,Σ),\sqrt{n}\nabla^{2}{\mathcal{R}}({h_{0}})({\hat{h}_{n}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma),

with Σ​=def​𝔼​[ℓ′​(h0​(X),Y)2​KX⊗KX]−∇L​(h0)⊗∇L​(h0)\Sigma\overset{\mathrm{def}}{=}\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-\nabla{L}({h_{0}})\otimes\nabla{L}({h_{0}}).

The proof of Theorem 2.1 (see Section A.2) is close to that in a parametric model, thanks to a Cramér-Wold-type result. The latter holds for, given assumptions on the considered RKHS ℍ\mathbb{H}, random sequences are asymptotically finite-dimensional in the sense of (43, Chapter 1.8) or (21, Theorem 7.7.5).

Asymptotic properties of the ERM in the non-parametric framework of RKHSs are known. Main results include consistency (6), outlining of a limit Gaussian process (16), and asymptotic normality in a ball of ℍ\mathbb{H} (36). Theorem 2.1 is similar to a result by 16; 15, but the proofs differ since 16; 15 make use of a functional delta method on the empirical process. Theorem 2.1 is nonetheless of interest for it and its proof serve as stepping stones to our main result.

3 Asymptotics of subsampling

We now introduce, in this section, the two considered subsampling strategies (with and without replacement), along with the corresponding estimators, nicknamed SRM in both cases. We then prove asymptotic normality of both estimators with general subsampling schemes, and discuss in the next section the choice of the latter.

Let Δn−1={𝒙∈(0,1)n,∑i=1nxi=1}\Delta_{n-1}=\{\bm{x}\in(0,1)^{n},\sum_{i=1}^{n}x_{i}=1\} be the set of probability vectors of size nn, and consider 𝝅n∈Δn−1{\bm{\pi}}_{n}\in\Delta_{n-1} a subsampling probability (SSP) vector, which may ultimately depend on the dataset 𝒟n{\mathcal{D}_{n}}. A subsampling scheme of size sn≤ns_{n}\leq n consists in randomly picking points ZiZ_{i} in the dataset 𝒟n{\mathcal{D}_{n}} with inclusion probabilities πn,i\pi_{n,i}. More formally, we consider, in the context of this paper, the two following subsampling strategies: one with replacement and another without.

Subsampling with replacement

In subsampling with replacement (also called Multinomial subsampling), one draws independently sns_{n} point indices:

In,1,…,In,sn|𝒟n​∼i.i.d.​∑i=1nπn,i​δ{i},I_{n,1},\dots,I_{n,s_{n}}|{\mathcal{D}_{n}}\overset{{{}}{i.i.d.}}{\sim}\sum_{i=1}^{n}\pi_{n,i}\delta_{\{i\}},

where δ{i}\delta_{\{i\}} is the Dirac measure at ii. Since the choice is with replacement, each point ZiZ_{i} appears γn,i=∑j=1sn𝟙{In,j=i}\gamma_{n,i}=\sum_{j=1}^{s_{n}}\mathbbm{1}_{\{I_{n,j}=i\}} times in the subsampled dataset, with γn,i\gamma_{n,i} being referred to as the multiplicity or the number of occurrences of ZiZ_{i} (which may be null if ZiZ_{i} is not picked). In this situation

(γn,1,…,γn,n)|𝒟n∼Mul​(sn,𝝅n),\addcontentsline{lla}{section}{\numberline qu:gamma_{m}ultinomial}(\gamma_{n,1},\dots,\gamma_{n,n})|{\mathcal{D}_{n}}\sim\text{Mul}(s_{n},{\bm{\pi}}_{n}), (8)

(Multinomial distribution with parameters sns_{n} and 𝝅n{\bm{\pi}}_{n}) and the subsample size (counting multiplicities) is equal to sns_{n}: ∑i=1nγn,i=sn\sum_{i=1}^{n}\gamma_{n,i}=s_{n} almost surely.

Subsampling without replacement

In subsampling without replacement (or Poisson subsampling), ones draws independently for each point ZiZ_{i}:

γn,i|𝒟n​∼i.i.d.​Ber​(sn​πn,i),\addcontentsline{lla}{section}{\numberline qu:gamma_{p}oisson}\gamma_{n,i}|{\mathcal{D}_{n}}\overset{i.i.d.}{\sim}\text{Ber}(s_{n}\pi_{n,i}), (9)

(Bernoulli distribution with parameter sn​πn,is_{n}\pi_{n,i}) and decides that it should enter the subsampled dataset when the multiplicity (or inclusion indicator) verifies γn,i=1\gamma_{n,i}=1. This is possible assuming that πn,i≤sn−1\pi_{n,i}\leq s_{n}^{-1} for all n>0n>0 and i∈{1,…,n}i\in\{1,\dots,n\}, and in this situation, the subsample size is in average equal to sns_{n}: 𝔼⁡[∑i=1nγn,i|𝒟n]=sn\mathbb{E}\left[\sum_{i=1}^{n}\gamma_{n,i}|{\mathcal{D}_{n}}\right]=s_{n}.

In both situation, the subsampling schemes can be summarized as incorporating the ii-th observation ZiZ_{i}, γn,i\gamma_{n,i} times to the subsampled dataset, where γn,i∈ℕ\gamma_{n,i}\in\mathbb{N} is a random variable such that 𝔼⁡[γn,i|𝒟n]=sn​πn,i\mathbb{E}\left[\gamma_{n,i}\middle|{\mathcal{D}_{n}}\right]=s_{n}\pi_{n,i}. The subsamples are then the ZiZ_{i}s such that γn,i>0\gamma_{n,i}>0, for i∈{1,…,n}i\in\{1,\dots,n\}, and we define the subsampled and regularized risks as follows:

Lsn∗​(h)​=def​1n​∑i=1nℓ⁡(h⁡(Xi),Yi)sn​πn,i​γn,i,\displaystyle L^{*}_{s_{n}}(h)\overset{\mathrm{def}}{=}\frac{1}{n}\sum_{i=1}^{n}\frac{\ell(h(X_{i}),Y_{i})}{s_{n}\pi_{n,i}}\gamma_{n,i},\addcontentsline{lla}{section}{\numberline q:subsample_{l}oss} (10)
ℛsn∗​(h)​=def​Lsn∗​(h)+λsn∗2​‖h‖ℍ2,\displaystyle{\mathcal{R}}^{*}_{s_{n}}(h)\overset{\mathrm{def}}{=}L^{*}_{s_{n}}(h)+\frac{{\lambda_{s_{n}}^{*}}}{2}\|h\|^{2}_{\mathbb{H}},\addcontentsline{lla}{section}{\numberline q:subsample_{r}isk} (11)

where λsn∗>0{\lambda_{s_{n}}^{*}}>0 is a (possibly random) regularization parameter. Let also hsn∗{h^{*}_{s_{n}}} be the minimizer of ℛsn∗{\mathcal{R}}^{*}_{s_{n}}. By Fermat’s rule, one has:

−λsn∗​hsn∗=∇Lsn∗​(hsn∗).-{\lambda_{s_{n}}^{*}}{h^{*}_{s_{n}}}=\nabla{L}^{*}_{s_{n}}({h^{*}_{s_{n}}}). (12)

The inverse probability weighting à la Horvitz-Thompson of Equation 10 is a mean to produce unbiased estimations of the empirical and true risks (Equations 2 and 1): 𝔼⁡[Lsn∗​(h)|𝒟n]=Ln​(h)\mathbb{E}\left[{L}^{*}_{s_{n}}(h)\middle|{\mathcal{D}_{n}}\right]={L}_{n}(h) and 𝔼⁡[Lsn∗​(h)]=L⁡(h)\mathbb{E}\left[{L}^{*}_{s_{n}}(h)\right]={L}(h). This is a critical point in order to get limit results, such as consistency and asymptotic normality. However, this is not enough. First, the regularization parameter λsn∗{\lambda_{s_{n}}^{*}} has to converge to λ0{\lambda_{0}} (for consistency), and with a rate at least 1/sn1/\sqrt{s_{n}}, for asymptotic normality. This is formalized by ’ ‣ Section 3 below.

Assumption 4’.

The (random) regularization parameter sequence (λsn∗)n>0(\lambda^{*}_{s_{n}})_{n>0} verifies that λsn∗>0{\lambda_{s_{n}}^{*}}>0 almost surely for all n>0n>0 and

sn​(λsn∗−λ0)​⟶n→∞ℙ​0.\sqrt{s_{n}}({\lambda_{s_{n}}^{*}}-{\lambda_{0}})\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.

Next, the SSPs πn,i\pi_{n,i} should not converge too quickly to 00, in order for the subsampled risk (10) not to explode. This is described in Assumption 5, which states that SSPs have to be asymptotically of the order 1/n1/n.

Assumption 5.

The probability vector sequence (𝛑n)n∈ℕ({\bm{\pi}}_{n})_{n\in\mathbb{N}} satisfies

𝔼⁡[max1≤i≤n⁡{1n​πn,i}2]=O⁡(1).\mathbb{E}\left[\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{2}\right]=O(1).
Remark.

The intuition that SSPs πn,i\pi_{n,i} cannot converge to 00 faster than 1/n1/n is not surprising, and can also be read in previous works. As an example, 19 leverage an assumption in expectation similar to Assumption 5 but with averaged inverse SSPs instead of their maximum. Remark that considering such type of assumption with our sketch of proof would require to go up to the order 8.

Similarly, 46 require max1≤i≤n⁡{n​πn,i}−1=Oℙ​(1)\max_{1\leq i\leq n}\left\{n\pi_{n,i}\right\}^{-1}=O_{\mathbb{P}}(1), which can be obtained from Assumption 5 by Markov’s inequality: for all M>0M>0,

ℙ⁡(max1≤i≤n⁡{1n​πn,i}>M)≤1M2​𝔼​[max1≤i≤n⁡{1n​πn,i}2]=1M2​O​(1),\mathbb{P}\left(\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}>M\right)\leq\frac{1}{M^{2}}\mathbb{E}\left[\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{2}\right]=\frac{1}{M^{2}}O(1),

hence, max1≤i≤n⁡{n​πn,i}−1=Oℙ​(1)\max_{1\leq i\leq n}\left\{n\pi_{n,i}\right\}^{-1}=O_{\mathbb{P}}(1) and more generally max1≤i≤n⁡{n​πn,i}−p=Oℙ​(1)\max_{1\leq i\leq n}\left\{n\pi_{n,i}\right\}^{-p}=O_{\mathbb{P}}(1) for all positive integer pp.

The next result states SRM consistency (which can actually be obtained without a rate of convergence for λsn∗{\lambda_{s_{n}}^{*}}) in both subsampling schemes, as n→∞n\to\infty and sn→∞s_{n}\to\infty.

Theorem 3.1 (Consistency of hsn∗{h^{*}_{s_{n}}}).

Under Assumptions 1, 2, 3 and 5, and λsn∗​⟶n→∞ℙ​λ0{\lambda_{s_{n}}^{*}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}{\lambda_{0}} (or ’ ‣ Section 3), one has

‖hsn∗−h0‖ℍ​⟶n→∞ℙ​0,\|{h^{*}_{s_{n}}}-{h_{0}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0,

whether hsn∗{h^{*}_{s_{n}}} is the Multinomial (Equation 8) or the Poisson (Equation 9) subsampling estimator.

We will show in the next theorems that the SRM hsn∗{h^{*}_{s_{n}}} is asymptotically normal to the target h0{h_{0}}. Obviously, it is expected that the rate of convergence of hsn∗{h^{*}_{s_{n}}} as well as its asymptotic covariance operator are different from that of the ERM h^n{\hat{h}_{n}}. In order to reveal the alteration of the asymptotic covariance operator, we consider inclusion probabilities, which depend on the observation of interest as πn,i∝ψ⁡(Zi)\pi_{n,i}\propto\psi(Z_{i}), where ψ\psi is a positive absolute interest (or importance) function. More formally, let ψ:𝒵→ℝ+∗\psi:\mathcal{Z}\rightarrow\mathbb{R}^{*}_{+} be a deterministic map independent from nn. Then, for all n>0n>0, the SSP vector 𝝅n{\bm{\pi}}_{n} reads

πn,i=ψ⁡(Zi)∑j=1nψ⁡(Zj),∀i∈{1,…,n}.\addcontentsline{lla}{section}{\numberline q:ssp}\pi_{n,i}=\frac{\psi(Z_{i})}{\sum_{j=1}^{n}\psi(Z_{j})},\qquad\forall i\in\{1,\dots,n\}. (13)

If this writing seems restrictive (since, except for the normalization, each SSP πn,i\pi_{n,i} depends only on ZiZ_{i}), we shall remark that it is consistent with optimal SSPs found by 46 for parametric models, without considering beforehand a particular form for the vector 𝝅n{\bm{\pi}}_{n}. It is however required in order to understand how the asymptotic covariance operator is affected by the subsampling procedure. Now, Assumption 6 provides a condition on ψ\psi for the asymptotic covariance operator not to explode. Equipped with it, Theorems 3.2 and 3.3 state asymptotic normality of the SRM hsn∗{h^{*}_{s_{n}}}.

Assumption 6.

The interest function ψ\psi is such that

𝔼⁡[ψ⁡(Z)]<∞and𝔼⁡[ψ−1​(Z)​ℓ′​(h0​(X),Y)2​k​(X,X)]<∞.\mathbb{E}\left[\psi(Z)\right]<\infty\quad\text{and}\quad\mathbb{E}\left[\psi^{-1}(Z)\ell^{\prime}({h_{0}}(X),Y)^{2}k(X,X)\right]<\infty.
Theorem 3.2 (Asymptotic normality of Multinomial subsampling (Equation 8)).

Under Assumptions 1, 2, 3, ’ ‣ 3, 5 and 6, if one furthermore assumes that sn/n​⟶n→∞​c≥0s_{n}/n\underset{n\rightarrow\infty}{\longrightarrow}c\geq 0, then

sn​∇2ℛ​(h0)​(hsn∗−h0)​⟶n→∞d​𝒢​(0,ΣM∗​(ψ)+c​Σ),\addcontentsline{lla}{section}{\numberline q:hsn_{a}symp_{n}ormality_{R}}\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma^{*}_{\mathrm{M}}(\psi)+c\Sigma), (14)

where

ΣM∗​(ψ)​=def​𝔼​[𝔼⁡[ψ⁡(Z)]ψ⁡(Z)​ℓ′​(h0​(X),Y)2​KX⊗KX]−∇L​(h0)⊗∇L​(h0).\Sigma^{*}_{\mathrm{M}}(\psi)\overset{\mathrm{def}}{=}\mathbb{E}\left[\frac{\mathbb{E}\left[\psi(Z)\right]}{\psi(Z)}\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-\nabla{L}({h_{0}})\otimes\nabla{L}({h_{0}}).
Theorem 3.3 (Asymptotic normality of Poisson subsampling (Equation 9)).

Under Assumptions 1, 2, 3, ’ ‣ 3, 5 and 6, if one furthermore assumes that sn/n​⟶n→∞​c∈[0,1]s_{n}/n\underset{n\rightarrow\infty}{\longrightarrow}c\in[0,1], πn,i≤1/sn\pi_{n,i}\leq 1/s_{n} for all n>0n>0 and i∈{1,…,n}i\in\{1,\dots,n\}, then

sn​∇2ℛ​(h0)​(hsn∗−h0)​⟶n→∞d​𝒢​(0,ΣP,c∗​(ψ)+c​Σ),\addcontentsline{lla}{section}{\numberline q:poisson_{h}sn_{a}symp_{n}ormality}\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma^{*}_{\mathrm{P},c}(\psi)+c\Sigma), (15)

where

ΣP,c∗​(ψ)​=def​𝔼​[𝔼⁡[ψ⁡(Z)]ψ⁡(Z)​ℓ′​(h0​(X),Y)2​KX⊗KX]−c​𝔼​[ℓ′​(h0​(X),Y)2​KX⊗KX].\Sigma^{*}_{\mathrm{P},c}(\psi)\overset{\mathrm{def}}{=}\mathbb{E}\left[\frac{\mathbb{E}\left[\psi(Z)\right]}{\psi(Z)}\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-c\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right].
Remark.

If c>0c>0, Equations 14 and 15 can be written:

n​∇2ℛ​(h0)​(hsn∗−h0)​⟶n→∞d​𝒢​(0,c−1​ΣM∗​(ψ)+Σ)(Theorem 3.2)\displaystyle\sqrt{n}\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,c^{-1}\Sigma^{*}_{\mathrm{M}}(\psi)+\Sigma)\quad\text{(\lx@cref{creftypecap\lx@tilde refnum}{thm:srm_normality_R})}
n​∇2ℛ​(h0)​(hsn∗−h0)​⟶n→∞d​𝒢​(0,c−1​ΣP,c∗​(ψ)+Σ)(Theorem 3.3),\displaystyle\sqrt{n}\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,c^{-1}\Sigma^{*}_{\mathrm{P},c}(\psi)+\Sigma)\quad\text{(\lx@cref{creftypecap\lx@tilde refnum}{thm:srm_normality_P})},

showing that the SRM hsn∗{h^{*}_{s_{n}}} has the same 1/n1/\sqrt{n}-rate of convergence to h0{h_{0}} than the ERM h^n{\hat{h}_{n}}, but increased covariance operators. In this situation, as expected, the less data is used (c≪1c\ll 1), the greater the covariance operator.

As a byproduct, Theorems 3.2 and 3.3 also give the asymptotic normality of the SRM, denoted hsn∗U{h_{s_{n}}^{*\mathrm{U}}} below, when subsampling with uniform SSPs: for all n>0n>0 and all i∈{1,…,n}i\in\{1,\dots,n\}, πn,i=1/n\pi_{n,i}=1/n. Let us remark that, in this case, Assumptions 5 and 6 are directly granted.

Corollary 3.4 (Asymptotic normality of uniform Multinomial subsampling (Equation 8)).

Under Assumptions 1, 2, 3 and ’ ‣ 3, if one furthermore assumes that sn/n​⟶n→∞​c≥0s_{n}/n\underset{n\rightarrow\infty}{\longrightarrow}c\geq 0, then the uniform SRM hsn∗U{h_{s_{n}}^{*\mathrm{U}}} verifies:

sn​∇2ℛ​(h0)​(hsn∗U−h0)​⟶n→∞d​𝒢​(0,(1+c)​Σ).\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h_{s_{n}}^{*\mathrm{U}}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,(1+c)\Sigma).
Corollary 3.5 (Asymptotic normality of uniform Poisson subsampling (Equation 9)).

Under Assumptions 1, 2, 3 and ’ ‣ 3, if one furthermore assumes that sn/n​⟶n→∞​c∈[0,1]s_{n}/n\underset{n\rightarrow\infty}{\longrightarrow}c\in[0,1], then the uniform SRM hsn∗U{h_{s_{n}}^{*\mathrm{U}}} verifies:

sn​∇2ℛ​(h0)​(hsn∗U−h0)​⟶n→∞d​𝒢​(0,ΣP,cU),\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h_{s_{n}}^{*\mathrm{U}}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma^{\mathrm{U}}_{\mathrm{P},c}),

where ΣP,cU=def𝔼[ℓ′(h0(X),Y)2KX⊗KX]−c∇L(h0)⊗∇L(h0)\Sigma^{\mathrm{U}}_{\mathrm{P},c}\overset{\mathrm{def}}{=}\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-c\nabla{L}({h_{0}})\otimes\nabla{L}({h_{0}}).

Remark.

For Poisson subsampling, choosing c=1c=1 implies that, asymptotically, all observations are part of the subsample. In this case, hsn∗{h^{*}_{s_{n}}} has convergence rate 1/n1/\sqrt{n} (see the preceding remark) and asymptotic covariance operator ΣP,1U=Σ\Sigma^{\mathrm{U}}_{\mathrm{P},1}=\Sigma. In other words, the SRM has the same performance as the ERM.

4 Variance reduction

Since the role of subsampling is to reduce the dataset size by randomly picking points, it is of interest to choose these few points in order to maximize the SRM estimator precision. Once the limit ratio c=limn→∞sn/nc=\lim_{n\to\infty}s_{n}/n has been chosen (see Theorems 3.2 and 3.3), it is about minimizing the asymptotic covariance operator. The most common way to do it is to reduce the covariance information to a scalar, and to minimize the latter. Several manners of reducing the covariance information exist and are well documented in the literature of optimal design (see for instance (23)). In this study, we follow the work by 46 and focus on L-optimality, which consists in computing the trace of the covariance, preconditioned by a well-chosen operator (here (∇2R​(h0))−1(\nabla^{2}R(h_{0}))^{-1}, which exists according to (16, Lemma A.5)). This choice is consistent with the dependence of the covariance operator to ψ\psi and is computationally advantageous.

In our infinite dimensional framework based on RKHSs, the trace of a self-adjoint bounded linear map does not differ much from the finite dimensional case. For such an operator Λ:ℍ→ℍ\Lambda:\mathbb{H}\to\mathbb{H}, it can be defined as tr⁡(Λ)​=def​∑j=1∞⟨Λ​ej,ej⟩ℍ\Tr(\Lambda)\overset{\mathrm{def}}{=}\sum_{j=1}^{\infty}\langle\Lambda e_{j},e_{j}\rangle_{\mathbb{H}}, and, in the particular case where Λ\Lambda is the outer product of two vectors, i.e. Λ=f⊗h\Lambda=f\otimes h (with f,h∈ℍf,h\in\mathbb{H}), then tr⁡(Λ)=⟨f,h⟩ℍ\Tr(\Lambda)=\langle f,h\rangle_{\mathbb{H}} (see (21) for more details).

Going back to Theorems 3.3 and 3.2, let Σ∗​(ψ)\Sigma^{*}(\psi) be either ΣM∗​(ψ)\Sigma^{*}_{\mathrm{M}}(\psi) or ΣP,c∗​(ψ)\Sigma^{*}_{\mathrm{P},c}(\psi), depending on the subsampling strategy. In both cases, L-optimality boils down to minimizing

tr⁡(Σ∗​(ψ))=𝔼⁡[𝔼⁡[ψ⁡(Z)]ψ⁡(Z)​ℓ′​(h0​(X),Y)2​k​(X,X)]+C,\Tr(\Sigma^{*}(\psi))=\mathbb{E}\left[\frac{\mathbb{E}\left[\psi(Z)\right]}{\psi(Z)}\ell^{\prime}({h_{0}}(X),Y)^{2}k(X,X)\right]+C,

with respect to ψ\psi, where CC is a constant term. Proposition 4.1 gives a closed-form expression of such an L-optimal absolute interest map ψ\psi.

Remark.

Since the two subsampling strategies considered here lead to the same convergence rate of the estimator hsn∗{h^{*}_{s_{n}}} (depending on the value of the limit ratio c=limn→∞sn/nc=\lim_{n\to\infty}s_{n}/n), they can be compared to each other based on L-optimality. For this purpose, consider a fixed absolute interest function ψ\psi and let

Δ\displaystyle\Delta =def​tr⁡(ΣM∗​(ψ))−tr⁡(ΣP,c∗​(ψ))=c​𝔼​[ℓ′​(h0​(X),Y)2​k​(X,X)]−‖∇L​(h0)‖ℍ2.\displaystyle\overset{\mathrm{def}}{=}\Tr(\Sigma^{*}_{\mathrm{M}}(\psi))-\Tr(\Sigma^{*}_{\mathrm{P},c}(\psi))=c\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)^{2}k(X,X)\right]-\|\nabla L({h_{0}})\|_{\mathbb{H}}^{2}.

Whenever c=0c=0 (i.e. sn=o⁡(n)s_{n}=o(n)), one has Δ<0\Delta<0, hence Multinomial subsampling surpasses Poisson subsampling. On the contrary, when c=1c=1, one has Δ=tr⁡(Σ)>0\Delta=\Tr(\Sigma)>0, thus Poisson subsampling is superior to Multinomial subsampling.

It results that the choice between the two strategies depends on the limit ratio cc, which is a quantity defined by the practitioner: if cc is small, Multinomial subsampling is preferable to Poisson subsampling, while the converse holds when cc is close to 11. Let us remark that this conclusion is slightly different from the parametric case studied in (46), which concludes that both subsampling schemes have the same asymptotically estimation efficiency when c=0c=0. This is due to the presence of a quadratic regularization in our setting, which does not exist in the parametric framework.

Proposition 4.1 (L-optimal map ψ\psi).

The minimization problem

minimizeψ:𝒵→ℝ+∗tr(Σ∗(ψ)),\addcontentsline{lla}{section}{\numberline pb:l-optimality}\operatorname{minimize}_{\psi:\mathcal{Z}\rightarrow\mathbb{R}^{*}_{+}}\ \Tr\left(\Sigma^{*}(\psi)\right), (𝒫ψ\mathcal{P}_{\psi})

has a unique solution (up to a multiplicative factor and an L2L^{2} equivalence w.r.t. the law of ZZ), being ψ⋆\psi^{\star}, defined for all 𝐳=(𝐱,y)∈𝒵\bm{z}=(\bm{x},y)\in\mathcal{Z}, by

ψ⋆​(𝒛)​=def​|ℓ′​(h0​(𝒙),y)|​k⁡(𝒙,𝒙).\addcontentsline{lla}{section}{\numberline q:optimal_{p}si_{R}}\psi^{\star}(\bm{z})\overset{\mathrm{def}}{=}|\ell^{\prime}({h_{0}}(\bm{x}),y)|\sqrt{k(\bm{x},\bm{x})}. (16)

If it is clear that, given our technical Assumptions 1, 2 and 3, the L-optimal absolute interest function ψ⋆\psi^{\star} verifies Assumption 6, it is not true neither for Assumption 5, nor for the basic requirement of Poisson subsampling (i.e. that all SSPs are bounded by 1/sn1/s_{n}). This is discussed in the two forthcoming remarks.

Remark.

As one may notice, Proposition 4.1 does not take into account that ψ\psi has to verify Assumption 5 in order to be used in application of Theorems 3.2 and 3.3. Indeed, incorporating Assumption 5 as a constraint into Problem ( P ψ ) would lead to an intractable problem. It results that ψ⋆\psi^{\star} may not satisfy Assumption 5. However, in practice, the optimal SSPs computed thanks to ψ⋆\psi^{\star} are then adjusted such that Assumption 5 is granted (see Section 5).

Remark.

Poisson subsampling (Equation 9) also requires that, for all n>0n>0,

for all ​i∈{1,…,n},ψ⁡(Zi)∑j=1nψ⁡(Zj)≤1sn,\addcontentsline{lla}{section}{\numberline qu:Poisson_{c}ontraints}\text{for all }i\in\{1,\dots,n\},\quad\frac{\psi(Z_{i})}{\sum_{j=1}^{n}\psi(Z_{j})}\leq\frac{1}{s_{n}}, (17)

which, again, may not be true for ψ⋆\psi^{\star}. If one would like to consider these inequalities as part of Problem ( P ψ ), it would mean handling an infinite amount of constraints (inequalities have to hold true for all n>0n>0). Moreover, even for a fixed value of nn (keeping in mind the practical use of the proposed procedure), the latter constraints would lead to inconsistent (even lack of) solutions, since a candidate ψ\psi may always be smoothly altered so as to satisfy pointwise conditions. As a result, Conditions (17) are not considered when determining an optimal absolute interest function ψ⋆\psi^{\star}, yet, as explained in Section 5, optimal SSPs computed with ψ⋆\psi^{\star} are then post-processed in order to be valid inclusion probabilities for Poisson subsampling.

Let us remark that, in the parametric case, 46 follow the same path but minimizing (for a fixed value of nn) the trace of an empirical version of Σ∗​(ψ)\Sigma^{*}(\psi) subject to Conditions (17). They then exhibit optimal SSPs proportional to ψ⋆∧H\psi^{\star}\wedge H, where HH is a data-dependent threshold. This workaround does not fit our framework, since the absolute interest map ψ\psi is thought deterministic and independent from nn.

Let us now investigate some examples of supervised learning settings, which illustrate the shape of the L-optimal absolute interest function ψ⋆\psi^{\star}, revealed in Proposition 4.1. For this purpose and for simplicity, we consider a radial basis function kernel kk, implying that for all 𝒙∈𝒳\bm{x}\in\mathcal{X}, k⁡(𝒙,𝒙)k(\bm{x},\bm{x}) is constant.

Example 1 (Logistic regression).

In the classification setting of penalized kernel logistic regression, one has, for y∈{−1,1}y\in\{-1,1\} and y^∈ℝ\hat{y}\in\mathbb{R}:

ℓ⁡(y^,y)=log⁡(1+exp⁡(−y​y^))andℓ′​(y^,y)=−y​σ​(−y​y^),\ell(\hat{y},y)=\log(1+\exp(-y\hat{y}))\quad\text{and}\quad\ell^{\prime}(\hat{y},y)=-y\sigma(-y\hat{y}),

where σ:t↦1/(1+e−t)\sigma:t\mapsto 1/(1+e^{-t}) is the sigmoid function. The optimal SSPs are then proportional to

|ℓ′​(h0​(𝒙),y)|=σ⁡(−y​h0​(𝒙)),(𝒙,y)∈𝒳×𝒴.|\ell^{\prime}({h_{0}}(\bm{x}),y)|=\sigma(-y{h_{0}}(\bm{x})),\quad(\bm{x},y)\in\mathcal{X}\times\mathcal{Y}.

Hence a datapoint Zi=(Xi,Yi)Z_{i}=(X_{i},Y_{i}) has a high probability of being picked if Yi​h0​(Xi)≪0Y_{i}{h_{0}}(X_{i})\ll 0, i.e. if XiX_{i} is wrongly classified by the true function h0{h_{0}} (h0​(Xi){h_{0}}(X_{i}) and YiY_{i} have different signs) and with a high confidence (|h0​(Xi)||{h_{0}}(X_{i})| is large).

Example 2 (LpL^{p} regression).

In the LpL^{p} (with p≥1p\geq 1) kernel ridge regression setting, one has, for y,y^∈ℝy,\hat{y}\in\mathbb{R}:

ℓ⁡(y^,y)=1p​|y^−y|pandℓ′​(y^,y)=sign⁡(y^−y)​|y^−y|p−1.\ell(\hat{y},y)=\frac{1}{p}|\hat{y}-y|^{p}\quad\text{and}\quad\ell^{\prime}(\hat{y},y)=\sign(\hat{y}-y)|\hat{y}-y|^{p-1}.

The optimal SSPs are thus proportional to

|ℓ′​(h0​(𝒙),y)|=|h0​(𝒙)−y|p−1,(𝒙,y)∈𝒳×𝒴.|\ell^{\prime}({h_{0}}(\bm{x}),y)|=|{h_{0}}(\bm{x})-y|^{p-1},\quad(\bm{x},y)\in\mathcal{X}\times\mathcal{Y}.

Hence a datapoint Zi=(Xi,Yi)Z_{i}=(X_{i},Y_{i}) has a high probability of being picked if YiY_{i} is poorly predicted by the true function h0{h_{0}} (|Yi−h0​(Xi)|≫0|Y_{i}-{h_{0}}(X_{i})|\gg 0). This is for instance the case for noisy observations.

In addition, let us remark that for high values of pp, the SSPs (through |ℓ′​(h0​(𝐱),y)||\ell^{\prime}({h_{0}}(\bm{x}),y)|) are squashed to 00 when h0​(𝐱)≈y{h_{0}}(\bm{x})\approx y, thus imitating an ϵ\epsilon-insensitive loss (37), with the nice property of being infinitely differentiable, and producing SSPs of different magnitudes.

Example 3 (Quartic-quadratic Huber).

As stated above, the LpL^{p} loss with a high value of pp produces SSPs of different magnitudes, attributing near zero inclusion probabilities to well predicted datapoints. On the converse, it assigns high SSPs to datapoints, the outputs yy of which are far from the predictions h0​(𝐱){h_{0}}(\bm{x}). As a result, and as it may be expected by using an LpL^{p} loss, the SSPs are not robust to outliers.

To keep the benefit of an almost ϵ\epsilon-insensitive loss (i.e. SSPs with different magnitudes) while being more robust to outliers, one may defined a “Huberized” L2L^{2} loss (see (20, Section 10.6)), which is quartic around 00 and quadratic elsewhere. For this purpose, let ϵ>0\epsilon>0 be a given threshold, and consider

ℓϵ​(y^,y)​=def​{14​(y^−y)4if​|y^−y|≤ϵ,32​ϵ2​(y^−y)2−2​ϵ3​|y^−y|+34​ϵ4otherwise,\ell_{\epsilon}(\hat{y},y)\overset{\mathrm{def}}{=}\begin{cases}\frac{1}{4}(\hat{y}-y)^{4}&\text{if}\ |\hat{y}-y|\leq\epsilon,\\ \frac{3}{2}\epsilon^{2}(\hat{y}-y)^{2}-2\epsilon^{3}|\hat{y}-y|+\frac{3}{4}\epsilon^{4}&\text{otherwise},\end{cases}

which is twice-differentiable, with

ℓϵ′​(y^,y)={(y^−y)3if​|y^−y|≤ϵ,3​ϵ2​(y^−y)−2​ϵ3​sign⁡(y^−y)otherwise.\ell^{\prime}_{\epsilon}(\hat{y},y)=\begin{cases}(\hat{y}-y)^{3}&\text{if}\ |\hat{y}-y|\leq\epsilon,\\ 3\epsilon^{2}(\hat{y}-y)-2\epsilon^{3}\sign(\hat{y}-y)&\text{otherwise}.\end{cases}

In the same manner as for LpL^{p} regression, the optimal SSPs are as large as the output yy is wrongly predicted by h0​(𝐱){h_{0}}(\bm{x}), nevertherless, there is a regime shift whether the prediction is at least (or at most) ϵ\epsilon far away from the output yy. This leads to SSPs of different magnitudes, which are more robust to outliers than those obtained with an LpL^{p} loss.

5 Piloted subsampling estimator

We address in this section the practical side of subsampling with the L-optimal absolute interest function ψ⋆\psi^{\star}, exhibited in Proposition 4.1. First, as it can be noticed, ψ⋆\psi^{\star} makes use of the unknown regularized risk minimizer h0{h_{0}}. Nevertheless, the latter can be estimated by plug-in as soon as we are provided with prior information on h0{h_{0}}, which is assumed to be true in the form of a naive estimator h^kn{\hat{h}_{k_{n}}} of h0{h_{0}} (called a pilot estimator, and computed with knk_{n} points). Based on it, L-optimal SSPs can be estimated as π~n,i∝|ℓ′​(h^kn​(Xi),Yi)|​k⁡(Xi,Xi)\tilde{\pi}_{n,i}\propto|\ell^{\prime}({\hat{h}_{k_{n}}}(X_{i}),Y_{i})|\sqrt{k(X_{i},X_{i})} for all i∈{1,…,n}i\in\{1,\dots,n\}. Second, as explained in the previous section, there is no guarantee that the map ψ⋆\psi^{\star} leads to SSPs which verify Assumption 5. For this reason, it is proposed to smooth estimated SSPs as:

π~n,iα=(1−α)​π~n,i+αn,\tilde{\pi}_{n,i}^{\alpha}=(1-\alpha)\tilde{\pi}_{n,i}+\frac{\alpha}{n},

for all i∈{1,…,n}i\in\{1,\dots,n\}, where α∈(0,1]\alpha\in(0,1] is a hyperparameter. As a last point, since SSPs should be less than 1/sn1/s_{n} for Poisson subsampling, one may apply a post hoc truncation, such as 𝝅~nα∧sn−1\tilde{\bm{\pi}}_{n}^{\alpha}\wedge s_{n}^{-1}. Everything together provides data driven SSPs satisfying all requirements and usable to build an SRM hsn∗α{h_{s_{n}}^{*\alpha}}, called an α\alpha-piloted subsampling estimator.

Theorems 5.1 and 5.2 below state that the latter estimator is consistent to h0{h_{0}} and asymptotically normal. In particular, it exhibits a covariance operator (which is well-defined and finite by the very definition of ψ⋆\psi^{\star} and Assumptions 1, 2 and 3), which, compared to that of Theorems 3.2 and 3.3, is slightly impacted by smoothing the SSPs (tuned by the hyperparameter α\alpha) but not by the use of a plug-in estimation of ψ⋆\psi^{\star}.

Theorem 5.1 (Asymptotic normality of α\alpha-piloted Multinomial subsampling (Equation 8)).

Under Assumptions 1, 2, 3 and ’ ‣ 3, let h^kn{\hat{h}_{k_{n}}} be a consistent estimator of h0{h_{0}}, α∈(0,1]\alpha\in(0,1] and define the probability vectors 𝛑~n\tilde{\bm{\pi}}_{n} and 𝛑~nα\tilde{\bm{\pi}}_{n}^{\alpha} such that

π~n,i=|ℓ′​(h^kn​(Xi),Yi)|​k⁡(Xi,Xi)∑j=1n|ℓ′​(h^kn​(Xj),Yj)|​k⁡(Xj,Xj)andπ~n,iα=(1−α)​π~n,i+αn,\tilde{\pi}_{n,i}=\frac{|\ell^{\prime}({\hat{h}_{k_{n}}}(X_{i}),Y_{i})|\sqrt{k(X_{i},X_{i})}}{\sum_{j=1}^{n}|\ell^{\prime}({\hat{h}_{k_{n}}}(X_{j}),Y_{j})|\sqrt{k(X_{j},X_{j})}}\quad\text{and}\quad\tilde{\pi}_{n,i}^{\alpha}=(1-\alpha)\tilde{\pi}_{n,i}+\frac{\alpha}{n},

for all n>0n>0 and i∈{1,…,n}i\in\{1,\dots,n\}. Let hsn∗α{h_{s_{n}}^{*\alpha}} be the SRM of the subsampled regularized risk with SSP vector 𝛑~nα\tilde{\bm{\pi}}_{n}^{\alpha}. If one furthermore assumes that sn/n​⟶n→∞​c≥0s_{n}/n\underset{n\rightarrow\infty}{\longrightarrow}c\geq 0, then

sn​∇2ℛ​(h0)​(hsn∗α−h0)​⟶n→∞d​𝒢​(0,ΣM∗​(α)+c​Σ),\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h_{s_{n}}^{*\alpha}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma^{*}_{\mathrm{M}}(\alpha)+c\Sigma),

where

ΣM∗​(α)​=def​𝔼​[𝔼​ψ⋆​(Z)Ψα⋆​(Z)​ℓ′​(h0​(X),Y)2​KX⊗KX]−∇L​(h0)⊗∇L​(h0),\Sigma^{*}_{\mathrm{M}}(\alpha)\overset{\mathrm{def}}{=}\mathbb{E}\left[\frac{\mathbb{E}{\psi^{\star}(Z)}}{\Psi_{\alpha}^{\star}(Z)}\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-\nabla{L}({h_{0}})\otimes\nabla{L}({h_{0}}),

with Ψα⋆​(Z)​=def​(1−α)​ψ⋆​(Z)+α​𝔼​ψ⋆​(Z)\Psi^{\star}_{\alpha}(Z)\overset{\mathrm{def}}{=}(1-\alpha)\psi^{\star}(Z)+\alpha\mathbb{E}\psi^{\star}(Z).

Theorem 5.2 (Asymptotic normality of α\alpha-piloted Poisson subsampling (Equation 9)).

Under Assumptions 1, 2, 3 and ’ ‣ 3, let h^kn{\hat{h}_{k_{n}}} be a consistent estimator of h0{h_{0}}, α∈(0,1]\alpha\in(0,1] and define the probability vectors 𝛑~n\tilde{\bm{\pi}}_{n} and 𝛑~nα\tilde{\bm{\pi}}_{n}^{\alpha} such that

π~n,i=|ℓ′​(h^kn​(Xi),Yi)|​k⁡(Xi,Xi)∑j=1n|ℓ′​(h^kn​(Xj),Yj)|​k⁡(Xj,Xj)andπ~n,iα=(1−α)​π~n,i+αn,\tilde{\pi}_{n,i}=\frac{|\ell^{\prime}({\hat{h}_{k_{n}}}(X_{i}),Y_{i})|\sqrt{k(X_{i},X_{i})}}{\sum_{j=1}^{n}|\ell^{\prime}({\hat{h}_{k_{n}}}(X_{j}),Y_{j})|\sqrt{k(X_{j},X_{j})}}\quad\text{and}\quad\tilde{\pi}_{n,i}^{\alpha}=(1-\alpha)\tilde{\pi}_{n,i}+\frac{\alpha}{n},

for all n>0n>0 and i∈{1,…,n}i\in\{1,\dots,n\}. Let hsn∗α{h_{s_{n}}^{*\alpha}} be the SRM of the subsampled regularized risk with SSP vector 𝛑~nα∧sn−1\tilde{\bm{\pi}}_{n}^{\alpha}\wedge s_{n}^{-1}. If one furthermore assumes that sn/n​⟶n→∞​c∈[0,1]s_{n}/n\underset{n\rightarrow\infty}{\longrightarrow}c\in[0,1], then

sn​∇2ℛ​(h0)​(hsn∗α−h0)​⟶n→∞d​𝒢​(0,ΣP,c∗​(α)+c​Σ),\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h_{s_{n}}^{*\alpha}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma^{*}_{\mathrm{P},c}(\alpha)+c\Sigma),

where

ΣP,c∗​(α)​=def​𝔼​[𝔼⁡[ψ⋆​(Z)]​ℓ′​(h0​(X),Y)2Ψα⋆​(Z)∧(c−1​𝔼​[ψ⋆​(Z)])​KX⊗KX]−c​𝔼​[ℓ′​(h0,(X),Y)2​KX⊗KX].\Sigma^{*}_{\mathrm{P},c}(\alpha)\overset{\mathrm{def}}{=}\mathbb{E}\left[\frac{\mathbb{E}\left[\psi^{\star}(Z)\right]\ell^{\prime}({h_{0}}(X),Y)^{2}}{\Psi^{\star}_{\alpha}(Z)\wedge(c^{-1}\mathbb{E}\left[\psi^{\star}(Z)\right])}K_{X}\otimes K_{X}\right]-c\mathbb{E}\left[\ell^{\prime}({h_{0}},(X),Y)^{2}K_{X}\otimes K_{X}\right].

A particularity of α\alpha-piloted Poisson subsampling (Theorem 5.2) is the use of a post hoc truncation of SSPs: 𝝅~nα∧sn−1\tilde{\bm{\pi}}_{n}^{\alpha}\wedge s_{n}^{-1}, in order to get valid Bernoulli distribution parameters. It has two direct consequences. First, the subsampled dataset size is in expectation less than or equal to sns_{n} rather than equal to sns_{n}. Second, a thresholdind based on c−1​𝔼​[ψ⋆​(Z)]c^{-1}\mathbb{E}\left[\psi^{\star}(Z)\right] appears in the denominator of the asymptotic covariance operator ΣP,c∗\Sigma_{\mathrm{P},c}^{*} of hsn∗α{h_{s_{n}}^{*\alpha}}.

In practice, the pilot estimator h^kn{\hat{h}_{k_{n}}} can be easily obtained by picking uniformly a small number of datapoints and by minimizing an empirical regularized risk. In this situation, Theorem 3.1 ensures consistency of h^kn{\hat{h}_{k_{n}}}. The proposed workable procedure for computing an α\alpha-piloted subsampling estimator is summarized Algorithm 1.

Require sn≤ns_{n}\leq n (desired subsampled dataset size), kn≪snk_{n}\ll s_{n} (pilot dataset size), α∈(0,1]\alpha\in(0,1] (smoothing hyperparameter).

  1. 1.

    Consider a random permutation σ\sigma on {1,…,n}\{1,\dots,n\} and build a pilot estimator

    h^kn∈arg​minh∈ℍ⁡{1kn​∑i=1knℓ⁡(h⁡(Xσ⁡(i)),Yσ⁡(i))+λkn∗2​‖h‖ℍ2}.\hat{h}_{k_{n}}\in\argmin_{h\in\mathbb{H}}\left\{\frac{1}{k_{n}}\sum_{i=1}^{k_{n}}\ell(h(X_{\sigma(i)}),Y_{\sigma(i)})+\frac{\lambda_{k_{n}}^{*}}{2}\|h\|^{2}_{\mathbb{H}}\right\}.
  2. 2.

    Estimate optimal SSPs by plug-in:

    π~n,i=|ℓ′​(h^kn​(Xi),Yi)|​k⁡(Xi,Xi)∑j=1n|ℓ′​(h^kn​(Xj),Yj)|​k⁡(Xj,Xj),\tilde{\pi}_{n,i}=\frac{|\ell^{\prime}({\hat{h}_{k_{n}}}(X_{i}),Y_{i})|\sqrt{k(X_{i},X_{i})}}{\sum_{j=1}^{n}|\ell^{\prime}({\hat{h}_{k_{n}}}(X_{j}),Y_{j})|\sqrt{k(X_{j},X_{j})}},

    for all i∈{1,…,n}i\in\{1,\dots,n\}.

  3. 3.

    Smooth the estimated SSPs:

    π~n,iα=(1−α)​π~n,i+αn,\tilde{\pi}_{n,i}^{\alpha}=(1-\alpha)\tilde{\pi}_{n,i}+\frac{\alpha}{n},

    for all i∈{1,…,n}i\in\{1,\dots,n\}.

  4. 4.

    Subsample datapoints either with replacement (with SSP vector 𝝅~nα\tilde{\bm{\pi}}_{n}^{\alpha}) or without replacement (with SSP vector 𝝅~nα∧sn−1\tilde{\bm{\pi}}_{n}^{\alpha}\wedge s_{n}^{-1}) and get multiplicities γn,iα\gamma_{n,i}^{\alpha}.

  5. 5.

    Build the α\alpha-piloted SRM:

    hsn∗α∈arg​minh∈ℍ⁡{1n​∑i=1nℓ⁡(h⁡(Xi),Yi)sn​π~n,iα​γn,iα+λsn∗2​‖h‖ℍ2}.{h_{s_{n}}^{*\alpha}}\in\argmin_{h\in\mathbb{H}}\left\{\frac{1}{n}\sum_{i=1}^{n}\frac{\ell(h(X_{i}),Y_{i})}{s_{n}\tilde{\pi}_{n,i}^{\alpha}}\gamma_{n,i}^{\alpha}+\frac{{\lambda_{s_{n}}^{*}}}{2}\|h\|^{2}_{\mathbb{H}}\right\}.
Algorithm 1 α\alpha-piloted subsampling estimator

6 Numerical experiments

6.1 Setting

In this section, we empirically assess the performance of the proposed α\alpha-piloted subsampling method (Algorithm 1) compared to a naive approach (uniform subsampling) and three state-of-the-art kernel approximation and dataset reduction techniques: the Nyström method (48; 10), Random Fourier Features (31) and kernel sketching (50; 12).22 2 The Python source code for reproducing the numerical experiments is provided at https://gitlab.com/Yaloude/rkhs-subsampling. By performance, it is meant first the generalization error of the methods (Figure 3), second their computational effort, that is the curve mapping the generalization error to the training CPU time (Figures 4, 5 and 6). Let us now describe the competitive methods.

α\alpha-piloted subsampling (SRM)

This is the method proposed in Algorithm 1 with kn=sn/3k_{n}=s_{n}/3 and α=0.2\alpha=0.2. The subsampling budget is here bn=kn+snb_{n}=k_{n}+s_{n}, where a quarter is used for computing the pilot estimator h^kn{\hat{h}_{k_{n}}} and the remaining for the final subsampling estimator hsn∗α{h_{s_{n}}^{*\alpha}}.

Uniform subsampling

This corresponds to Multinomial or Poisson subsampling with uniform SSPs: 𝝅nU=(1/n,…,1/n){\bm{\pi}}_{n}^{\mathrm{U}}=(1/n,\dots,1/n) (see Corollaries 3.4 and 3.5), and constitutes a naive, dataset unrelated and problem agnostic subsampling strategy used as a baseline. The subsampling budget is here bn=snb_{n}=s_{n}.

Nyström

The Nyström method is a kernel approximation technique, where the Gram matrix K=(k⁡(Xi,Xj))1≤i,j≤nK=(k(X_{i},X_{j}))_{1\leq i,j\leq n} is replaced by a low rank approximation computed on m∈ℕm\in\mathbb{N} randomly chosen observations from 𝒟n{\mathcal{D}_{n}} as basis vectors. From the memory footprint point of view, it results in an n×mn\times m data matrix instead of the n×nn\times n Gram matrix KK for ERM.

Random Fourier features (RFF)

The canonical feature map 𝒙∈𝒳↦k⁡(𝒙,⋅)∈ℍ\bm{x}\in\mathcal{X}\mapsto k(\bm{x},\cdot)\in\mathbb{H} is approximated by a pp-valued function, where p∈ℕp\in\mathbb{N} is the number of random cosine basis functions chosen. This method yields a data matrix of size n×pn\times p compared to n×nn\times n for ERM.

Sketching (SKT)

Sketching is a dataset reduction method, basically working on l∈ℕl\in\mathbb{N} random linear combinations of the observations. We chose, for the comparison, the pp-sparsified Rademacher sketch, as introduced by 12, with probability p=30/np=30/n of non-empty entry in the sketch matrix. Let us remark that, if the memory footprint for the optimization procedure is n×ln\times l, the method requires first to compute the n×nn\times n Gram matrix before getting the sketched one.

The methods above are all compared based on a Gaussian radial basis kernel: k⁡(𝒙,𝒙′)=e−γ​‖𝒙−𝒙′‖22k(\bm{x},\bm{x}^{\prime})=e^{-\gamma\|\bm{x}-\bm{x}^{\prime}\|_{2}^{2}} for all 𝒙,𝒙′∈ℝd\bm{x},\bm{x}^{\prime}\in\mathbb{R}^{d}, with parameter γ\gamma set to the inverse of the empirical variance of the observations (rounded to two significant digits), unless said otherwise. For this comparison, two synthetic datasets (corresponding to a classification and a regression task) and a real-world dataset coming from the UCI repository (Covertype) are employed and described below.

Synthetic classification

The dataset is represented in Figure 1(a): the input vector is such that X∼Unif⁡([0,1]2)X\sim\mathrm{Unif}([0,1]^{2}) and three random centers are drawn from the same uniform distribution. Denoting d⁡(𝒙)d(\bm{x}) the minimum distance between a spatial observation 𝒙\bm{x} and the latter centers, the binary classification labels are such that Y|X∼Rad⁡(σ⁡(100​(d⁡(X)−0.25)))Y|X\sim\mathrm{Rad}(\sigma(100(d(X)-0.25))), where Rad⁡(p)\mathrm{Rad}(p) is the Rademarcher distribution with parameter p∈(0,1)p\in(0,1), and σ:t∈ℝ↦1/(1+e−t)\sigma:t\in\mathbb{R}\mapsto 1/(1+e^{-t}) is the sigmoid function.

For this task, a million observations (independent from the training data) are used for computing the test errors, and the logistic loss is used with regularization parameters λsn∗=λ0=10−5{\lambda_{s_{n}}^{*}}={\lambda_{0}}=10^{-5}.

(a) Classification
(b) Regression
Figure 1: Visualization of the synthetic datasets used in the numerical experiments.

Synthetic regression

The dataset is represented in Figure 1(b): the function to estimate is h⋆=(5/∑1≤i,j≤mβi0​βj0​k​(xi0,xj0))​∑i=1mβi0​k​(xi0,⋅)h^{\star}=(5/\sqrt{\sum_{1\leq i,j\leq m}\beta_{i}^{0}\beta_{j}^{0}k(x_{i}^{0},x_{j}^{0})})\sum_{i=1}^{m}\beta_{i}^{0}k(x_{i}^{0},\cdot) (i.e. ‖h⋆‖ℍ=5\|h^{\star}\|_{\mathbb{H}}=5), where m=10m=10, x10x_{1}^{0} to xm0x_{m}^{0} are random centers independently drawn according to a standard Gaussian distribution, and factors β10\beta_{1}^{0} to βm0\beta_{m}^{0} are sampled from the same distribution. Observations are (Xi,Yi)(X_{i},Y_{i})s, where for all i∈{1,…,n}i\in\{1,\dots,n\},

Yi​=def​h⋆​(Xi)+(12​|Xi|+0.1)​εi,Y_{i}\overset{\mathrm{def}}{=}h^{\star}(X_{i})+\left(\frac{1}{2}|X_{i}|+0.1\right)\varepsilon_{i},

with εi​∼i.i.d.​𝒩​(0,1)\varepsilon_{i}\overset{i.i.d.}{\sim}\mathcal{N}(0,1).

For this task, a 10610^{6}-sample independent from the training data is used for computing test errors, and the previously defined quartic-quadratic Huber loss (with ε=1\varepsilon=1) is used with regularization parameters λsn∗=λ0=10−3{\lambda_{s_{n}}^{*}}={\lambda_{0}}=10^{-3}. The latter loss has the benefit of being almost insensitive to small residues, while not less robust to outliers than the least squares loss. Let us remark that, since λ0>0{\lambda_{0}}>0, the true regularized risk minimizer h0{h_{0}} is different from h⋆h^{\star}.

Refer to caption
(a) Classification
Refer to caption
(b) Regression
Figure 2: Visualization of the L-optimal SSPs on the synthetic datasets (the size of each datapoint is proportional to its probability of being subsampled).

For both synthetic datasets, Figure 2 depicts the same points as in Figure 1 but with the size of each point proportional to its L-optimal SSP. It clearly reveals that important points for building the SRM hsn∗{h^{*}_{s_{n}}} are at the frontiers of classes for classification, and away from h⋆h^{\star} for regression.

UCI Covertype

The CovType dataset is a real-world repository of biological attributes on seven different forest cover types. It contains 581,012 records of 54 features each, with 10 of which being quantitative and the rest being binary. We aim at separating the last class from the others, which results in an imbalanced binary classification problem, handled with the logistic loss (meeting Assumption 2).

The dataset is split into two parts: 100,000 points are used for training and the rest for testing. Quantitative covariates are standardized and hyperparameters are set to γ=1\gamma=1 and λsn∗=λ0=5⋅10−6{\lambda_{s_{n}}^{*}}={\lambda_{0}}=5\cdot 10^{-6}.

6.2 Results

Methods are compared in three different settings, described below.

Varying smoothing hyperparameter α\alpha

As a first numerical experiment, we study the impact of the smoothing hyperparameter α∈(0,1]\alpha\in(0,1] on the generalization error. Figure 3 depicts classification and regression errors (computed on the test set) for SRM with Multinomial (SRM (M)) and Poisson (SRM (P)) subsampling, with respect to α\alpha. Both methods have the same subsampling budget bn=kn+snb_{n}=k_{n}+s_{n} when α<1\alpha<1, and bn=snb_{n}=s_{n} when α=1\alpha=1. In both synthetic and real-world situations, it appears that the higher α\alpha (the closer to uniform subsampling), the higher the generalization error (and both subsampling methods perform roughly the same). In particular, for α≤0.4\alpha\leq 0.4, the SRM error stays roughly constant and is less than that for uniform subsampling (α=1\alpha=1). As an exception, L-optimal subsampling without smoothing (α=0\alpha=0) for the synthetic classification task is as bad as uniform subsampling. This may be so because the optimal map ψ⋆\psi^{\star} does not verify assumptions of Theorems 3.2 and 3.3. As a result of this first lesson, we fix α=0.2\alpha=0.2 for the forthcoming experiments.

Moreover, as our framework is based on the consistency of hsn∗α{h_{s_{n}}^{*\alpha}}, Figures B.2 and B.1 in Appendix B provide L2L^{2}, L∞L^{\infty} or ℍ\mathbb{H}-distances between hsn∗α{h_{s_{n}}^{*\alpha}} and h0{h_{0}}. The results are similar than those of Figure 3 and show that a value of α\alpha between 0.10.1 and 0.40.4 leads to a better SRM estimator than uniform subsampling. This means that, in this setting, statistical and learning performances are in line with each other.

(a) Synthetic classification with n=105n=10^{5} and bn/n=0.02b_{n}/n=0.02.
(b) Synthetic regression with n=105n=10^{5} and bn/n=0.01b_{n}/n=0.01.
(c) Covtype with n=105n=10^{5} and bn/n=0.2b_{n}/n=0.2.
Figure 3: Generalization error with respect to the smoothing hyperparameter α\alpha.

Varying dataset size nn, fixed subsampling budget ratio bn/nb_{n}/n

In this second experiment, uniform subsampling is compared to α\alpha-piloted SRM on both synthetic tasks when the dataset size nn increases (from 10410^{4} to 5⋅1055\cdot 10^{5}) but the subsampling budget ratio bn/nb_{n}/n is fixed. Figure 4 represents the computational effort of each method, i.e. the CPU training time with respect to the generalization error, here as a curve parameterized by nn (in particular, the points from left to right on each curve correspond to the same values of nn). It appears that for small datasets (right part of the graphs), SRM is generally less efficient than uniform subsampling: for a given generalization error, SRM is more (time) consuming than uniform subsampling, and conversely, for a given training time, SRM is less accurate. This may be explained by a spurious information given by the pilot estimator, which is computed on too few data. However, the exact converse is true for large dataset sizes nn (left part of the graphs). To sum up, for small datasets, uniform subsampling is preferable, while for large datasets, SRM (which is based on asymptotic results) is more advantageous. This holds true for both subsampling techniques, which perform similarly.

Surprisingly, for a given dataset size nn, uniform subsampling is longer to train than α\alpha-piloted SRM, while it includes computing a pilot estimator. This can actually be explained by the fact that the computational cost is mainly due to computing hsn∗α{h_{s_{n}}^{*\alpha}}, that is solving an optimization problem of size (bn−kn)2(b_{n}-k_{n})^{2} for SRM and bn2b_{n}^{2} for uniform subsampling. The forthcoming experiment improves on this interpretation bias.

(a) Synthetic classification.
(b) Synthetic regression.
Figure 4: Computational effort parameterized by the sample size nn (fixed bn/nb_{n}/n).

Varying space budget, fixed dataset size nn

This last numerical experiment is closer to a real situation (and thus also includes the real-world case of cover type classification), where the dataset is given (so nn is fixed), and methods are compared thanks to the computational effort parameterized by the (memory) space budget. This one corresponds to the size of the optimization problems to solve, that is bn2b_{n}^{2} for uniform subsampling and kn2+(bn−kn)2k_{n}^{2}+(b_{n}-k_{n})^{2} for α\alpha-piloted SRM. On that occasion, it is also possible to fairly include state-of-the-art competitors, i.e. Nyström, RFF and SKT, for which the space budget is n​mnm, where mm is the approximation parameter of the method: the dimension of the subspace for the Nyström approach, the number of random projections for RFF and the number of linear combinations for the SKT. As evidenced by Figure 5, since nn is large, SRM is always favorable compared to uniform subsampling. It is also more efficient than Nyström, RFF and SKT on the CovType dataset (see Figure 5(c)).

Moreover, for a given space budget (a given point on the curves), α\alpha-piloted SRM and uniform subsampling are roughly as long to train than each other but the former is more accurate than the latter. This means that, for a prescribed memory budget, SRM is preferable to uniform subsampling (for large datasets), but also that estimating the L-optimal SSPs has a negligible computational time.

(a) Synthetic classification.
(b) Synthetic regression.
(c) Covtype.
Figure 5: Computational effort parameterized by the space budget (fixed nn).

Regarding the synthetic tasks (Figures 5(a) and 5(b)), Nyström, RFF and SKT appear more computationally efficient (curves are at the bottom and on the left). This may be explained by the low dimension of the input data. Nevertheless, subsampling and kernel approximations methods can be considered as complementary techniques for reducing the computational cost of kernel approaches. Thus, Figure 6 presents numerical results when uniform subsampling and SRM estimators are computed with the Nyström approximation method. It results in increased performances for subsampling techniques, making α\alpha-piloted SRM more appealing than Nyström, RFF and SKT alone regarding the computational effort.

(a) Synthetic classification.
(b) Synthetic regression.
Figure 6: Computational effort parameterized by the space budget (fixed nn) for mixed Nyström-subsampling estimators.

7 Conclusion and discussion

This paper addresses the design of a reduced dataset by subsampling a large one, with the aim of computing a kernel-based estimator for classification or regression. Based on asymptotic results, it is possible to randomly choose observations leading to a minimal trace for the limit covariance operator of the subsampling estimator. This L-optimal subsampling scheme can then be estimated by plug-in, based on a pilot estimator, and smoothed in order to provide a robust practical method. The latter is compatible with state-of-the-art kernel approximation techniques and can, for instance, be coupled with the Nyström method, leading to a very computationally efficient framework for learning in RKHSs. Numerical experiments demonstrate the appeal of the method compared to uniform subsampling and kernel approximations, in particular for large initial datasets.

The work presented here opens several directions of research. First, the theory is based on a regularized population risk and could, at the price of a substantial work, be extended to a non-regularized risk minimizer. Second, the proposed approach is basically a two-step algorithm, learning first a pilot estimator (as well as estimating the subsampling probabilities and building the subsampled dataset) and then learning the final subsampling estimator. One may conceive a multistage (or online) procedure, where the pilot estimator and the subsampling probabilities are sequentially adjusted in order to leverage more the random choice of consistent individuals.

Acknowledgments

This project was partially funded by the alliance AI4IDF. The authors are grateful to Jeffrey Näf for insightful discussions on asymptotics in RKHSs.

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Appendix A Proofs

A.1 Derivatives of LL

Lemma A.1.

Under Assumptions 1, 2 and 3, LL is twice differentiable at h0{h_{0}}, with:

∇L​(h0)=𝔼⁡[ℓ′​(h0​(X),Y)​KX]and∇2L​(h0)=𝔼⁡[ℓ′′​(h0​(X),Y)​KX⊗KX].\nabla{L}({h_{0}})=\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)K_{X}\right]\quad\text{and}\quad\nabla^{2}{L}({h_{0}})=\mathbb{E}\left[\ell^{\prime\prime}({h_{0}}(X),Y)K_{X}\otimes K_{X}\right].
Proof.

Let B1​=def​κ​(‖h0‖ℍ+1)B_{1}\overset{\mathrm{def}}{=}\kappa(\|{h_{0}}\|_{\mathbb{H}}+1) and ϕ​=def​ϕB1\phi\overset{\mathrm{def}}{=}\phi_{B_{1}}. By Cauchy-Schwarz and Assumption 1, for all h∈ℍh\in\mathbb{H} such that ‖h‖ℍ≤1\|h\|_{\mathbb{H}}\leq 1,

|(h0+h)​(X)|=|⟨h0+h,KX⟩ℍ|≤‖KX‖ℍ​‖h0+h‖ℍ≤B1.|({h_{0}}+h)(X)|=|\langle{h_{0}}+h,K_{X}\rangle_{\mathbb{H}}|\leq\|K_{X}\|_{\mathbb{H}}\|{h_{0}}+h\|_{\mathbb{H}}\leq B_{1}.

Now, by the inequality (a+b)4≤8​(a4+b4)(a+b)^{4}\leq 8(a^{4}+b^{4}) for all (a,b)∈ℝ2(a,b)\in\mathbb{R}^{2}, and Assumption 2:

ℓ​((h0+h)​(X),Y)4\displaystyle\ell(({h_{0}}+h)(X),Y)^{4} ≤8​(ℓ​(0,Y)4+|ℓ⁡((h0+h)​(X),Y)−ℓ⁡(0,Y)|4)\displaystyle\leq 8\left(\ell(0,Y)^{4}+|\ell(({h_{0}}+h)(X),Y)-\ell(0,Y)|^{4}\right)
≤8​(ℓ​(0,Y)4+ϕ​(Y)4​|(h0+h)​(X)|4)\displaystyle\leq 8\left(\ell(0,Y)^{4}+\phi(Y)^{4}|({h_{0}}+h)(X)|^{4}\right)
≤8​(ℓ​(0,Y)4+B14​ϕ​(Y)4).\displaystyle\leq 8\left(\ell(0,Y)^{4}+B_{1}^{4}\phi(Y)^{4}\right).

Thus, by Assumption 3, L{L} is dominated in a neighborhood of h0{h_{0}} by a four times integrable function. As the previous set of inequalities remains true for ℓ(k)\ell^{(k)} with k∈{0,1,2}k\in\{0,1,2\}, it yields, by the dominated convergence theorem and Leibniz integral rule, that LL is continuous and Fréchet differentiable at h0{h_{0}} with:

∇L​(h0)=𝔼⁡[ℓ′​(h0​(X),Y)​KX].\nabla{L}({h_{0}})=\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)K_{X}\right].

In the same manner, it comes:

∇2L​(h0)=𝔼⁡[ℓ′′​(h0​(X),Y)​KX⊗KX].∎\nabla^{2}{L}({h_{0}})=\mathbb{E}\left[\ell^{\prime\prime}({h_{0}}(X),Y)K_{X}\otimes K_{X}\right].\qed

A.2 Proof of Theorem 2.1

Theorem A.2 (Consistency of h^n{\hat{h}_{n}}).

Under Assumptions 1, 2 and 3, if one furthermore assumes that λn​⟶n→∞ℙ​λ0{\lambda_{n}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}{\lambda_{0}}, one has

‖h^n−h0‖ℍ​⟶n→∞ℙ​0.\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.

Part of the following proof is adapted from Theorem 5.9 of (6).

Proof.

As ℓ\ell is convex, one has for all (𝒙,y)∈𝒵(\bm{x},y)\in\mathcal{Z},

ℓ′​(h0​(𝒙),y)​(h^n​(𝒙)−h0​(𝒙))≤ℓ⁡(h^n​(𝒙),y)−ℓ⁡(h0​(𝒙),y),\ell^{\prime}({h_{0}}(\bm{x}),y)({\hat{h}_{n}}(\bm{x})-{h_{0}}(\bm{x}))\leq\ell({\hat{h}_{n}}(\bm{x}),y)-\ell({h_{0}}(\bm{x}),y),

and

⟨h^n−h0,∇Ln​(h0)⟩ℍ≤Ln​(h^n)−Ln​(h0),\langle{\hat{h}_{n}}-{h_{0}},\nabla{L}_{n}({h_{0}})\rangle_{\mathbb{H}}\leq{L}_{n}({\hat{h}_{n}})-{L}_{n}({h_{0}}),

by summing under the empirical distribution. Moreover,

λn​⟨h^n−h0,h0⟩ℍ+λn2​‖h^n−h0‖ℍ2=λn2​‖h^n‖ℍ2−λn2​‖h0‖ℍ2.{\lambda_{n}}\langle{\hat{h}_{n}}-{h_{0}},{h_{0}}\rangle_{\mathbb{H}}+\frac{{\lambda_{n}}}{2}\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}^{2}=\frac{{\lambda_{n}}}{2}\|{\hat{h}_{n}}\|_{\mathbb{H}}^{2}-\frac{{\lambda_{n}}}{2}\|{h_{0}}\|_{\mathbb{H}}^{2}.

Hence,

λn2​‖h^n−h0‖ℍ2+⟨h^n−h0,∇Ln​(h0)+λn​h0⟩ℍ≤ℛn​(h^n)−ℛn​(h0)≤0,\displaystyle\frac{{\lambda_{n}}}{2}\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}^{2}+\langle{\hat{h}_{n}}-{h_{0}},\nabla{L}_{n}({h_{0}})+{\lambda_{n}}{h_{0}}\rangle_{\mathbb{H}}\leq{\mathcal{R}}_{n}({\hat{h}_{n}})-{\mathcal{R}}_{n}({h_{0}})\leq 0,

since h^n{\hat{h}_{n}} is the minimizer of ℛn{\mathcal{R}}_{n}. However, λ0​h0=−∇L​(h0){\lambda_{0}}{h_{0}}=-\nabla L({h_{0}}), thus,

λn2∥h^n−h0∥ℍ2≤⟨h^n−h0,λnλ0∇L(h0)−∇Ln(h0)⟩ℍ.\frac{{\lambda_{n}}}{2}\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}^{2}\leq\langle{\hat{h}_{n}}-{h_{0}},\frac{{\lambda_{n}}}{{\lambda_{0}}}\nabla{L}({h_{0}})-\nabla{L}_{n}({h_{0}})\rangle_{\mathbb{H}}.

Furthermore, by Cauchy-Schwarz,

‖h^n−h0‖ℍ\displaystyle\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}} ≤2λn∥∇Ln(h0)−λnλ0∇L(h0)∥ℍ\displaystyle\leq\frac{2}{{\lambda_{n}}}\|\nabla{L}_{n}({h_{0}})-\frac{{\lambda_{n}}}{{\lambda_{0}}}\nabla{L}({h_{0}})\|_{\mathbb{H}}
≤2λn​‖∇Ln​(h0)−∇L​(h0)‖ℍ+2λ0​λn​|λn−λ0|​‖∇L​(h0)‖ℍ,\displaystyle\leq\frac{2}{{\lambda_{n}}}\|\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})\|_{\mathbb{H}}+\frac{2}{{\lambda_{0}}{\lambda_{n}}}\left|{\lambda_{n}}-{\lambda_{0}}\right|\|\nabla{L}({h_{0}})\|_{\mathbb{H}},

as λ0>0{\lambda_{0}}>0 and λn>0{\lambda_{n}}>0. Finally, λn​⟶n→∞ℙ​λ0{\lambda_{n}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}{\lambda_{0}} and ∇Ln(h0)⟶n→∞ℙ∇L(h0)\nabla{L}_{n}({h_{0}})\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\nabla{L}({h_{0}}), by the law of large numbers, which shows that ‖h^n−h0‖ℍ​⟶n→∞ℙ​0\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0. ∎

Lemma A.3.

Under Assumptions 1, 2 and 3 one has,

n​(∇Ln​(h0)−∇L​(h0))​⟶n→∞d​𝒢​(0,Σ),\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}))\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma),

where Σ​=def​𝔼​[ℓ′​(h0​(X),Y)2​KX⊗KX]−∇L​(h0)⊗∇L​(h0)\Sigma\overset{\mathrm{def}}{=}\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-\nabla{L}({h_{0}})\otimes\nabla{L}({h_{0}}).

Proof.

Let f∈ℍf\in\mathbb{H}. Define the real-valued random variable Sn​=def​⟨∇Ln​(h0)−∇L​(h0),f⟩ℍS_{n}\overset{\mathrm{def}}{=}\langle\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}),f\rangle_{\mathbb{H}}, then,

Sn\displaystyle S_{n} =1n​∑i=1nℓ′​(h0​(Xi),Yi)​⟨KXi,f⟩ℍ−⟨∇L​(h0),f⟩ℍ\displaystyle=\frac{1}{n}\sum_{i=1}^{n}\ell^{\prime}({h_{0}}(X_{i}),Y_{i})\langle K_{X_{i}},f\rangle_{\mathbb{H}}-\langle\nabla{L}({h_{0}}),f\rangle_{\mathbb{H}}
=1n​∑i=1nℓ′​(h0​(Xi),Yi)​f​(Xi)−𝔼⁡[ℓ′​(h0​(X),Y)​f​(X)]\displaystyle=\frac{1}{n}\sum_{i=1}^{n}\ell^{\prime}({h_{0}}(X_{i}),Y_{i})f(X_{i})-\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)f(X)\right]
=1n​∑i=1nℒ′​(Zi,h0,f)−𝔼⁡[ℒ′​(Z,h0,f)],\displaystyle=\frac{1}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)-\mathbb{E}\left[\mathcal{L}^{\prime}(Z,{h_{0}},f)\right],

where ℒ′​(Z,h,f)​=def​ℓ′​(h⁡(X),Y)​f​(X)\mathcal{L}^{\prime}(Z,h,f)\overset{\mathrm{def}}{=}\ell^{\prime}(h(X),Y)f(X). SnS_{n} is a sum of nn i.i.d real random variables with mean,

𝔼⁡[ℒ′​(Z1,h0,f)−𝔼⁡[ℒ′​(Z,h0,f)]]=𝔼⁡[ℒ′​(Z1,h0,f)]−𝔼⁡[ℒ′​(Z,h0,f)]=0,\displaystyle\mathbb{E}\left[\mathcal{L}^{\prime}(Z_{1},{h_{0}},f)-\mathbb{E}\left[\mathcal{L}^{\prime}(Z,{h_{0}},f)\right]\right]=\mathbb{E}\left[\mathcal{L}^{\prime}(Z_{1},{h_{0}},f)\right]-\mathbb{E}\left[\mathcal{L}^{\prime}(Z,{h_{0}},f)\right]=0,

and variance,

Var⁡(ℒ′​(Z1,h0,f))\displaystyle\Var\left(\mathcal{L}^{\prime}(Z_{1},{h_{0}},f)\right) =𝔼⁡[(ℒ′​(Z1,h0,f)−𝔼⁡[ℒ′​(Z1,h0,f)])2]\displaystyle=\mathbb{E}\left[\left(\mathcal{L}^{\prime}(Z_{1},{h_{0}},f)-\mathbb{E}\left[\mathcal{L}^{\prime}(Z_{1},{h_{0}},f)\right]\right)^{2}\right]
=𝔼⁡[ℒ′​(Z1,h0,f)2]−𝔼​[ℒ′​(Z1,h0,f)]2\displaystyle=\mathbb{E}\left[\mathcal{L}^{\prime}(Z_{1},{h_{0}},f)^{2}\right]-\mathbb{E}\left[\mathcal{L}^{\prime}(Z_{1},{h_{0}},f)\right]^{2}
=⟨Σ​f,f⟩ℍ.\displaystyle=\langle\Sigma f,f\rangle_{\mathbb{H}}.

where Σ​=def​𝔼​[ℓ′​(h0​(X),Y)2​KX⊗KX]−∇L​(h0)⊗∇L​(h0)\Sigma\overset{\mathrm{def}}{=}\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-\nabla{L}({h_{0}})\otimes\nabla{L}({h_{0}}). Thus, by the one dimensional central limit theorem,

n​⟨∇Ln​(h0)−∇L​(h0),f⟩ℍ​⟶n→∞d​𝒩​(0,⟨Σ​f,f⟩ℍ).\sqrt{n}\langle\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}),f\rangle_{\mathbb{H}}\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{N}(0,\langle\Sigma f,f\rangle_{\mathbb{H}}).

There is left to show that n​(∇Ln​(h0)−∇L​(h0))\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})) is asymptotically finite dimensional. Let ε,δ>0\varepsilon,\delta>0. Since 𝔼⁡[‖ℓ′​(h0​(X),Y)​KX‖ℍ2]<∞\mathbb{E}\left[\|\ell^{\prime}({h_{0}}(X),Y)K_{X}\|^{2}_{\mathbb{H}}\right]<\infty by Assumption 3, there exists J∈ℕJ\in\mathbb{N} such that 𝔼⁡[∑j>Jℓ′​(h0​(X),Y)2​⟨KX,ej⟩ℍ2]<δ​ε\mathbb{E}\left[\sum_{j>J}\ell^{\prime}({h_{0}}(X),Y)^{2}\langle K_{X},e_{j}\rangle_{\mathbb{H}}^{2}\right]<\delta\varepsilon. Hence by Markov’s inequality,

ℙ⁡(∑j>J⟨n​(∇Ln​(h0)−∇L​(h0)),ej⟩ℍ2≥ε)≤nε​𝔼​[∑j>J⟨∇Ln​(h0)−∇L​(h0),ej⟩ℍ2].\mathbb{P}\left(\sum_{j>J}\langle\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})),e_{j}\rangle_{\mathbb{H}}^{2}\geq\varepsilon\right)\leq\frac{n}{\varepsilon}\mathbb{E}\left[\sum_{j>J}\langle\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}),e_{j}\rangle_{\mathbb{H}}^{2}\right].

Moreover, considering that the random variables in ∇Ln​(h0)\nabla{L}_{n}({h_{0}}) are i.i.d. with mean ∇L​(h0)\nabla{L}({h_{0}}) one has,

𝔼⁡[∑j>J⟨∇Ln​(h0)−∇L​(h0),ej⟩ℍ2]=1n​𝔼​[∑j>Jℓ′​(h0​(X),Y)2​⟨KX,ej⟩ℍ2]\displaystyle\mathbb{E}\left[\sum_{j>J}\langle\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}),e_{j}\rangle_{\mathbb{H}}^{2}\right]=\frac{1}{n}\mathbb{E}\left[\sum_{j>J}\ell^{\prime}({h_{0}}(X),Y)^{2}\langle K_{X},e_{j}\rangle_{\mathbb{H}}^{2}\right]
−1n∑j>J⟨∇L(h0),ej⟩ℍ2.\displaystyle-\frac{1}{n}\sum_{j>J}\langle\nabla{L}({h_{0}}),e_{j}\rangle_{\mathbb{H}}^{2}.

Hence, by definition of JJ,

ℙ⁡(∑j>J⟨n​(∇Ln​(h0)−∇L​(h0)),ej⟩ℍ2≥ε)\displaystyle\mathbb{P}\left(\sum_{j>J}\langle\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})),e_{j}\rangle_{\mathbb{H}}^{2}\geq\varepsilon\right) ≤1ε​𝔼​[∑j>Jℓ′​(h0​(X),Y)2​⟨KX,ej⟩ℍ2]\displaystyle\leq\frac{1}{\varepsilon}\mathbb{E}\left[\sum_{j>J}\ell^{\prime}({h_{0}}(X),Y)^{2}\langle K_{X},e_{j}\rangle_{\mathbb{H}}^{2}\right]
≤δ.\displaystyle\leq\delta.

Thus, n​(∇Ln​(h0)−∇L​(h0))\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})) is asymptotically finite-dimensional, in the sense that for all ε,δ>0\varepsilon,\delta>0, there exists J∈ℕJ\in\mathbb{N} such that,

lim supn∈ℕℙ⁡(∑j>J⟨n​(∇Ln​(h0)−∇L​(h0)),ej⟩ℍ2≥ε)≤δ.\limsup_{n\in\mathbb{N}}\ \mathbb{P}\left(\sum_{j>J}\langle\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})),e_{j}\rangle_{\mathbb{H}}^{2}\geq\varepsilon\right)\leq\delta.

Applying Theorem 7.7.5 of (21) yields

n​(∇Ln​(h0)−∇L​(h0))​⟶n→∞d​𝒢​(0,Σ).∎\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}))\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma).\qed
Lemma A.4.

Under Assumptions 1, 2, 3 and 4,

n​∫01∇2ℛn​(h¯n,t)​(h^n−h0)​𝑑t−n​∇2ℛ​(h0)​(h^n−h0)​⟶n→∞ℙ​0,\sqrt{n}\int_{0}^{1}\nabla^{2}{\mathcal{R}}_{n}(\bar{h}_{n,t})({\hat{h}_{n}}-{h_{0}})\,\mathrm{d}t-\sqrt{n}\nabla^{2}{\mathcal{R}}({h_{0}})({\hat{h}_{n}}-{h_{0}})\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0,

with h¯n,t=h0+t⁡(h^n−h0)\bar{h}_{n,t}={h_{0}}+t({\hat{h}_{n}}-{h_{0}}) for all t∈[0,1]t\in[0,1].

Proof.

Firstly, in the proof of Theorem A.2 we showed that,

‖h^n−h0‖ℍ≤2λn​‖∇Ln​(h0)−∇L​(h0)‖ℍ+2λ0​λn​|λn−λ0|​‖∇L​(h0)‖ℍ,\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}\leq\frac{2}{{\lambda_{n}}}\|\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})\|_{\mathbb{H}}+\frac{2}{{\lambda_{0}}{\lambda_{n}}}\left|{\lambda_{n}}-{\lambda_{0}}\right|\|\nabla{L}({h_{0}})\|_{\mathbb{H}},

and from Lemma A.3 n​(∇Ln​(h0)−∇L​(h0))\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})) converges in distribution to a Gaussian process. Thus, n​‖h^n−h0‖ℍ=Oℙ​(1)\sqrt{n}\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}=O_{\mathbb{P}}(1), by the fact that n​(λn−λ0)\sqrt{n}({\lambda_{n}}-{\lambda_{0}}) converges to 0 in probability.

Then, let h∈ℍh\in\mathbb{H}, t∈[0,1]t\in[0,1] and denote h¯n,t=h0+t⁡(h^n−h0)\bar{h}_{n,t}={h_{0}}+t({\hat{h}_{n}}-{h_{0}}). By consistency of h^n{\hat{h}_{n}}, one has that ‖h¯n,t−h0‖​⟶n→∞ℙ​0\|\bar{h}_{n,t}-{h_{0}}\|\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0. On the one hand, by the expression of ∇2ℛn​(⋅)\nabla^{2}{\mathcal{R}}_{n}(\cdot) and triangle inequality,

n​|⟨∇2ℛn​(h¯n,t)​(h^n−h0),h⟩ℍ−⟨∇2ℛn​(h0)​(h^n−h0),h⟩ℍ|\displaystyle\sqrt{n}|\langle\nabla^{2}{\mathcal{R}}_{n}(\bar{h}_{n,t})({\hat{h}_{n}}-{h_{0}}),h\rangle_{\mathbb{H}}-\langle\nabla^{2}{\mathcal{R}}_{n}({h_{0}})({\hat{h}_{n}}-{h_{0}}),h\rangle_{\mathbb{H}}|
=|1n​∑i=1n(ℓ′′​(h¯n,t​(Xi),Yi)−ℓ′′​(h0​(Xi),Yi))​⟨KXi⊗KXi​(h^n−h0),h⟩ℍ|\displaystyle\quad=\left|\frac{1}{\sqrt{n}}\sum_{i=1}^{n}(\ell^{\prime\prime}(\bar{h}_{n,t}(X_{i}),Y_{i})-\ell^{\prime\prime}({h_{0}}(X_{i}),Y_{i}))\langle K_{X_{i}}\otimes K_{X_{i}}({\hat{h}_{n}}-{h_{0}}),h\rangle_{\mathbb{H}}\right|
≤1n​∑i=1n|(ℓ′′​(h¯n,t​(Xi),Yi)−ℓ′′​(h0​(Xi),Yi))​⟨KXi,h^n−h0⟩ℍ​⟨KXi,h⟩ℍ|.\displaystyle\quad\leq\frac{1}{\sqrt{n}}\sum_{i=1}^{n}\left|(\ell^{\prime\prime}(\bar{h}_{n,t}(X_{i}),Y_{i})-\ell^{\prime\prime}({h_{0}}(X_{i}),Y_{i}))\langle K_{X_{i}},{\hat{h}_{n}}-{h_{0}}\rangle_{\mathbb{H}}\langle K_{X_{i}},h\rangle_{\mathbb{H}}\right|. (A.1)

Moreover, using Assumption 2 for all i∈{1,…,n}i\in\{1,\dots,n\},

|ℓ′′(h¯n,t(Xi),Yi)−ℓ′′(h0(Xi),Yi)|𝟙{∥h¯n,t−h0∥ℍ<1}\displaystyle|\ell^{\prime\prime}(\bar{h}_{n,t}(X_{i}),Y_{i})-\ell^{\prime\prime}({h_{0}}(X_{i}),Y_{i})|\mathbbm{1}_{\{\|\bar{h}_{n,t}-{h_{0}}\|_{\mathbb{H}}<1\}} ≤ϕ⁡(Yi)​|⟨KXi,h¯n,t−h0⟩ℍ|\displaystyle\leq\phi(Y_{i})|\langle K_{X_{i}},\bar{h}_{n,t}-{h_{0}}\rangle_{\mathbb{H}}|
≤ϕ⁡(Yi)​|⟨KXi,h^n−h0⟩ℍ|,\displaystyle\leq\phi(Y_{i})|\langle K_{X_{i}},{\hat{h}_{n}}-{h_{0}}\rangle_{\mathbb{H}}|,

as t∈[0,1]t\in[0,1]. By Cauchy-Schwarz and Assumption 1, one has

|⟨KXi,h^n−h0⟩ℍ|≤‖h^n−h0‖ℍ​‖KXi‖ℍ≤κ​‖h^n−h0‖ℍ,|\langle K_{X_{i}},{\hat{h}_{n}}-{h_{0}}\rangle_{\mathbb{H}}|\leq\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}\|K_{X_{i}}\|_{\mathbb{H}}\leq\kappa\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}},

and |⟨KXi,h⟩ℍ|≤κ​‖h‖ℍ|\langle K_{X_{i}},h\rangle_{\mathbb{H}}|\leq\kappa\|h\|_{\mathbb{H}}. Thus, applying Lemma A.6 with the random variables being (A.1) and the events En={∥h¯n−h0∥ℍ≥1}E_{n}=\{\|\bar{h}_{n}-{h_{0}}\|_{\mathbb{H}}\geq 1\} yields

n​∫01|⟨∇2ℛn​(h¯n,t)​(h^n−h0),h⟩ℍ−⟨∇2ℛn​(h0)​(h^n−h0),h⟩ℍ|​𝑑t\displaystyle\sqrt{n}\int_{0}^{1}|\langle\nabla^{2}{\mathcal{R}}_{n}(\bar{h}_{n,t})({\hat{h}_{n}}-{h_{0}}),h\rangle_{\mathbb{H}}-\langle\nabla^{2}{\mathcal{R}}_{n}({h_{0}})({\hat{h}_{n}}-{h_{0}}),h\rangle_{\mathbb{H}}|\,\mathrm{d}t
≤n​κ3​‖h‖ℍ​‖h^n−h0‖ℍ2​1n​∑i=1nϕ⁡(Yi)+oℙ​(1)​⟶n→∞ℙ​0,\displaystyle\quad\leq\sqrt{n}\kappa^{3}\|h\|_{\mathbb{H}}\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}^{2}\frac{1}{n}\sum_{i=1}^{n}\phi(Y_{i})+o_{\mathbb{P}}(1)\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0, (A.2)

since n−1​∑i=1nϕ⁡(Yi)=𝔼​ϕ​(Y)+oℙ​(1)=Oℙ​(1)n^{-1}\sum_{i=1}^{n}\phi(Y_{i})=\mathbb{E}\phi(Y)+o_{\mathbb{P}}(1)=O_{\mathbb{P}}(1), n​‖h^n−h0‖ℍ=Oℙ​(1)\sqrt{n}\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}=O_{\mathbb{P}}(1) and ‖h^n−h0‖ℍ​⟶n→∞ℙ​0\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0 by Theorem A.2. On the other hand, since ∇2ℛn​(h0)\nabla^{2}{\mathcal{R}}_{n}({h_{0}}) and ∇2ℛ​(h0)\nabla^{2}{\mathcal{R}}({h_{0}}) are self-adjoint operators, one has

|⟨∇2ℛn​(h0)​(h^n−h0),h⟩ℍ−⟨∇2ℛ​(h0)​(h^n−h0),h⟩ℍ|\displaystyle|\langle\nabla^{2}{\mathcal{R}}_{n}({h_{0}})({\hat{h}_{n}}-{h_{0}}),h\rangle_{\mathbb{H}}-\langle\nabla^{2}{\mathcal{R}}({h_{0}})({\hat{h}_{n}}-{h_{0}}),h\rangle_{\mathbb{H}}|
=|⟨h^n−h0,∇2ℛn​(h0)​h⟩ℍ−⟨h^n−h0,∇2ℛ​(h0)​h⟩ℍ|\displaystyle\quad=|\langle{\hat{h}_{n}}-{h_{0}},\nabla^{2}{\mathcal{R}}_{n}({h_{0}})h\rangle_{\mathbb{H}}-\langle{\hat{h}_{n}}-{h_{0}},\nabla^{2}{\mathcal{R}}({h_{0}})h\rangle_{\mathbb{H}}|
=|⟨h^n−h0,∇2ℛn​(h0)​h−∇2ℛ​(h0)​h⟩ℍ|\displaystyle\quad=|\langle{\hat{h}_{n}}-{h_{0}},\nabla^{2}{\mathcal{R}}_{n}({h_{0}})h-\nabla^{2}{\mathcal{R}}({h_{0}})h\rangle_{\mathbb{H}}|
≤‖h^n−h0‖ℍ​‖∇2ℛn​(h0)​h−∇2ℛ​(h0)​h‖ℍ,\displaystyle\quad\leq\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}\|\nabla^{2}{\mathcal{R}}_{n}({h_{0}})h-\nabla^{2}{\mathcal{R}}({h_{0}})h\|_{\mathbb{H}},

by Cauchy-Schwarz inequality. Furthermore

∇2ℛn​(h0)​h\displaystyle\nabla^{2}{\mathcal{R}}_{n}({h_{0}})h =1n​∑i=1nℓ′′​(h0​(Xi),Yi)​h​(Xi)​KXi+λn​h\displaystyle=\frac{1}{n}\sum_{i=1}^{n}\ell^{\prime\prime}({h_{0}}(X_{i}),Y_{i})h(X_{i})K_{X_{i}}+{\lambda_{n}}h
⟶n→∞ℙ​𝔼​[ℓ′′​(h0​(X),Y)​h​(X)​KX]+λ0​h=∇2ℛ​(h0)​h,\displaystyle\quad\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}\left[\ell^{\prime\prime}({h_{0}}(X),Y)h(X)K_{X}\right]+{\lambda_{0}}h=\nabla^{2}{\mathcal{R}}({h_{0}})h,

by the law of large numbers and that λn​⟶n→∞ℙ​λ0{\lambda_{n}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}{\lambda_{0}}. Whence

n​∫01|⟨∇2ℛn​(h0)​(h^n−h0),h⟩ℍ−⟨∇2ℛ​(h0)​(h^n−h0),h⟩ℍ|​𝑑t\displaystyle\sqrt{n}\int_{0}^{1}|\langle\nabla^{2}{\mathcal{R}}_{n}({h_{0}})({\hat{h}_{n}}-{h_{0}}),h\rangle_{\mathbb{H}}-\langle\nabla^{2}{\mathcal{R}}({h_{0}})({\hat{h}_{n}}-{h_{0}}),h\rangle_{\mathbb{H}}|\,\mathrm{d}t
≤n​‖h^n−h0‖ℍ​‖∇2ℛn​(h0)​h−∇2ℛ​(h0)​h‖ℍ​⟶n→∞ℙ​0.\displaystyle\quad\leq\sqrt{n}\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}\|\nabla^{2}{\mathcal{R}}_{n}({h_{0}})h-\nabla^{2}{\mathcal{R}}({h_{0}})h\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0. (A.3)

Finally, combining (A.2) and (A.3) yields the wanted result

n​∫01⟨∇2ℛn​(h¯n,t)​(h^n−h0),h⟩ℍ​𝑑t−n​⟨∇2ℛ​(h0)​(h^n−h0),h⟩ℍ​⟶n→∞ℙ​0.∎\sqrt{n}\int_{0}^{1}\langle\nabla^{2}{\mathcal{R}}_{n}(\bar{h}_{n,t})({\hat{h}_{n}}-{h_{0}}),h\rangle_{\mathbb{H}}\,\mathrm{d}t-\sqrt{n}\langle\nabla^{2}{\mathcal{R}}({h_{0}})({\hat{h}_{n}}-{h_{0}}),h\rangle_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.\qed

We can now prove the main theorem using the two above lemmas.

Proof of Theorem 2.1.

The fundamental theorem of calculus yields

0=∇ℛn​(h^n)=∇ℛn​(h0)+∫01∇2ℛn​(h¯n,t)​(h^n−h0)​𝑑t,0=\nabla{\mathcal{R}}_{n}({\hat{h}_{n}})=\nabla{\mathcal{R}}_{n}({h_{0}})+\int_{0}^{1}\nabla^{2}{\mathcal{R}}_{n}(\bar{h}_{n,t})({\hat{h}_{n}}-{h_{0}})\,\mathrm{d}t,

with h¯n,t=h0+t⁡(h^n−h0)\bar{h}_{n,t}={h_{0}}+t({\hat{h}_{n}}-{h_{0}}) for t∈[0,1]t\in[0,1]. By Lemma A.4, one has

−n∇ℛn(h0)=n∇2ℛ(h0)(h^n−h0)+oℙ(1).-\sqrt{n}\nabla{\mathcal{R}}_{n}({h_{0}})=\sqrt{n}\nabla^{2}{\mathcal{R}}({h_{0}})({\hat{h}_{n}}-{h_{0}})+o_{\mathbb{P}}(1).

Notice that

∇ℛn​(h0)=(∇Ln​(h0)−∇L​(h0))+(λn−λ0)​h0.\displaystyle\nabla{\mathcal{R}}_{n}({h_{0}})=(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}))+({\lambda_{n}}-{\lambda_{0}}){h_{0}}.

However, n​(λn−λ0)​⟶n→∞ℙ​0\sqrt{n}({\lambda_{n}}-{\lambda_{0}})\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0 by Assumption 4, hence

n∇ℛn(h0)=n(∇Ln(h0)−∇L(h0))+n(λn−λ0)h0⟶n→∞d𝒢(0,Σ),\sqrt{n}\nabla{\mathcal{R}}_{n}({h_{0}})=\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}))+\sqrt{n}({\lambda_{n}}-{\lambda_{0}}){h_{0}}\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma),

by Slutsky’s lemma and Lemma A.3, which concludes the proof. ∎

A.3 Subsampling intermediate results

The two following short lemma deal of general results for convergence in probability.

Lemma A.5.

Let (Xn)n∈ℕ(X_{n})_{n\in\mathbb{N}} be a sequence of real valued random variables. Suppose that for all ε>0\varepsilon>0, there exists a sequence (Ynε)n∈ℕ(Y_{n}^{\varepsilon})_{n\in\mathbb{N}} such that for all n∈ℕn\in\mathbb{N},

0≤Xn≤Ynε​a.s.andYnε​⟶n→∞ℙ​ε.0\leq X_{n}\leq Y_{n}^{\varepsilon}\ \text{a.s.}\qquad\text{and}\qquad Y_{n}^{\varepsilon}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\varepsilon.

Then (Xn)n∈ℕ(X_{n})_{n\in\mathbb{N}} converges in probability to 0.

Proof.

Let δ>0\delta>0 and 0<ε<δ0<\varepsilon<\delta.

ℙ⁡(Xn≥δ)≤ℙ⁡(Ynε≥δ)\displaystyle\mathbb{P}\left(X_{n}\geq\delta\right)\leq\mathbb{P}\left(Y_{n}^{\varepsilon}\geq\delta\right) =ℙ⁡(Ynε−ε≥δ−ε)≤ℙ⁡(|Ynε−ε|≥δ−ε)​⟶n→∞​0.∎\displaystyle=\mathbb{P}\left(Y_{n}^{\varepsilon}-\varepsilon\geq\delta-\varepsilon\right)\leq\mathbb{P}\left(|Y_{n}^{\varepsilon}-\varepsilon|\geq\delta-\varepsilon\right)\underset{n\rightarrow\infty}{\longrightarrow}0.\qed
Lemma A.6.

Let (An)n∈ℕ(A_{n})_{n\in\mathbb{N}} be a sequence of non negative random variables and (En)n∈ℕ(E_{n})_{n\in\mathbb{N}} be a sequence of events such that ℙ⁡(En)​⟶n→∞​0\mathbb{P}\left(E_{n}\right)\underset{n\rightarrow\infty}{\longrightarrow}0. Then An​𝟙En​⟶n→∞ℙ​0A_{n}\mathbbm{1}_{E_{n}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.

Proof.

Let ε>0\varepsilon>0,

ℙ⁡(An​𝟙En>ε)≤ℙ⁡(𝟙En=1)=ℙ⁡(En)​⟶n→∞​0.∎\mathbb{P}\left(A_{n}\mathbbm{1}_{E_{n}}>\varepsilon\right)\leq\mathbb{P}\left(\mathbbm{1}_{E_{n}}=1\right)=\mathbb{P}\left(E_{n}\right)\underset{n\rightarrow\infty}{\longrightarrow}0.\qed

The hereby theorem and its following proof are a piece of Theorem 3.5 in (17) revised with the conditional Lindeberg-Feller assumption instead of the usual one.

Theorem A.7 (Conditional Lindeberg-Feller).

Let {ηn,j:n>0,1≤j≤kn}\{\eta_{n,j}:n>0,1\leq j\leq k_{n}\} be a real martingale difference array adapted to a filtration array (ℱn,j)n>0,0≤j≤kn({\mathcal{F}_{n,j}})_{n>0,0\leq j\leq k_{n}}, i.e. for all n>0n>0 and 1≤j≤kn1\leq j\leq k_{n}, ηn,j\eta_{n,j} is ℱn,j{\mathcal{F}_{n,j}}-measurable and 𝔼⁡[ηn,j|ℱn,j−1]=0\mathbb{E}\left[\eta_{n,j}\middle|{\mathcal{F}_{n,j-1}}\right]=0. Let σ2>0\sigma^{2}>0 such that,

∑j=1kn𝔼⁡[ηn,j2|ℱn,j−1]​⟶n→∞ℙ​σ2.\displaystyle\sum_{j=1}^{k_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\middle|{\mathcal{F}_{n,j-1}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\sigma^{2}.\addcontentsline{lla}{section}{\numberline q:thm_{t}echnical_{c}onditional_{d}conv_{1}} (A.4)

Moreover assume that for all ε>0\varepsilon>0,

∑j=1kn𝔼⁡[ηn,j2​𝟙|ηn,j|>ε|ℱn,j−1]​⟶n→∞ℙ​0.\sum_{j=1}^{k_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\mathbbm{1}_{|\eta_{n,j}|>\varepsilon}\middle|{\mathcal{F}_{n,j-1}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.\addcontentsline{lla}{section}{\numberline q:thm_{t}echnical_{c}onditional_{d}conv_{2}} (A.5)

Then for all t∈ℝt\in\mathbb{R}, on has,

∏j=1kn𝔼⁡[ei​t​ηn,j|ℱn,j−1]​⟶n→∞ℙ​e−12​t2​σ2.\prod_{j=1}^{k_{n}}\mathbb{E}\left[e^{it\eta_{n,j}}\middle|{\mathcal{F}_{n,j-1}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}e^{-\frac{1}{2}t^{2}\sigma^{2}}. (A.6)
Proof.

Define the functions A:ℝ→ℂA:\mathbb{R}\rightarrow\mathbb{C} and B:ℝ→ℝB:\mathbb{R}\rightarrow\mathbb{R} such that for all x∈ℝx\in\mathbb{R}

ei​t​x=1+i​t​x−12​x2+12​x2​A​(x)andB⁡(x)=min⁡(x/3,2).e^{itx}=1+itx-\frac{1}{2}x^{2}+\frac{1}{2}x^{2}A(x)\quad\text{and}\quad B(x)=\min(x/3,2).

And note that, from (13, Lemma 1, p.512), |A⁡(x)|≤B⁡(|x|)|A(x)|\leq B(|x|) for all x∈ℝx\in\mathbb{R}. Letting σn,j2​=def​𝔼​[ηn,j2|ℱn,j−1]\sigma_{n,j}^{2}\overset{\mathrm{def}}{=}\mathbb{E}\left[\eta_{n,j}^{2}\middle|{\mathcal{F}_{n,j-1}}\right] and σn2​=def​∑j=1knσn,j2\sigma_{n}^{2}\overset{\mathrm{def}}{=}\sum_{j=1}^{k_{n}}\sigma_{n,j}^{2}, one has

𝔼⁡[ei​t​ηn,j|ℱn,j−1]=1−12​t2​σn,j2+12​t2​𝔼​[ηn,j2​A​(t​ηn,j)|ℱn,j−1].\mathbb{E}\left[e^{it\eta_{n,j}}\middle|{\mathcal{F}_{n,j-1}}\right]=1-\frac{1}{2}t^{2}\sigma_{n,j}^{2}+\frac{1}{2}t^{2}\mathbb{E}\left[\eta_{n,j}^{2}A(t\eta_{n,j})\middle|{\mathcal{F}_{n,j-1}}\right].

Now define rnr_{n} by

log⁡(∏j=1kn𝔼⁡[ei​t​ηn,j|ℱn,j−1])\displaystyle\log\left(\prod_{j=1}^{k_{n}}\mathbb{E}\left[e^{it\eta_{n,j}}\middle|{\mathcal{F}_{n,j-1}}\right]\right) =∑j=1knlog⁡(1−12​t2​σn,j2+12​t2​𝔼​[ηn,j2​A​(t​ηn,j)|ℱn,j−1])\displaystyle=\sum_{j=1}^{k_{n}}\log\left(1-\frac{1}{2}t^{2}\sigma_{n,j}^{2}+\frac{1}{2}t^{2}\mathbb{E}\left[\eta_{n,j}^{2}A(t\eta_{n,j})\middle|{\mathcal{F}_{n,j-1}}\right]\right)
=−12​t2​σn2+12​t2​∑j=1kn𝔼⁡[ηn,j2​A​(t​ηn,j)|ℱn,j−1]+rn.\displaystyle=-\frac{1}{2}t^{2}\sigma_{n}^{2}+\frac{1}{2}t^{2}\sum_{j=1}^{k_{n}}\mathbb{E}\left[\eta_{n,j}^{2}A(t\eta_{n,j})\middle|{\mathcal{F}_{n,j-1}}\right]+r_{n}. (A.7)

As σn​⟶n→∞ℙ​σ2\sigma_{n}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\sigma^{2} by (A.4), it now suffices to show that rn​⟶n→∞ℙ​0r_{n}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0, then that the second term of (A.7) tends to 0 in probability as well. Regarding the first point, denote zn,j​=def−12​t2​σn,j2+12​t2​𝔼​[ηn,j2​A​(t​ηn,j)|ℱn,j−1]z_{n,j}\overset{\mathrm{def}}{=}-\frac{1}{2}t^{2}\sigma_{n,j}^{2}+\frac{1}{2}t^{2}\mathbb{E}\left[\eta_{n,j}^{2}A(t\eta_{n,j})\middle|{\mathcal{F}_{n,j-1}}\right] for n>0n>0 and 1≤j≤kn1\leq j\leq k_{n}, one has that

|zn,j|\displaystyle\left|z_{n,j}\right| ≤12​t2​(σn,j2+𝔼⁡[ηn,j2​|A⁡(t​ηn,j)||ℱn,j−1])\displaystyle\leq\frac{1}{2}t^{2}\left(\sigma_{n,j}^{2}+\mathbb{E}\left[\eta_{n,j}^{2}|A(t\eta_{n,j})|\middle|{\mathcal{F}_{n,j-1}}\right]\right)
≤12​t2​(σn,j2+𝔼⁡[ηn,j2​B​(|t​ηn,j|)|ℱn,j−1])\displaystyle\leq\frac{1}{2}t^{2}\left(\sigma_{n,j}^{2}+\mathbb{E}\left[\eta_{n,j}^{2}B(|t\eta_{n,j}|)\middle|{\mathcal{F}_{n,j-1}}\right]\right)
≤32​t2​σn,j2.\displaystyle\leq\frac{3}{2}t^{2}\sigma_{n,j}^{2}.

Moreover, for |z|<1|z|<1 one has (17, p. 72)

|log⁡(1+z)−z|≤|z|22​(1−|z|),|\mathrm{log}(1+z)-z|\leq\frac{|z|^{2}}{2(1-|z|)},

thus

|rn|\displaystyle|r_{n}| ≤∑j=1kn|log⁡(1+zn,j)−zn,j|\displaystyle\leq\sum_{j=1}^{k_{n}}|\log(1+z_{n,j})-z_{n,j}|
≤12∑j=1kn(32​t2​σn,j2)21−32​t2​σn,j2𝟙{|zn,j|<1}+∑j=1kn|log(1+zn,j)−zn,j|𝟙{|zn,j|≥1}\displaystyle\leq\frac{1}{2}\sum_{j=1}^{k_{n}}\frac{(\frac{3}{2}t^{2}\sigma_{n,j}^{2})^{2}}{1-\frac{3}{2}t^{2}\sigma_{n,j}^{2}}\mathbbm{1}_{\{|z_{n,j}|<1\}}+\sum_{j=1}^{k_{n}}|\log(1+z_{n,j})-z_{n,j}|\mathbbm{1}_{\{|z_{n,j}|\geq 1\}}
≤σn29​t28σ~n21−32​t4​σ~n2+𝟙{σ~n2≥23​t2}∑j=1kn|log(1+zn,j)−zn,j|,\displaystyle\leq\sigma_{n}^{2}\frac{9t^{2}}{8}\frac{\tilde{\sigma}_{n}^{2}}{1-\frac{3}{2}t^{4}\tilde{\sigma}_{n}^{2}}+\mathbbm{1}_{\left\{\tilde{\sigma}_{n}^{2}\geq\frac{2}{3t^{2}}\right\}}\sum_{j=1}^{k_{n}}|\log(1+z_{n,j})-z_{n,j}|, (A.8)

where σ~n2​=def​max1≤j≤kn​σn,j2\tilde{\sigma}_{n}^{2}\overset{\mathrm{def}}{=}\max_{1\leq j\leq k_{n}}\sigma_{n,j}^{2}. Let γ>0\gamma>0, for each 1≤j≤kn1\leq j\leq k_{n}

σn,j2≤γ2+𝔼[ηn,j2𝟙{|ηn,j|>γ}|ℱn,j],\sigma_{n,j}^{2}\leq\gamma^{2}+\mathbb{E}\left[\eta_{n,j}^{2}\mathbbm{1}_{\{|\eta_{n,j}|>\gamma\}}\middle|{\mathcal{F}_{n,j}}\right],

thus, with (A.5), one has

σ~n\displaystyle\tilde{\sigma}_{n} ≤γ2+max1≤j≤kn𝔼[ηn,j2𝟙{|ηn,j|>γ}|ℱn,j]\displaystyle\leq\gamma^{2}+\max_{1\leq j\leq k_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\mathbbm{1}_{\{|\eta_{n,j}|>\gamma\}}\middle|{\mathcal{F}_{n,j}}\right]
≤γ2+∑j=1kn𝔼[ηn,j2𝟙{|ηn,j|>γ}|ℱn,j]⟶n→∞ℙγ2.\displaystyle\leq\gamma^{2}+\sum_{j=1}^{k_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\mathbbm{1}_{\{|\eta_{n,j}|>\gamma\}}\middle|{\mathcal{F}_{n,j}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\gamma^{2}.

Therefore σ~n2​⟶n→∞ℙ​0\tilde{\sigma}_{n}^{2}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0, by application of Lemma A.5. Thus, the first term of the right hand side of (A.8) tends to 0 in probability and the second term as well by Lemma A.6.

Regarding the second point, let ε>0\varepsilon>0 and observe that

|∑j=1kn𝔼⁡[ηn,j2​A​(t​ηn,j)|ℱn,j−1]|\displaystyle\left|\sum_{j=1}^{k_{n}}\mathbb{E}\left[\eta_{n,j}^{2}A(t\eta_{n,j})\middle|{\mathcal{F}_{n,j-1}}\right]\right| ≤∑j=1kn𝔼⁡[ηn,j2​|A⁡(t​ηn,j)||ℱn,j−1]\displaystyle\leq\sum_{j=1}^{k_{n}}\mathbb{E}\left[\eta_{n,j}^{2}|A(t\eta_{n,j})|\middle|{\mathcal{F}_{n,j-1}}\right]
≤∑j=1kn𝔼[ηn,j2B(|tηn,j|)(𝟙{|tηn,j|≤ε}+𝟙{|tηn,j|>ε})|ℱn,j−1]\displaystyle\leq\sum_{j=1}^{k_{n}}\mathbb{E}\left[\eta_{n,j}^{2}B(|t\eta_{n,j}|)(\mathbbm{1}_{\{|t\eta_{n,j}|\leq\varepsilon\}}+\mathbbm{1}_{\{|t\eta_{n,j}|>\varepsilon\}})\middle|{\mathcal{F}_{n,j-1}}\right]
≤ε3σn2+2∑j=1kn𝔼[ηn,j2𝟙{|tηn,j|>ε}|𝒟n]⟶n→∞ℙε3σ2,\displaystyle\leq\frac{\varepsilon}{3}\sigma_{n}^{2}+2\sum_{j=1}^{k_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\mathbbm{1}_{\{|t\eta_{n,j}|>\varepsilon\}}\middle|{\mathcal{D}_{n}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\frac{\varepsilon}{3}\sigma^{2},

by (A.4) and (A.5). Thus, by application of Lemma A.5

∑j=1kn𝔼⁡[ηn,j2​A​(t​ηn,j)|ℱn,j−1]​⟶n→∞ℙ​0.\sum_{j=1}^{k_{n}}\mathbb{E}\left[\eta_{n,j}^{2}A(t\eta_{n,j})\middle|{\mathcal{F}_{n,j-1}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.

Whence, ∏j=1kn𝔼⁡[ei​t​ηn,j|ℱn,j−1]​⟶n→∞ℙ​exp⁡(−12​t2​σ2)\prod_{j=1}^{k_{n}}\mathbb{E}\left[e^{it\eta_{n,j}}\middle|{\mathcal{F}_{n,j-1}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\exp\left(-\frac{1}{2}t^{2}\sigma^{2}\right) for all t∈ℝt\in\mathbb{R}. ∎

Lemma A.8.

Let (An)n∈ℕ(A_{n})_{n\in\mathbb{N}} and (Bn)n∈ℕ(B_{n})_{n\in\mathbb{N}} two asymptotically finite dimensional random variable sequences in ℍ\mathbb{H} and (an)n∈ℕ(a_{n})_{n\in\mathbb{N}} a real non-zero sequence that converges to a∈ℝa\in\mathbb{R}. Then (an​An+Bn)n∈ℕ(a_{n}A_{n}+B_{n})_{n\in\mathbb{N}} is asymptotically finite dimensional as well.

Proof.

By definition, for all ε,δ>0\varepsilon,\delta>0, there exists Ja,Jb∈ℕJ_{a},J_{b}\in\mathbb{N} such that

lim supn∈ℕℙ⁡(∑j>Ja⟨An,ej⟩ℍ2≥ε4​(a2+1))<δ2,\limsup_{n\in\mathbb{N}}\mathbb{P}\left(\sum_{j>J_{a}}\langle A_{n},e_{j}\rangle_{\mathbb{H}}^{2}\geq\frac{\varepsilon}{4(a^{2}+1)}\right)<\frac{\delta}{2},

and

lim supn∈ℕℙ⁡(∑j>Jb⟨Bn,ej⟩ℍ2≥ε4)<δ2.\limsup_{n\in\mathbb{N}}\mathbb{P}\left(\sum_{j>J_{b}}\langle B_{n},e_{j}\rangle_{\mathbb{H}}^{2}\geq\frac{\varepsilon}{4}\right)<\frac{\delta}{2}.

Denote J​=def​max⁡(Ja,Jb)J\overset{\mathrm{def}}{=}\max(J_{a},J_{b}). Using the inequality (a+b)2≤2​(a2+b2)(a+b)^{2}\leq 2(a^{2}+b^{2}), one has

ℙ⁡(∑j>J⟨an​An+Bn,ej⟩ℍ2≥ε)\displaystyle\mathbb{P}\left(\sum_{j>J}\langle a_{n}A_{n}+B_{n},e_{j}\rangle_{\mathbb{H}}^{2}\geq\varepsilon\right)
≤ℙ⁡(∑j>J⟨an​An,ej⟩ℍ2+∑j>J⟨Bn,ej⟩ℍ2≥ε2)\displaystyle\qquad\leq\mathbb{P}\left(\sum_{j>J}\langle a_{n}A_{n},e_{j}\rangle_{\mathbb{H}}^{2}+\sum_{j>J}\langle B_{n},e_{j}\rangle_{\mathbb{H}}^{2}\geq\frac{\varepsilon}{2}\right)
≤ℙ⁡(∑j>J⟨An,ej⟩ℍ2≥ε4​an2)+ℙ⁡(∑j>J⟨Bn,ej⟩ℍ2≥ε4)\displaystyle\qquad\leq\mathbb{P}\left(\sum_{j>J}\langle A_{n},e_{j}\rangle_{\mathbb{H}}^{2}\geq\frac{\varepsilon}{4a_{n}^{2}}\right)+\mathbb{P}\left(\sum_{j>J}\langle B_{n},e_{j}\rangle_{\mathbb{H}}^{2}\geq\frac{\varepsilon}{4}\right)
≤ℙ⁡(∑j>Ja⟨An,ej⟩ℍ2≥ε4​an2)+ℙ⁡(∑j>Jb⟨Bn,ej⟩ℍ2≥ε4).\displaystyle\qquad\leq\mathbb{P}\left(\sum_{j>J_{a}}\langle A_{n},e_{j}\rangle_{\mathbb{H}}^{2}\geq\frac{\varepsilon}{4a_{n}^{2}}\right)+\mathbb{P}\left(\sum_{j>J_{b}}\langle B_{n},e_{j}\rangle_{\mathbb{H}}^{2}\geq\frac{\varepsilon}{4}\right).

Moreover, there exists N∈ℕN\in\mathbb{N} such that for all n≥Nn\geq N, an2≤a2+1a_{n}^{2}\leq a^{2}+1. Therefore

ℙ⁡(∑j>Ja⟨An,ej⟩ℍ2≥ε4​an2)≤ℙ⁡(∑j>Ja⟨An,ej⟩ℍ2≥ε4​(a2+1)).\mathbb{P}\left(\sum_{j>J_{a}}\langle A_{n},e_{j}\rangle_{\mathbb{H}}^{2}\geq\frac{\varepsilon}{4a_{n}^{2}}\right)\leq\mathbb{P}\left(\sum_{j>J_{a}}\langle A_{n},e_{j}\rangle_{\mathbb{H}}^{2}\geq\frac{\varepsilon}{4(a^{2}+1)}\right).

As a consequence, by subadditivity of the lim sup\limsup,

lim supn∈ℕℙ⁡(∑j>J⟨an​An+Bn,ej⟩ℍ2≥ε)≤δ2+δ2=δ,\limsup_{n\in\mathbb{N}}\mathbb{P}\left(\sum_{j>J}\langle a_{n}A_{n}+B_{n},e_{j}\rangle_{\mathbb{H}}^{2}\geq\varepsilon\right)\leq\frac{\delta}{2}+\frac{\delta}{2}=\delta,

and (an​An+Bn)n∈ℕ(a_{n}A_{n}+B_{n})_{n\in\mathbb{N}} is asymptotically finite dimensional. ∎

Let us consider the two following subsampling strategies, where γn,i\gamma_{n,i} refers to the multiplicity (or the number of occurrences) of each point ZiZ_{i} in the subsampled dataset (which may be null if ZiZ_{i} is not picked).

Subsampling with replacement

One draws independently sns_{n} point indices:

In,1,…,In,sn|𝒟n​∼i.i.d.​∑i=1nπn,i​δ{i},I_{n,1},\dots,I_{n,s_{n}}|{\mathcal{D}_{n}}\overset{{{}}{i.i.d.}}{\sim}\sum_{i=1}^{n}\pi_{n,i}\delta_{\{i\}},

where δ{i}\delta_{\{i\}} is the Dirac measure at ii. Each point ZiZ_{i} appears Nn,i=defγn,i=∑j=1sn𝟙{In,j=i}N_{n,i}\overset{\mathrm{def}}{=}\gamma_{n,i}=\sum_{j=1}^{s_{n}}\mathbbm{1}_{\{I_{n,j}=i\}} times in the subsampled dataset

Subsampling without replacement

Assuming that πn,i≤sn−1\pi_{n,i}\leq s_{n}^{-1} for all n>0n>0 and i∈{1,…,n}i\in\{1,\dots,n\}, ones draws independently for each point ZiZ_{i}

γn,i|𝒟n∼Ber​(sn​πn,i),\gamma_{n,i}|{\mathcal{D}_{n}}\sim\text{Ber}(s_{n}\pi_{n,i}),

and decides that it should enter the subsampled dataset when the inclusion indicator verifies δn,i​=def​γn,i=1\delta_{n,i}\overset{\mathrm{def}}{=}\gamma_{n,i}=1.

The following proposition is a weak law of large numbers for Multinomial and Poisson subsampling. It is written with an a general Hilbert space EE with the aim of applying it with either the reals ℝ\mathbb{R} and the regular product or the RKHS of study ℍ\mathbb{H} and its scalar product ⟨⋅,⋅⟩ℍ\langle\cdot,\cdot\rangle_{\mathbb{H}}.

Proposition A.9 (Subsampling LLN).

Let (E,⟨⋅,⋅⟩E)(E,\langle\cdot,\cdot\rangle_{E}) be a Hilbert space and ff a function from 𝒵\mathcal{Z} to EE such that 𝔼⁡[‖f⁡(Z)‖E4]<∞\mathbb{E}\left[\|f(Z)\|_{E}^{4}\right]<\infty. Then, if (𝛑n)n>0({\bm{\pi}}_{n})_{n>0} verifies Assumption 5, one has,

1n​∑j=1snf⁡(Zi)sn​πn,i​γn,i​⟶n→∞ℙ​𝔼​f​(Z),\frac{1}{n}\sum_{j=1}^{s_{n}}\frac{f(Z_{i})}{s_{n}\pi_{n,i}}\gamma_{n,i}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}f(Z),

whether γn,i=Nn,i\gamma_{n,i}=N_{n,i}, in the case of Multinomial subsampling, or γn,i=δn,i\gamma_{n,i}=\delta_{n,i}, in the case of Poisson subsampling.

Moreover, if it is assumed that sn=O⁡(n)s_{n}=O(n) then,

‖1n∑j=1snf⁡(Zi)sn​πn,iγn,i−𝔼f(Z)‖E=Oℙ(sn−1/2).\left\|\frac{1}{n}\sum_{j=1}^{s_{n}}\frac{f(Z_{i})}{s_{n}\pi_{n,i}}\gamma_{n,i}-\mathbb{E}f(Z)\right\|_{E}=O_{\mathbb{P}}(s_{n}^{-1/2}).

By construction, in Poisson subsampling, sn≤ns_{n}\leq n hence sn=O⁡(n)s_{n}=O(n). In the case of (Multinomial) subsampling, the goal is to reduce the effective dataset size. Hence one would largely want sn=O⁡(n)s_{n}=O(n) and the second point of the above proposition always holds in this context.

Proof.

To simplify the notation, first define

P​f​=def​𝔼​f​(Z),\displaystyle Pf\overset{\mathrm{def}}{=}\mathbb{E}f(Z),
Pn​f​=def​1n​∑i=1nf⁡(Zi),\displaystyle P_{n}f\overset{\mathrm{def}}{=}\frac{1}{n}\sum_{i=1}^{n}f(Z_{i}),
Psn∗​f​=def​1n​∑j=1snf⁡(Zi)sn​πn,i​γn,i,\displaystyle P_{s_{n}}^{*}f\overset{\mathrm{def}}{=}\frac{1}{n}\sum_{j=1}^{s_{n}}\frac{f(Z_{i})}{s_{n}\pi_{n,i}}\gamma_{n,i},

and recall that Pn​f​⟶n→∞ℙ​P​fP_{n}f\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}Pf by the usual weak law of large numbers. By the tower property one has

𝔼⁡[Psn∗​f]=1n​∑i=1n𝔼⁡[f⁡(Zi)sn​πn,i​𝔼​[γn,i|𝒟n]]=1n​∑i=1n𝔼​f​(Zi)=P​f,\mathbb{E}\left[P_{s_{n}}^{*}f\right]=\frac{1}{n}\sum_{i=1}^{n}\mathbb{E}\left[\frac{f(Z_{i})}{s_{n}\pi_{n,i}}\mathbb{E}\left[\gamma_{n,i}\middle|{\mathcal{D}_{n}}\right]\right]=\frac{1}{n}\sum_{i=1}^{n}\mathbb{E}f(Z_{i})=Pf,

so 𝔼⁡[‖Psn∗​f−P​f‖E2]=𝔼⁡[‖Psn∗​f‖E2]−‖P​f‖E2\mathbb{E}\left[\|P_{s_{n}}^{*}f-Pf\|_{E}^{2}\right]=\mathbb{E}\left[\|P_{s_{n}}^{*}f\|_{E}^{2}\right]-\|Pf\|_{E}^{2}. Let us now show that for all i,k∈{1,…,n}i,k\in\{1,\dots,n\},

𝔼⁡[γn,i​γn,k|𝒟n]≤sn​πn,i​𝟙i=k+sn2​πn,i​πn,k,\addcontentsline{lla}{section}{\numberline q:prop_{w}lln_{R}{}_{p}art1}\mathbb{E}\left[\gamma_{n,i}\gamma_{n,k}\middle|{\mathcal{D}_{n}}\right]\leq s_{n}\pi_{n,i}\mathbbm{1}_{i=k}+s_{n}^{2}\pi_{n,i}\pi_{n,k}, (A.9)

for Multinomial and Poisson subsampling. On the one hand,

𝔼⁡[Nn,i​Nn,k|𝒟n]\displaystyle\mathbb{E}\left[N_{n,i}N_{n,k}\middle|{\mathcal{D}_{n}}\right] =𝔼⁡[∑j,m=1sn𝟙{In,j=i}​𝟙{In,m=k}|𝒟n]\displaystyle=\mathbb{E}\left[\sum_{j,m=1}^{s_{n}}\mathbbm{1}_{\{I_{n,j=i}\}}\mathbbm{1}_{\{I_{n,m=k}\}}\middle|{\mathcal{D}_{n}}\right]
=∑j,m=1snℙ(In,j=i,In,m=k|𝒟n)\displaystyle=\sum_{j,m=1}^{s_{n}}\mathbb{P}\left(I_{n,j=i},I_{n,m=k}\middle|{\mathcal{D}_{n}}\right)
=∑j=1snℙ(In,j=i,In,j=k|𝒟n)+∑j≠msnℙ(In,j=i|𝒟n)ℙ(In,m=k|𝒟n)\displaystyle=\sum_{j=1}^{s_{n}}\mathbb{P}\left(I_{n,j=i},I_{n,j=k}\middle|{\mathcal{D}_{n}}\right)+\sum_{j\neq m}^{s_{n}}\mathbb{P}\left(I_{n,j=i}\middle|{\mathcal{D}_{n}}\right)\mathbb{P}\left(I_{n,m=k}\middle|{\mathcal{D}_{n}}\right)
=sn​πn,i​𝟙i=k+sn​(sn−1)​πn,i​πn,k\displaystyle=s_{n}\pi_{n,i}\mathbbm{1}_{i=k}+s_{n}(s_{n}-1)\pi_{n,i}\pi_{n,k}
≤sn​πn,i​𝟙i=k+sn2​πn,i​πn,k.\displaystyle\leq s_{n}\pi_{n,i}\mathbbm{1}_{i=k}+s_{n}^{2}\pi_{n,i}\pi_{n,k}.

On the other hand,

𝔼⁡[δn,i​δn,k|𝒟n]\displaystyle\mathbb{E}\left[\delta_{n,i}\delta_{n,k}\middle|{\mathcal{D}_{n}}\right] =𝔼⁡[δn,i|𝒟n]​𝟙i=k+𝔼⁡[δn,i|𝒟n]​𝔼​[δn,k|𝒟n]​𝟙i≠k\displaystyle=\mathbb{E}\left[\delta_{n,i}\middle|{\mathcal{D}_{n}}\right]\mathbbm{1}_{i=k}+\mathbb{E}\left[\delta_{n,i}\middle|{\mathcal{D}_{n}}\right]\mathbb{E}\left[\delta_{n,k}\middle|{\mathcal{D}_{n}}\right]\mathbbm{1}_{i\neq k}
=sn​πn,i​𝟙i=k+sn2​πn,i​πn,k​𝟙i≠k\displaystyle=s_{n}\pi_{n,i}\mathbbm{1}_{i=k}+s_{n}^{2}\pi_{n,i}\pi_{n,k}\mathbbm{1}_{i\neq k}
≤sn​πn,i​𝟙i=k+sn2​πn,i​πn,k.\displaystyle\leq s_{n}\pi_{n,i}\mathbbm{1}_{i=k}+s_{n}^{2}\pi_{n,i}\pi_{n,k}.

Hence

𝔼⁡[‖Psn∗​f‖E2|𝒟n]\displaystyle\mathbb{E}\left[\|P_{s_{n}}^{*}f\|_{E}^{2}\middle|{\mathcal{D}_{n}}\right] =1n2​sn2​∑i,k=1n⟨f⁡(Zi),f⁡(Zk)⟩Eπn,i​πn,k​𝔼​[γn,i​γn,k|𝒟n]\displaystyle=\frac{1}{n^{2}s_{n}^{2}}\sum_{i,k=1}^{n}\frac{\langle f(Z_{i}),f(Z_{k})\rangle_{E}}{\pi_{n,i}\pi_{n,k}}\mathbb{E}\left[\gamma_{n,i}\gamma_{n,k}\middle|{\mathcal{D}_{n}}\right]
≤1sn​n2​∑i=1n‖f⁡(Zi)‖E2πn,i+1n2​∑i,k=1n⟨f⁡(Zi),f⁡(Zk)⟩E\displaystyle\leq\frac{1}{s_{n}n^{2}}\sum_{i=1}^{n}\frac{\|f(Z_{i})\|_{E}^{2}}{\pi_{n,i}}+\frac{1}{n^{2}}\sum_{i,k=1}^{n}\langle f(Z_{i}),f(Z_{k})\rangle_{E}
=1sn​n2​∑i=1n‖f⁡(Zi)‖E2πn,i+‖Pn​f‖E2.\displaystyle=\frac{1}{s_{n}n^{2}}\sum_{i=1}^{n}\frac{\|f(Z_{i})\|_{E}^{2}}{\pi_{n,i}}+\|P_{n}f\|_{E}^{2}.

On the one hand, by Cauchy-Schwarz,

𝔼⁡[1n2​∑i=1n‖f⁡(Zi)‖E2πn,i]\displaystyle\mathbb{E}\left[\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\|f(Z_{i})\|_{E}^{2}}{\pi_{n,i}}\right] ≤𝔼⁡[max1≤i≤n⁡{1n​πn,i}2]​𝔼⁡[(1n​∑i=1n‖f⁡(Zi)‖E2)2].\displaystyle\leq\sqrt{\mathbb{E}\left[\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{2}\right]}\sqrt{\mathbb{E}\left[\left(\frac{1}{n}\sum_{i=1}^{n}\|f(Z_{i})\|_{E}^{2}\right)^{2}\right]}.

However,

𝔼⁡[max1≤i≤n⁡{1n​πn,i}2]=O⁡(1),\mathbb{E}\left[\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{2}\right]=O(1),

and,

𝔼⁡[(1n​∑i=1n‖f⁡(Zi)‖E2)2]\displaystyle\mathbb{E}\left[\left(\frac{1}{n}\sum_{i=1}^{n}\|f(Z_{i})\|_{E}^{2}\right)^{2}\right] =1n2​∑i=1n𝔼⁡[‖f⁡(Zi)‖E4]+1n2​∑i≠j𝔼⁡[‖f⁡(Zi)‖E2​‖f⁡(Zj)‖E2]\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\mathbb{E}\left[\|f(Z_{i})\|_{E}^{4}\right]+\frac{1}{n^{2}}\sum_{i\neq j}\mathbb{E}\left[\|f(Z_{i})\|_{E}^{2}\|f(Z_{j})\|_{E}^{2}\right]
=1n​𝔼​[‖f⁡(Z1)‖E4]+n⁡(n−1)n2​𝔼​[‖f⁡(Z1)‖E2]2=O⁡(1).\displaystyle=\frac{1}{n}\mathbb{E}\left[\|f(Z_{1})\|_{E}^{4}\right]+\frac{n(n-1)}{n^{2}}\mathbb{E}\left[\|f(Z_{1})\|_{E}^{2}\right]^{2}=O(1).

Hence,

𝔼⁡[1sn​n2​∑i=1n‖f⁡(Zi)‖E2πn,i]=O⁡(sn−1).\mathbb{E}\left[\frac{1}{s_{n}n^{2}}\sum_{i=1}^{n}\frac{\|f(Z_{i})\|_{E}^{2}}{\pi_{n,i}}\right]=O(s_{n}^{-1}).

On the other hand, by independence of the observations Z1,…,ZnZ_{1},\dots,Z_{n},

𝔼⁡[‖Pn​f‖E2]\displaystyle\mathbb{E}\left[\|P_{n}f\|_{E}^{2}\right] =1n2​∑i,m=1n𝔼⁡[⟨f⁡(Zi),f⁡(Zm)⟩E]\displaystyle=\frac{1}{n^{2}}\sum_{i,m=1}^{n}\mathbb{E}\left[\langle f(Z_{i}),f(Z_{m})\rangle_{E}\right]
=1n2​∑i=1n𝔼⁡[‖f⁡(Zi)‖E2]+1n2​∑i≠mn𝔼⁡[⟨f⁡(Zi),f⁡(Zm)⟩E]\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\mathbb{E}\left[\|f(Z_{i})\|_{E}^{2}\right]+\frac{1}{n^{2}}\sum_{i\neq m}^{n}\mathbb{E}\left[\langle f(Z_{i}),f(Z_{m})\rangle_{E}\right]
=1n​𝔼​[‖f⁡(Z)‖E2]+n⁡(n−1)n2​‖P​f‖E2.\displaystyle=\frac{1}{n}\mathbb{E}\left[\|f(Z)\|_{E}^{2}\right]+\frac{n(n-1)}{n^{2}}\|Pf\|_{E}^{2}.

Thus,

𝔼⁡[‖Psn∗​f‖E2]\displaystyle\mathbb{E}\left[\|P_{s_{n}}^{*}f\|_{E}^{2}\right] ≤𝔼⁡[1sn​n2​∑i=1n‖f⁡(Zi)‖E2πn,i]+1n​𝔼​[‖f⁡(Z)‖E2]+n−1n​‖P​f‖E2\displaystyle\leq\mathbb{E}\left[\frac{1}{s_{n}n^{2}}\sum_{i=1}^{n}\frac{\|f(Z_{i})\|_{E}^{2}}{\pi_{n,i}}\right]+\frac{1}{n}\mathbb{E}\left[\|f(Z)\|_{E}^{2}\right]+\frac{n-1}{n}\|Pf\|_{E}^{2}
≤𝔼⁡[1sn​n2​∑i=1n‖f⁡(Zi)‖E2πn,i]+1n​𝔼​[‖f⁡(Z)‖E2]+‖P​f‖E2,\displaystyle\leq\mathbb{E}\left[\frac{1}{s_{n}n^{2}}\sum_{i=1}^{n}\frac{\|f(Z_{i})\|_{E}^{2}}{\pi_{n,i}}\right]+\frac{1}{n}\mathbb{E}\left[\|f(Z)\|_{E}^{2}\right]+\|Pf\|_{E}^{2},

and

𝔼⁡[‖Psn∗​f‖E2]−‖P​f‖E2\displaystyle\mathbb{E}\left[\|P_{s_{n}}^{*}f\|_{E}^{2}\right]-\|Pf\|_{E}^{2} ≤𝔼⁡[1sn​n2​∑i=1n‖f⁡(Zi)‖E2πn,i]+1n​𝔼​[‖f⁡(Z)‖E2]\displaystyle\leq\mathbb{E}\left[\frac{1}{s_{n}n^{2}}\sum_{i=1}^{n}\frac{\|f(Z_{i})\|_{E}^{2}}{\pi_{n,i}}\right]+\frac{1}{n}\mathbb{E}\left[\|f(Z)\|_{E}^{2}\right]
=O⁡(sn−1)+O⁡(n−1)​⟶n→∞​0.\displaystyle=O(s_{n}^{-1})+O(n^{-1})\underset{n\rightarrow\infty}{\longrightarrow}0. (A.10)

Finally, by Chebyshev’s inequality, for all ε>0\varepsilon>0,

ℙ⁡(‖Psn∗​f−P​f‖E≥ε)\displaystyle\mathbb{P}\left(\|P_{s_{n}}^{*}f-Pf\|_{E}\geq\varepsilon\right) ≤1ε2​𝔼​[‖Psn∗​f−P​f‖E2]\displaystyle\leq\frac{1}{\varepsilon^{2}}\mathbb{E}\left[\|P_{s_{n}}^{*}f-Pf\|_{E}^{2}\right]
=1ε2​(𝔼⁡[‖Psn∗​f‖E2]−‖P​f‖E2)​⟶n→∞​0,\displaystyle=\frac{1}{\varepsilon^{2}}\left(\mathbb{E}\left[\|P_{s_{n}}^{*}f\|_{E}^{2}\right]-\|Pf\|_{E}^{2}\right)\underset{n\rightarrow\infty}{\longrightarrow}0,

whence Psn∗​f​⟶n→∞ℙ​P​fP_{s_{n}}^{*}f\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}Pf.

Assume now that sn=O⁡(n)s_{n}=O(n). From (A.10) one has

sn​(𝔼⁡[‖Psn∗​f‖E2]−‖P​f‖E2)\displaystyle s_{n}(\mathbb{E}\left[\|P_{s_{n}}^{*}f\|_{E}^{2}\right]-\|Pf\|_{E}^{2}) =sn​(O⁡(sn−1)+O⁡(n−1))=O⁡(1).\displaystyle=s_{n}(O(s_{n}^{-1})+O(n^{-1}))=O(1).

Whence, there exists M>0M>0 and N∈ℕN\in\mathbb{N} such that for n≥Nn\geq N,

sn​(𝔼⁡[‖Psn∗​f‖E2]−‖P​f‖E2)≤M2.\displaystyle s_{n}(\mathbb{E}\left[\|P_{s_{n}}^{*}f\|_{E}^{2}\right]-\|Pf\|_{E}^{2})\leq M^{2}.

Finally, by Chebyshev’s inequality, for all ε>0\varepsilon>0,

ℙ(sn∥Psn∗f−Pf∥E≥Mε−1/2)\displaystyle\mathbb{P}\left(\sqrt{s_{n}}\|P_{s_{n}}^{*}f-Pf\|_{E}\geq M\varepsilon^{-1/2}\right) ≤ε​snM2​𝔼​[‖Psn∗​f−P​f‖E2]\displaystyle\leq\varepsilon\frac{s_{n}}{M^{2}}\mathbb{E}\left[\|P_{s_{n}}^{*}f-Pf\|_{E}^{2}\right]
=ε​snM2​(𝔼⁡[‖Psn∗​f‖E2]−‖P​f‖E2)\displaystyle=\varepsilon\frac{s_{n}}{M^{2}}\left(\mathbb{E}\left[\|P_{s_{n}}^{*}f\|_{E}^{2}\right]-\|Pf\|_{E}^{2}\right)
≤ε,\displaystyle\leq\varepsilon,

and therefore ∥Psn∗f−Pf∥E=Oℙ(sn−1/2)\|P_{s_{n}}^{*}f-Pf\|_{E}=O_{\mathbb{P}}(s_{n}^{-1/2}). ∎

We hereby give the proof of Theorem 3.1 that is valid for Poisson and Multinomial subsampling via the law of large numbers proposition above. Also notice that as ‖h^n−h0‖ℍ​⟶n→∞ℙ​0\|{\hat{h}_{n}}-{h_{0}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0 from Theorem A.2, triangle inequality implies that ‖hsn∗−h^n‖ℍ​⟶n→∞ℙ​0\|{h^{*}_{s_{n}}}-{\hat{h}_{n}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0 as well.

Proof of Theorem 3.1.

Following the same steps as for the proof of Theorem A.2 but replacing h^n{\hat{h}_{n}} by hsn∗{h^{*}_{s_{n}}} and Ln{L}_{n} by Lsn∗{L}^{*}_{s_{n}}, it comes that

0≤‖hsn∗−h0‖ℍ≤2λsn∗​‖∇Lsn∗​(h0)−∇L​(h0)‖ℍ+2​|1λsn∗−1λ0|​‖∇L​(h0)‖ℍ.0\leq\|{h^{*}_{s_{n}}}-{h_{0}}\|_{\mathbb{H}}\leq\frac{2}{{\lambda_{s_{n}}^{*}}}\|\nabla{L}^{*}_{s_{n}}({h_{0}})-\nabla L({h_{0}})\|_{\mathbb{H}}+2\left|\frac{1}{{\lambda_{s_{n}}^{*}}}-\frac{1}{{\lambda_{0}}}\right|\|\nabla{L}({h_{0}})\|_{\mathbb{H}}.

with ∇L​(h0)=𝔼⁡[ℓ′​(h0​(X),Y)​KX]\nabla{L}({h_{0}})=\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)K_{X}\right] and

∇Lsn∗​(h0)=1n​∑i=1nγn,i​ℓ′​(h0​(Xi),Yi)sn​πn,i​KXi.\nabla{L}^{*}_{s_{n}}({h_{0}})=\frac{1}{n}\sum_{i=1}^{n}\gamma_{n,i}\frac{\ell^{\prime}({h_{0}}(X_{i}),Y_{i})}{s_{n}\pi_{n,i}}K_{X_{i}}.

By Assumptions 1 and 3, ℓ′​(h0​(X),Y)​KX∈ℍ\ell^{\prime}({h_{0}}(X),Y)K_{X}\in\mathbb{H} has a fourth order moment. Therefore, ‖∇Lsn∗​(h)−∇L​(h)‖ℍ​⟶n→∞ℙ​0\|\nabla{L}^{*}_{s_{n}}(h)-\nabla{L}(h)\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0 by application of Proposition A.9, and eventually ‖hsn∗−h0‖ℍ​⟶n→∞ℙ​0\|{h^{*}_{s_{n}}}-{h_{0}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0 since λsn∗​⟶n→∞ℙ​λ0{\lambda_{s_{n}}^{*}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}{\lambda_{0}} by ’ ‣ Section 3. ∎

The following lemma is valid for Poisson and Multinomial subsampling via the law of large numbers proposition above.

Lemma A.10.

Under Assumptions 1, 2 and 3, ’ ‣ 3 and 5,

sn​∫01∇2ℛsn∗​(h¯n,t)​(hsn∗−h0)​𝑑t−sn​∇2ℛ​(h0)​(hsn∗−h0)​⟶n→∞ℙ​0,\sqrt{s_{n}}\int_{0}^{1}\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}(\bar{h}_{n,t})({h^{*}_{s_{n}}}-{h_{0}})\,\mathrm{d}t-\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}})\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0,

with h¯n,t=h0+t⁡(hsn∗−h0)\bar{h}_{n,t}={h_{0}}+t({h^{*}_{s_{n}}}-{h_{0}}) for all t∈[0,1]t\in[0,1], either in the framework of Multinomial or Poisson subsampling.

Proof.

Firstly, from Theorem 3.1 we showed that

‖hsn∗−h0‖ℍ≤2λsn∗​‖∇Lsn∗​(h0)−∇L​(h0)‖ℍ+2​1λ0​λsn∗​|λsn∗−λ0|​‖∇L​(h0)‖ℍ.\|{h^{*}_{s_{n}}}-{h_{0}}\|_{\mathbb{H}}\leq\frac{2}{{\lambda_{s_{n}}^{*}}}\|\nabla{L}^{*}_{s_{n}}({h_{0}})-\nabla L({h_{0}})\|_{\mathbb{H}}+2\frac{1}{{\lambda_{0}}{\lambda_{s_{n}}^{*}}}\left|{\lambda_{s_{n}}^{*}}-{\lambda_{0}}\right|\|\nabla{L}({h_{0}})\|_{\mathbb{H}}.

By the second part of the subsampling law of large numbers Proposition A.9, one has

sn​‖∇Lsn∗​(h0)−∇L​(h0)‖ℍ=Oℙ​(1).\sqrt{s_{n}}\|\nabla{L}^{*}_{s_{n}}({h_{0}})-\nabla L({h_{0}})\|_{\mathbb{H}}=O_{\mathbb{P}}(1).

Moreover, sn​(λsn∗−λ0)​⟶n→∞ℙ​0\sqrt{s_{n}}({\lambda_{s_{n}}^{*}}-{\lambda_{0}})\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0. Therefore, sn​‖hsn∗−h0‖ℍ=Oℙ​(1)\sqrt{s_{n}}\|{h^{*}_{s_{n}}}-{h_{0}}\|_{\mathbb{H}}=O_{\mathbb{P}}(1).

Then, let h∈ℍh\in\mathbb{H}, t∈[0,1]t\in[0,1] and denote h¯n,t=h0+t⁡(hsn∗−h0)\bar{h}_{n,t}={h_{0}}+t({h^{*}_{s_{n}}}-{h_{0}}). By consistency of hsn∗{h^{*}_{s_{n}}}, one has that ‖h¯n,t−h0‖ℍ​⟶n→∞ℙ​0\|\bar{h}_{n,t}-{h_{0}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0. On the one hand, by the expression of ∇2ℛsn∗​(⋅)\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}(\cdot) and triangle inequality one has

sn​|⟨∇2ℛsn∗​(h¯n,t)​(hsn∗−h0),h⟩ℍ−⟨∇2ℛsn∗​(h0)​(hsn∗−h0),h⟩ℍ|\displaystyle\sqrt{s_{n}}|\langle\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}(\bar{h}_{n,t})({h^{*}_{s_{n}}}-{h_{0}}),h\rangle_{\mathbb{H}}-\langle\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}}),h\rangle_{\mathbb{H}}|
≤|snn​∑i=1nℓ′′​(h¯n,t​(Xi),Yi)−ℓ′′​(h0​(Xi),Yi)sn​πn,i​γn,i​⟨KXi⊗KXi​(hsn∗−h0),h⟩ℍ|\displaystyle\leq\left|\frac{\sqrt{s_{n}}}{n}\sum_{i=1}^{n}\frac{\ell^{\prime\prime}(\bar{h}_{n,t}(X_{i}),Y_{i})-\ell^{\prime\prime}({h_{0}}(X_{i}),Y_{i})}{s_{n}\pi_{n,i}}\gamma_{n,i}\langle K_{X_{i}}\otimes K_{X_{i}}({h^{*}_{s_{n}}}-{h_{0}}),h\rangle_{\mathbb{H}}\right|
≤snn​∑i=1n|ℓ′′​(h¯n,t​(Xi),Yi)−ℓ′′​(h0​(Xi),Yi)sn​πn,i​γn,i​⟨hsn∗−h0,KXi⟩ℍ​⟨h,KXi⟩ℍ|.\displaystyle\leq\frac{\sqrt{s_{n}}}{n}\sum_{i=1}^{n}\left|\frac{\ell^{\prime\prime}(\bar{h}_{n,t}(X_{i}),Y_{i})-\ell^{\prime\prime}({h_{0}}(X_{i}),Y_{i})}{s_{n}\pi_{n,i}}\gamma_{n,i}\langle{h^{*}_{s_{n}}}-{h_{0}},K_{X_{i}}\rangle_{\mathbb{H}}\langle h,K_{X_{i}}\rangle_{\mathbb{H}}\right|. (A.11)

Moreover, using Assumption 2 for all i∈{1,…,n}i\in\{1,\dots,n\},

|ℓ′′(h¯n,t(Xi),Yi)−ℓ′′(h0(Xi),Yi)|𝟙{∥h¯n,t−h0∥ℍ<1}\displaystyle|\ell^{\prime\prime}(\bar{h}_{n,t}(X_{i}),Y_{i})-\ell^{\prime\prime}({h_{0}}(X_{i}),Y_{i})|\mathbbm{1}_{\{\|\bar{h}_{n,t}-{h_{0}}\|_{\mathbb{H}}<1\}} ≤ϕ⁡(Yi)​|⟨KXi,h¯n,t−h0⟩ℍ|\displaystyle\leq\phi(Y_{i})|\langle K_{X_{i}},\bar{h}_{n,t}-{h_{0}}\rangle_{\mathbb{H}}|
≤ϕ⁡(Yi)​|⟨KXi,hsn∗−h0⟩ℍ|,\displaystyle\leq\phi(Y_{i})|\langle K_{X_{i}},{h^{*}_{s_{n}}}-{h_{0}}\rangle_{\mathbb{H}}|,

since t∈[0,1]t\in[0,1]. By Cauchy-Schwarz one has

|⟨KXi,hsn∗−h0⟩ℍ|≤‖KXi‖ℍ​‖hsn∗−h0‖ℍ≤κ​‖hsn∗−h0‖ℍ,|\langle K_{X_{i}},{h^{*}_{s_{n}}}-{h_{0}}\rangle_{\mathbb{H}}|\leq\|K_{X_{i}}\|_{\mathbb{H}}\|{h^{*}_{s_{n}}}-{h_{0}}\|_{\mathbb{H}}\leq\kappa\|{h^{*}_{s_{n}}}-{h_{0}}\|_{\mathbb{H}},

and |⟨KXi,h⟩ℍ|≤κ​‖h‖ℍ|\langle K_{X_{i}},h\rangle_{\mathbb{H}}|\leq\kappa\|h\|_{\mathbb{H}}. Furthermore, sn​‖hsn∗−h0‖ℍ​⟶n→∞ℙ​0\sqrt{s_{n}}\|{h^{*}_{s_{n}}}-{h_{0}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0, ‖hsn∗−h0‖ℍ​⟶n→∞ℙ​0\|{h^{*}_{s_{n}}}-{h_{0}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0, and by Assumption 3 ϕ⁡(Z)\phi(Z) has a fourth order moment hence

1n​∑i=1nϕ⁡(Yi)sn​πn,i​γn,i​⟶n→∞ℙ​𝔼​ϕ​(Y),\frac{1}{n}\sum_{i=1}^{n}\frac{\phi(Y_{i})}{s_{n}\pi_{n,i}}\gamma_{n,i}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}\phi(Y),

by application of Proposition A.9. Thus, applying Lemma A.6 with the random variables being (A.11) and the events En={∥h¯n,t−h0∥ℍ≥1}E_{n}=\{\|\bar{h}_{n,t}-{h_{0}}\|_{\mathbb{H}}\geq 1\} one has

sn​∫01|⟨∇2ℛsn∗​(h¯n,t)​(hsn∗−h0),h⟩ℍ−⟨∇2ℛsn∗​(h0)​(hsn∗−h0),h⟩ℍ|​𝑑t\displaystyle\sqrt{s_{n}}\int_{0}^{1}|\langle\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}(\bar{h}_{n,t})({h^{*}_{s_{n}}}-{h_{0}}),h\rangle_{\mathbb{H}}-\langle\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}}),h\rangle_{\mathbb{H}}|\,\mathrm{d}t
≤sn​κ3​‖h‖ℍ​‖hsn∗−h0‖ℍ2​1n​∑i=1nϕ⁡(Yi)sn​πn,j​γn,i+oℙ​(1)​⟶n→∞ℙ​0.\displaystyle\quad\leq\sqrt{s_{n}}\kappa^{3}\|h\|_{\mathbb{H}}\|{h^{*}_{s_{n}}}-{h_{0}}\|_{\mathbb{H}}^{2}\frac{1}{n}\sum_{i=1}^{n}\frac{\phi(Y_{i})}{s_{n}\pi_{n,j}}\gamma_{n,i}+o_{\mathbb{P}}(1)\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0. (A.12)

On the other hand, since ∇2ℛsn∗​(h0)\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}({h_{0}}) and ∇2ℛ​(h0)\nabla^{2}{\mathcal{R}}({h_{0}}) are self-adjoint operators, one has

|⟨∇2ℛsn∗​(h0)​(hsn∗−h0),h⟩ℍ−⟨∇2ℛ​(h0)​(hsn∗−h0),h⟩ℍ|\displaystyle|\langle\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}}),h\rangle_{\mathbb{H}}-\langle\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}}),h\rangle_{\mathbb{H}}|
=|⟨hsn∗−h0,∇2ℛsn∗​(h0)​h⟩ℍ−⟨hsn∗−h0,∇2ℛ​(h0)​h⟩ℍ|\displaystyle\quad=|\langle{h^{*}_{s_{n}}}-{h_{0}},\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}({h_{0}})h\rangle_{\mathbb{H}}-\langle{h^{*}_{s_{n}}}-{h_{0}},\nabla^{2}{\mathcal{R}}({h_{0}})h\rangle_{\mathbb{H}}|
=|⟨hsn∗−h0,∇2ℛsn∗​(h0)​h−∇2ℛ​(h0)​h⟩ℍ|\displaystyle\quad=|\langle{h^{*}_{s_{n}}}-{h_{0}},\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}({h_{0}})h-\nabla^{2}{\mathcal{R}}({h_{0}})h\rangle_{\mathbb{H}}|
≤‖hsn∗−h0‖ℍ​‖∇2ℛsn∗​(h0)​h−∇2ℛ​(h0)​h‖ℍ,\displaystyle\quad\leq\|{h^{*}_{s_{n}}}-{h_{0}}\|_{\mathbb{H}}\|\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}({h_{0}})h-\nabla^{2}{\mathcal{R}}({h_{0}})h\|_{\mathbb{H}},

by Cauchy-Schwarz inequality. Furthermore, ℓ′′​(h0​(X),Y)​h​(X)​KX∈ℍ\ell^{\prime\prime}({h_{0}}(X),Y)h(X)K_{X}\in\mathbb{H} has a fourth order moment by Assumptions 1 and 3 hence

‖∇2Lsn∗​(h0)​h−∇2L​(h0)​h‖ℍ​⟶n→∞ℙ​0,\|\nabla^{2}{L}^{*}_{s_{n}}({h_{0}})h-\nabla^{2}{L}({h_{0}})h\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0,

by application of Proposition A.9. Moreover

‖∇2ℛsn∗​(h0)​h−∇2ℛ​(h0)​h‖ℍ\displaystyle\|\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}({h_{0}})h-\nabla^{2}{\mathcal{R}}({h_{0}})h\|_{\mathbb{H}} ≤‖∇2Lsn∗​(h0)​h−∇2L​(h0)​h‖ℍ+|λsn∗−λ0|​‖h‖ℍ.\displaystyle\leq\|\nabla^{2}{L}^{*}_{s_{n}}({h_{0}})h-\nabla^{2}{L}({h_{0}})h\|_{\mathbb{H}}+|{\lambda_{s_{n}}^{*}}-{\lambda_{0}}|\|h\|_{\mathbb{H}}.

Hence

‖∇2ℛsn∗​(h0)​h−∇2ℛ​(h0)​h‖ℍ​⟶n→∞ℙ​0,\|\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}({h_{0}})h-\nabla^{2}{\mathcal{R}}({h_{0}})h\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0,

since λsn∗​⟶n→∞ℙ​λ0{\lambda_{s_{n}}^{*}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}{\lambda_{0}}. Therefore

sn​∫01|⟨∇2ℛsn∗​(h0)​(hsn∗−h0),h⟩ℍ−⟨∇2ℛ​(h0)​(hsn∗−h0),h⟩ℍ|​𝑑t\displaystyle\sqrt{s_{n}}\int_{0}^{1}|\langle\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}}),h\rangle_{\mathbb{H}}-\langle\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}}),h\rangle_{\mathbb{H}}|\,\mathrm{d}t
≤sn​‖hsn∗−h0‖​‖∇2ℛsn∗​(h0)​h−∇2ℛ​(h0)​h‖ℍ​⟶n→∞ℙ​0.\displaystyle\quad\leq\sqrt{s_{n}}\|{h^{*}_{s_{n}}}-{h_{0}}\|\|\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}({h_{0}})h-\nabla^{2}{\mathcal{R}}({h_{0}})h\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0. (A.13)

Finally combining (A.12) and (A.13) yields the wanted result

sn​∫01⟨∇2ℛsn∗​(h¯n,t)​(hsn∗−h0),h⟩ℍ​𝑑t−sn​⟨∇2ℛ​(h0)​(hsn∗−h0),h⟩ℍ​⟶n→∞ℙ​0.∎\sqrt{s_{n}}\int_{0}^{1}\langle\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}(\bar{h}_{n,t})({h^{*}_{s_{n}}}-{h_{0}}),h\rangle_{\mathbb{H}}\,\mathrm{d}t-\sqrt{s_{n}}\langle\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}}),h\rangle_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.\qed

The following lemma can be applied for Multinomial or Poisson subsampling.

Lemma A.11.

Under Assumptions 1, 2, 3 and 5, the quantity sn​(∇Lsn∗​(h0)−∇Ln​(h0))\sqrt{s_{n}}(\nabla{L}^{*}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}})) is asymptotically finite dimensional, i.e. for all ε,δ>0\varepsilon,\delta>0, there exists J∈ℕJ\in\mathbb{N} such that

lim supn∈ℕℙ⁡(∑j>J⟨sn​(∇Lsn∗−∇Ln)​(h0),ej⟩ℍ2≥ε)<δ,\limsup_{n\in\mathbb{N}}\ \mathbb{P}\left(\sum_{j>J}\langle\sqrt{s_{n}}(\nabla{L}^{*}_{s_{n}}-\nabla{L}_{n})({h_{0}}),e_{j}\rangle_{\mathbb{H}}^{2}\geq\varepsilon\right)<\delta,

whether considering Poisson or Multinomial subsampling.

Proof.

Let ε,δ>0\varepsilon,\delta>0 and J∈ℕJ\in\mathbb{N}. By Markov’s inequality

ℙ⁡(∑j>J⟨sn​(∇Lsn∗−∇Ln)​(h0),ej⟩ℍ2≥ε)≤snε​𝔼​[∑j>J⟨(∇Lsn∗−∇Ln)​(h0),ej⟩ℍ2].\mathbb{P}\left(\sum_{j>J}\langle\sqrt{s_{n}}(\nabla{L}^{*}_{s_{n}}-\nabla{L}_{n})({h_{0}}),e_{j}\rangle_{\mathbb{H}}^{2}\geq\varepsilon\right)\leq\frac{s_{n}}{\varepsilon}\mathbb{E}\left[\sum_{j>J}\langle(\nabla{L}^{*}_{s_{n}}-\nabla{L}_{n})({h_{0}}),e_{j}\rangle_{\mathbb{H}}^{2}\right].

Expanding the right hand side together with the tower property yields the quantity

snn2​ε​𝔼​[∑j>J∑i,k=1nℒ′​(Zi,h0,ej)​ℒ′​(Zk,h0,ej)sn2​πn,i​πn,k​(γn,i−sn​πn,i)​(γn,k−sn​πn,k)]\displaystyle\frac{s_{n}}{n^{2}\varepsilon}\mathbb{E}\left[\sum_{j>J}\sum_{i,k=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},e_{j})\mathcal{L}^{\prime}(Z_{k},{h_{0}},e_{j})}{s_{n}^{2}\pi_{n,i}\pi_{n,k}}(\gamma_{n,i}-s_{n}\pi_{n,i})(\gamma_{n,k}-s_{n}\pi_{n,k})\right]
=1n2​ε​𝔼​[∑j>J∑i,k=1nℒ′​(Zi,h0,ej)​ℒ′​(Zk,h0,ej)sn​πn,i​πn,k​𝔼​[(γn,i−sn​πn,i)​(γn,k−sn​πn,k)|𝒟n]].\displaystyle\quad=\frac{1}{n^{2}\varepsilon}\mathbb{E}\left[\sum_{j>J}\sum_{i,k=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},e_{j})\mathcal{L}^{\prime}(Z_{k},{h_{0}},e_{j})}{s_{n}\pi_{n,i}\pi_{n,k}}\mathbb{E}\left[(\gamma_{n,i}-s_{n}\pi_{n,i})(\gamma_{n,k}-s_{n}\pi_{n,k})\middle|{\mathcal{D}_{n}}\right]\right].

However, from (A.9), for all i,k∈{1,…,n}i,k\in\{1,\dots,n\} one has

𝔼⁡[(γn,i−sn​πn,i)​(γn,k−sn​πn,k)|𝒟n]\displaystyle\mathbb{E}\left[(\gamma_{n,i}-s_{n}\pi_{n,i})(\gamma_{n,k}-s_{n}\pi_{n,k})\middle|{\mathcal{D}_{n}}\right] =𝔼⁡[γn,i​γn,k|𝒟n]−sn​πn,i​𝔼​[γn,k|𝒟n]\displaystyle=\mathbb{E}\left[\gamma_{n,i}\gamma_{n,k}\middle|{\mathcal{D}_{n}}\right]-s_{n}\pi_{n,i}\mathbb{E}\left[\gamma_{n,k}\middle|{\mathcal{D}_{n}}\right]
−sn​πn,k​𝔼​[γn,i|𝒟n]+sn2​πn,i​πn,k\displaystyle\qquad-s_{n}\pi_{n,k}\mathbb{E}\left[\gamma_{n,i}\middle|{\mathcal{D}_{n}}\right]+s_{n}^{2}\pi_{n,i}\pi_{n,k}
=𝔼⁡[γn,i​γn,k|𝒟n]−sn2​πn,i​πn,k\displaystyle=\mathbb{E}\left[\gamma_{n,i}\gamma_{n,k}\middle|{\mathcal{D}_{n}}\right]-s_{n}^{2}\pi_{n,i}\pi_{n,k}
≤sn​πn,i​𝟙i=k\displaystyle\leq s_{n}\pi_{n,i}\mathbbm{1}_{i=k}

Thus

snε​𝔼​[∑j>J⟨(∇Lsn∗−∇Ln)​(h0),ej⟩ℍ2]\displaystyle\frac{s_{n}}{\varepsilon}\mathbb{E}\left[\sum_{j>J}\langle(\nabla{L}^{*}_{s_{n}}-\nabla{L}_{n})({h_{0}}),e_{j}\rangle_{\mathbb{H}}^{2}\right]
≤1ε​𝔼​[∑j>J1n2​∑i=1nℒ′​(Zi,h0,ej)2πn,i]\displaystyle\quad\leq\frac{1}{\varepsilon}\mathbb{E}\left[\sum_{j>J}\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},e_{j})^{2}}{\pi_{n,i}}\right]
≤1n​ε​∑i=1n𝔼⁡[maxk∈[n]⁡{1n​πn,k}​∑j>Jℒ′​(Zi,h0,ej)2]\displaystyle\quad\leq\frac{1}{n\varepsilon}\sum_{i=1}^{n}\mathbb{E}\left[\max_{k\in[n]}\left\{\frac{1}{n\pi_{n,k}}\right\}\sum_{j>J}\mathcal{L}^{\prime}(Z_{i},{h_{0}},e_{j})^{2}\right]
=1ε​𝔼​[maxk∈[n]⁡{1n​πn,k}​∑j>Jℒ′​(Z,h0,ej)2]\displaystyle\quad=\frac{1}{\varepsilon}\mathbb{E}\left[\max_{k\in[n]}\left\{\frac{1}{n\pi_{n,k}}\right\}\sum_{j>J}\mathcal{L}^{\prime}(Z,{h_{0}},e_{j})^{2}\right]
≤1ε​𝔼⁡[max∈[n]⁡{1n​πn,i}2]​𝔼⁡[(∑j>Jℓ′​(h0​(X),Y)2​⟨KX,ej⟩ℍ2)2].\displaystyle\quad\leq\frac{1}{\varepsilon}\sqrt{\mathbb{E}\left[\max_{\in[n]}\left\{\frac{1}{n\pi_{n,i}}\right\}^{2}\right]}\sqrt{\mathbb{E}\left[\left(\sum_{j>J}\ell^{\prime}({h_{0}}(X),Y)^{2}\langle K_{X},e_{j}\rangle_{\mathbb{H}}^{2}\right)^{2}\right]}.

However, ‖ℓ′​(h0​(X),Y)​KX‖ℍ2<∞\|\ell^{\prime}({h_{0}}(X),Y)K_{X}\|_{\mathbb{H}}^{2}<\infty hence

Z(J)​=def​∑j>Jℓ′​(h0​(X),Y)2​⟨KX,ej⟩ℍ2​⟶J→∞ℙ​0,Z^{(J)}\overset{\mathrm{def}}{=}\sum_{j>J}\ell^{\prime}({h_{0}}(X),Y)^{2}\langle K_{X},e_{j}\rangle_{\mathbb{H}}^{2}\overset{\mathbb{P}}{\underset{J\rightarrow\infty}{\longrightarrow}}0,

as the rest of a converging series. Furthermore, ‖ℓ′​(h0​(X),Y)​KX‖ℍ2\|\ell^{\prime}({h_{0}}(X),Y)K_{X}\|_{\mathbb{H}}^{2} dominates the series (Z(J))J≥0(Z^{(J)})_{J\geq 0} and has a second order moment by Assumption 3 whence, by the dominated convergence theorem in L2L^{2}, one has

𝔼⁡[(∑j>Jℓ′​(h0​(X),Y)2​⟨KX,ej⟩ℍ2)2]​⟶J→∞​0.\mathbb{E}\left[\left(\sum_{j>J}\ell^{\prime}({h_{0}}(X),Y)^{2}\langle K_{X},e_{j}\rangle_{\mathbb{H}}^{2}\right)^{2}\right]\underset{J\rightarrow\infty}{\longrightarrow}0.

Moreover, it is assumed from Assumption 5 that there exists N∈ℕN\in\mathbb{N} and C>0C>0 such that for all n≥Nn\geq N,

𝔼⁡[max1≤i≤n⁡{1n​πn,i}2]≤C2.\mathbb{E}\left[\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{2}\right]\leq C^{2}.

Hence for JJ large enough such that

𝔼⁡[(∑j>Jℓ′​(h0​(X),Y)2​⟨KX,ej⟩ℍ2)2]<δ​εC,\sqrt{\mathbb{E}\left[\left(\sum_{j>J}\ell^{\prime}({h_{0}}(X),Y)^{2}\langle K_{X},e_{j}\rangle_{\mathbb{H}}^{2}\right)^{2}\right]}<\delta\frac{\varepsilon}{C},

one has

lim supn∈ℕℙ⁡(∑j>J⟨sn​(∇Lsn∗−∇Ln)​(h0),ej⟩ℍ2≥ε)<δ.\limsup_{n\in\mathbb{N}}\ \mathbb{P}\left(\sum_{j>J}\langle\sqrt{s_{n}}(\nabla{L}^{*}_{s_{n}}-\nabla{L}_{n})({h_{0}}),e_{j}\rangle_{\mathbb{H}}^{2}\geq\varepsilon\right)<\delta.

Thus sn​(∇Lsn∗​(h0)−∇Ln​(h0))\sqrt{s_{n}}(\nabla{L}^{*}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}})) is asymptotically finite dimensional. ∎

The following lemma is the main lemma for the proofs of Theorems 3.2, 3.3, 5.1 and 5.2.

Lemma A.12.

Let (Hn)n>0(H_{n})_{n>0} be a sequence of ℍ\mathbb{H} valued random variables and (ℱn)n>0({\mathcal{F}_{n}})_{n>0} a sequence of σ\sigma-algebras. Assume that HnH_{n} is asymptotically finite-dimensional, σ⁡(𝒟n)⊂ℱn\sigma({\mathcal{D}_{n}})\subset{\mathcal{F}_{n}} and for all f∈ℍf\in\mathbb{H},

𝔼⁡[ei​t​⟨Hn,f⟩ℍ|ℱn]​⟶n→∞ℙ​e−12​⟨Σ∗​f,f⟩ℍ,\mathbb{E}\left[e^{it\langle H_{n},f\rangle_{\mathbb{H}}}\middle|{\mathcal{F}_{n}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}e^{-\frac{1}{2}\langle\Sigma^{*}f,f\rangle_{\mathbb{H}}},\addcontentsline{lla}{section}{\numberline q:lem_{s}rm_{n}ormality_{f}inal_{p}art1} (A.14)

for some covariance operator Σ∗\Sigma^{*}. Then

Hn+snn​n​(∇Ln​(h0)−∇L​(h0))​⟶n→∞d​𝒢​(0,Σ∗+c​Σ).H_{n}+\sqrt{\frac{s_{n}}{n}}\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}))\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma^{*}+c\Sigma).
Proof.

Let f∈ℍf\in\mathbb{H} and define

Sn∗​=def​⟨Hn,f⟩ℍ,\displaystyle S_{n}^{*}\overset{\mathrm{def}}{=}\langle H_{n},f\rangle_{\mathbb{H}},
Sn​=def​n​⟨∇Ln​(h0)−∇L​(h0),f⟩ℍ.\displaystyle S_{n}\overset{\mathrm{def}}{=}\sqrt{n}\langle\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}),f\rangle_{\mathbb{H}}.

Let t∈ℝt\in\mathbb{R} and consider the convergence of the characteristic function, i.e.

|𝔼​ei​t​(Sn∗+snn​Sn)−e−12​t2​⟨(Σ∗+c​Σ)​f,f⟩ℍ|.\left|\mathbb{E}e^{it(S_{n}^{*}+\sqrt{\frac{s_{n}}{n}}S_{n})}-e^{-\frac{1}{2}t^{2}\langle(\Sigma^{*}+c\Sigma)f,f\rangle_{\mathbb{H}}}\right|.

First adding and subtracting ei​t​snn​Sn​e−12​t2​⟨Σ∗​f,f⟩ℍe^{it\sqrt{\frac{s_{n}}{n}}S_{n}}e^{-\frac{1}{2}t^{2}\langle\Sigma^{*}f,f\rangle_{\mathbb{H}}} and using the triangle inequality one gets that the previous display is upper bounded by

|𝔼⁡[ei​t​snn​Sn​(ei​t​Sn∗−e−12​t2​⟨Σ∗​f,f⟩ℍ)]|+e−12​t2​⟨Σ∗​f,f⟩ℍ​|𝔼⁡[ei​t​snn​Sn]−e−12​t2​c​⟨Σ​f,f⟩ℍ|.\left|\mathbb{E}\left[e^{it\sqrt{\frac{s_{n}}{n}}S_{n}}(e^{itS_{n}^{*}}-e^{-\frac{1}{2}t^{2}\langle\Sigma^{*}f,f\rangle_{\mathbb{H}}})\right]\right|+e^{-\frac{1}{2}t^{2}\langle\Sigma^{*}f,f\rangle_{\mathbb{H}}}\left|\mathbb{E}\left[e^{it\sqrt{\frac{s_{n}}{n}}S_{n}}\right]-e^{-\frac{1}{2}t^{2}c\langle\Sigma f,f\rangle_{\mathbb{H}}}\right|.

By Lemma A.3, Sn​⟶n→∞d​𝒩​(0,⟨Σ​f,f⟩ℍ)S_{n}\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{N}(0,\langle\Sigma f,f\rangle_{\mathbb{H}}) and since sn/n​⟶n→∞​cs_{n}/n\underset{n\rightarrow\infty}{\longrightarrow}c, Slutsky’s theorem yields that snn​Sn​⟶n→∞d​𝒩​(0,c​⟨Σ​f,f⟩ℍ)\sqrt{\frac{s_{n}}{n}}S_{n}\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{N}(0,c\langle\Sigma f,f\rangle_{\mathbb{H}}). Thus

|𝔼⁡[ei​t​snn​Sn]−e−12​t2​c​⟨Σ​f,f⟩ℍ|​⟶n→∞​0.\left|\mathbb{E}\left[e^{it\sqrt{\frac{s_{n}}{n}}S_{n}}\right]-e^{-\frac{1}{2}t^{2}c\langle\Sigma f,f\rangle_{\mathbb{H}}}\right|\underset{n\rightarrow\infty}{\longrightarrow}0.

Moreover, SnS_{n} is 𝒟n{\mathcal{D}_{n}}-measurable thus

|𝔼⁡[ei​t​snn​Sn​(ei​t​Sn∗−e−12​t2​⟨Σ∗​f,f⟩ℍ)]|\displaystyle\left|\mathbb{E}\left[e^{it\sqrt{\frac{s_{n}}{n}}S_{n}}(e^{itS_{n}^{*}}-e^{-\frac{1}{2}t^{2}\langle\Sigma^{*}f,f\rangle_{\mathbb{H}}})\right]\right| =|𝔼⁡[ei​t​snn​Sn​(𝔼⁡[ei​t​Sn∗|ℱn]−e−12​t2​⟨Σ∗​f,f⟩ℍ)]|\displaystyle=\left|\mathbb{E}\left[e^{it\sqrt{\frac{s_{n}}{n}}S_{n}}\left(\mathbb{E}\left[e^{itS_{n}^{*}}\middle|{\mathcal{F}_{n}}\right]-e^{-\frac{1}{2}t^{2}\langle\Sigma^{*}f,f\rangle_{\mathbb{H}}}\right)\right]\right|
≤𝔼⁡[|𝔼⁡[ei​t​Sn∗|ℱn]−e−12​t2​⟨Σ∗​f,f⟩ℍ|].\displaystyle\leq\mathbb{E}\left[\left|\mathbb{E}\left[e^{itS_{n}^{*}}\middle|{\mathcal{F}_{n}}\right]-e^{-\frac{1}{2}t^{2}\langle\Sigma^{*}f,f\rangle_{\mathbb{H}}}\right|\right].

However, |𝔼⁡[ei​t​Sn∗|𝒟n]|≤1\left|\mathbb{E}\left[e^{itS_{n}^{*}}\middle|{\mathcal{D}_{n}}\right]\right|\leq 1. Thus, by (A.14) and the dominated convergence theorem

𝔼⁡[|𝔼⁡[ei​t​Sn∗|ℱn]−e−12​t2​⟨Σ∗​f,f⟩ℍ|]​⟶n→∞​0.\mathbb{E}\left[\left|\mathbb{E}\left[e^{itS_{n}^{*}}\middle|{\mathcal{F}_{n}}\right]-e^{-\frac{1}{2}t^{2}\langle\Sigma^{*}f,f\rangle_{\mathbb{H}}}\right|\right]\underset{n\rightarrow\infty}{\longrightarrow}0.

As a consequence,

Sn∗+snn​Sn​⟶n→∞d​𝒩​(0,⟨(Σ∗+c​Σ)​f,f⟩ℍ).S_{n}^{*}+\sqrt{\frac{s_{n}}{n}}S_{n}\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{N}(0,\langle(\Sigma^{*}+c\Sigma)f,f\rangle_{\mathbb{H}}).

Moreover, by Lemma A.3 n​(∇Ln​(h0)−∇L​(h0))\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})) is asymptotically finite dimensional and so is HnH_{n}, by assumption. Then, by Lemma A.8 the sum of two asymptotically finite dimensional sequences of random variables in ℍ\mathbb{H} is itself asymptotically finite dimensional. Therefore

Hn+n​(∇Ln​(h0)−∇L​(h0))​⟶n→∞d​𝒢​(0,Σ∗+c​Σ).∎H_{n}+\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}))\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma^{*}+c\Sigma).\qed

A.4 Proof of Theorem 3.2

Lemma A.13.

Under Assumptions 1, 2, 3 and 5, one has for all t∈ℝt\in\mathbb{R} and f∈ℍf\in\mathbb{H},

𝔼⁡[exp⁡(i​t​Ssn∗)|𝒟n]​⟶n→∞ℙ​exp⁡(−12​t2​⟨ΣM∗​(ψ)​f,f⟩ℍ),\mathbb{E}\left[\exp\left(itS_{s_{n}}^{*}\right)\middle|{\mathcal{D}_{n}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\exp\left(-\frac{1}{2}t^{2}\langle\Sigma^{*}_{\mathrm{M}}(\psi)f,f\rangle_{\mathbb{H}}\right),

where

Ssn∗​=def​sn​⟨(∇Lsn∗​(h0)−∇Ln​(h0)),f⟩ℍ,S_{s_{n}}^{*}\overset{\mathrm{def}}{=}\sqrt{s_{n}}\langle(\nabla{L}^{*}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}})),f\rangle_{\mathbb{H}},

and

ΣM∗​(ψ)​=def​𝔼​[𝔼⁡[ψ⁡(Z)]ψ⁡(Z)​ℓ′​(h0​(X),Y)2​KX⊗KX]−∇L​(h0)⊗∇L​(h0).\Sigma^{*}_{\mathrm{M}}(\psi)\overset{\mathrm{def}}{=}\mathbb{E}\left[\frac{\mathbb{E}\left[\psi(Z)\right]}{\psi(Z)}\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-\nabla{L}({h_{0}})\otimes\nabla{L}({h_{0}}).
Proof.

The goal is to apply Theorem A.7. Recall that

∇Lsn∗​(h0)\displaystyle\nabla{L}^{*}_{s_{n}}({h_{0}}) =1n​∑i=1nℓ′​(h0​(Xi),Yi)sn​πn,i​Nn,i​KXi\displaystyle=\frac{1}{n}\sum_{i=1}^{n}\frac{\ell^{\prime}({h_{0}}(X_{i}),Y_{i})}{s_{n}\pi_{n,i}}N_{n,i}K_{X_{i}}
=1sn∑j=1sn∑i=1nℓ′​(h0​(Xi),Yi)n​πn,iKXi𝟙{In,j=i},\displaystyle=\frac{1}{s_{n}}\sum_{j=1}^{s_{n}}\sum_{i=1}^{n}\frac{\ell^{\prime}({h_{0}}(X_{i}),Y_{i})}{n\pi_{n,i}}K_{X_{i}}\mathbbm{1}_{\{I_{n,j}=i\}},

Let f∈ℍf\in\mathbb{H} and define Ssn∗​=def​⟨sn​(∇Lsn∗−∇Ln)​(h0),f⟩ℍS_{s_{n}}^{*}\overset{\mathrm{def}}{=}\langle\sqrt{s_{n}}(\nabla{L}^{*}_{s_{n}}-\nabla{L}_{n})({h_{0}}),f\rangle_{\mathbb{H}} a real-valued random variable and ℒ′​(Z,h,f)​=def​ℓ′​(h⁡(X),Y)​f​(X)\mathcal{L}^{\prime}(Z,h,f)\overset{\mathrm{def}}{=}\ell^{\prime}(h(X),Y)f(X). Then

Ssn∗\displaystyle S_{s_{n}}^{*} =∑j=1sn1sn(1n∑i=1nℒ′​(Zi,h0,f)πn,i𝟙{In,j=i}−⟨∇Ln(h0),f⟩ℍ)\displaystyle=\sum_{j=1}^{s_{n}}\frac{1}{\sqrt{s_{n}}}\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\pi_{n,i}}\mathbbm{1}_{\{I_{n,j}=i\}}-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}\right)
=∑j=1snηn,j,\displaystyle=\sum_{j=1}^{s_{n}}\eta_{n,j},

where

ηn,j=def1sn(1n∑i=1nℒ′​(Zi,h0,f)πn,i𝟙{In,j=i}−⟨∇Ln(h0),f⟩ℍ),\eta_{n,j}\overset{\mathrm{def}}{=}\frac{1}{\sqrt{s_{n}}}\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\pi_{n,i}}\mathbbm{1}_{\{I_{n,j}=i\}}-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}\right),

for all n∈ℕn\in\mathbb{N} and j∈[sn]j\in[s_{n}]. Moreover, define the filtrations (ℱn,j)n∈ℕ,1≤j≤sn({\mathcal{F}_{n,j}})_{n\in\mathbb{N},1\leq j\leq s_{n}} such that ℱn,j{\mathcal{F}_{n,j}} is the σ\sigma-algebra generated by 𝒟n{\mathcal{D}_{n}} and In,1,…,In,jI_{n,1},\dots,I_{n,j} for 1≤j≤sn1\leq j\leq s_{n} and n∈ℕn\in\mathbb{N}. Notice that for all n∈ℕn\in\mathbb{N} and j∈{1,…,sn}j\in\{1,\dots,s_{n}\} the conditional distributions of ηn,j\eta_{n,j} with respect to 𝒟n{\mathcal{D}_{n}} and ℱn,j−1{\mathcal{F}_{n,j-1}} are the same. Remark as well that, conditionally to 𝒟n{\mathcal{D}_{n}}, Ssn∗S_{s_{n}}^{*} is a sum of i.i.d. random variables such that 𝔼⁡[ηn,j|𝒟n]=0\mathbb{E}\left[\eta_{n,j}\middle|{\mathcal{D}_{n}}\right]=0 since ℙ⁡(In,j=i|𝒟n)=πn,i\mathbb{P}\left(I_{n,j}=i\middle|{\mathcal{D}_{n}}\right)=\pi_{n,i}. Hence {ηn,j:n∈ℕ,1≤j≤sn}\{\eta_{n,j}:n\in\mathbb{N},1\leq j\leq s_{n}\} is a martingale difference array for the filtration (ℱn,j)n∈ℕ,1≤j≤sn({\mathcal{F}_{n,j}})_{n\in\mathbb{N},1\leq j\leq s_{n}}. Moreover, its conditional variance reads

∑j=1sn𝔼⁡[ηn,j2|ℱn,j−1]\displaystyle\sum_{j=1}^{s_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\middle|{\mathcal{F}_{n,j-1}}\right] =sn​𝔼​[ηn,12|𝒟n]\displaystyle=s_{n}\mathbb{E}\left[\eta_{n,1}^{2}\middle|{\mathcal{D}_{n}}\right]
=𝔼[(1n∑i=1nℒ′​(Zi,h0,f)πn,i𝟙{In,1=i}−⟨∇Ln(h0),f⟩ℍ)2|𝒟n].\displaystyle=\mathbb{E}\left[\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\pi_{n,i}}\mathbbm{1}_{\{I_{n,1}=i\}}-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}\right)^{2}\middle|{\mathcal{D}_{n}}\right].

Since 𝔼[1n∑i=1nℒ′​(Zi,h0,f)πn,i𝟙{In,1=i}|𝒟n]=⟨∇Ln(h0),f⟩ℍ\mathbb{E}\left[\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\pi_{n,i}}\mathbbm{1}_{\{I_{n,1}=i\}}\middle|{\mathcal{D}_{n}}\right]=\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}, the previous display reads

∑j=1sn𝔼[ηn,j2|ℱn,j−1]=𝔼[(1n∑i=1nℒ′​(Zi,h0,f)πn,i𝟙{In,1=i})2|𝒟n]−⟨∇Ln(h0),f⟩ℍ2.\sum_{j=1}^{s_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\middle|{\mathcal{F}_{n,j-1}}\right]=\mathbb{E}\left[\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\pi_{n,i}}\mathbbm{1}_{\{I_{n,1}=i\}}\right)^{2}\middle|{\mathcal{D}_{n}}\right]-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}^{2}.

However, only one term of the sum in the right hand side of the previous display is non-zero. Thus

𝔼[(1n∑i=1nℒ′​(Zi,h0,f)πn,i𝟙{In,1=i})2|𝒟n]\displaystyle\mathbb{E}\left[\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\pi_{n,i}}\mathbbm{1}_{\{I_{n,1}=i\}}\right)^{2}\middle|{\mathcal{D}_{n}}\right] =1n2​∑i=1nℒ′​(Zi,h0,f)2πn,i2​ℙ​(In,1=i|𝒟n)\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\pi_{n,i}^{2}}\mathbb{P}\left(I_{n,1}=i\middle|{\mathcal{D}_{n}}\right)
=1n2​∑i=1nℒ′​(Zi,h0,f)2πn,i.\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\pi_{n,i}}.

Hence, the conditional variance reads

∑j=1sn𝔼⁡[ηn,j2|ℱn,j−1]=1n2​∑i=1nℒ′​(Zi,h0,f)2πn,i−⟨∇Ln​(h0),f⟩ℍ2.\sum_{j=1}^{s_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\middle|{\mathcal{F}_{n,j-1}}\right]=\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\pi_{n,i}}-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}^{2}.

If one writes πn,i=ψ⁡(Zi)/∑j=1nψ⁡(Zj)\pi_{n,i}=\psi(Z_{i})/\sum_{j=1}^{n}\psi(Z_{j}), then by the law of large numbers

∑j=1sn𝔼⁡[ηn,j2|ℱn,j−1]\displaystyle\sum_{j=1}^{s_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\middle|{\mathcal{F}_{n,j-1}}\right] =1n2​∑i=1n(∑j=1nψ⁡(Zj))​ℒ′​(Zi,h0,f)2ψ⁡(Zi)−⟨∇Ln​(h0),f⟩ℍ2\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\left(\sum_{j=1}^{n}\psi(Z_{j})\right)\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\psi(Z_{i})}-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}^{2}
=(1n​∑j=1nψ⁡(Zj))​(1n​∑i=1nℒ′​(Zi,h0,f)2ψ⁡(Zi))−⟨∇Ln​(h0),f⟩ℍ2\displaystyle=\left(\frac{1}{n}\sum_{j=1}^{n}\psi(Z_{j})\right)\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\psi(Z_{i})}\right)-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}^{2}
⟶n→∞ℙ​𝔼​[ψ⁡(Z)]​𝔼​[ℒ′​(Z,h0,f)2ψ⁡(Z)]−⟨∇L​(h0),f⟩ℍ2=⟨ΣM∗​(ψ)​f,f⟩ℍ,\displaystyle\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}\left[\psi(Z)\right]\mathbb{E}\left[\frac{\mathcal{L}^{\prime}(Z,{h_{0}},f)^{2}}{\psi(Z)}\right]-\langle\nabla{L}({h_{0}}),f\rangle_{\mathbb{H}}^{2}=\langle\Sigma^{*}_{\mathrm{M}}(\psi)f,f\rangle_{\mathbb{H}},

where ΣM∗​(ψ)​=def​𝔼​[𝔼⁡[ψ⁡(Z)]ψ⁡(Z)​ℓ′​(h0​(X),Y)2​KX⊗KX]−∇L​(h0)⊗∇L​(h0)\Sigma^{*}_{\mathrm{M}}(\psi)\overset{\mathrm{def}}{=}\mathbb{E}\left[\frac{\mathbb{E}\left[\psi(Z)\right]}{\psi(Z)}\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-\nabla{L}({h_{0}})\otimes\nabla{L}({h_{0}}).

Let us now show that the martingale difference array satisfies the conditional Lindeberg-Feller condition. Let ε>0\varepsilon>0,

∑j=1sn𝔼[ηn,j2𝟙{|ηn,j|>ε}|𝒟n]\displaystyle\sum_{j=1}^{s_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\mathbbm{1}_{\{|\eta_{n,j}|>\varepsilon\}}\middle|{\mathcal{D}_{n}}\right]
=sn𝔼[ηn,12𝟙{|ηn,1|>ε}|𝒟n]\displaystyle\quad=s_{n}\mathbb{E}\left[\eta_{n,1}^{2}\mathbbm{1}_{\{|\eta_{n,1}|>\varepsilon\}}\middle|{\mathcal{D}_{n}}\right]
≤snε2​𝔼​[ηn,14|𝒟n]\displaystyle\quad\leq\frac{s_{n}}{\varepsilon^{2}}\mathbb{E}\left[\eta_{n,1}^{4}\middle|{\mathcal{D}_{n}}\right]
=1sn​ε2𝔼[(1n∑i=1nℒ′​(Zi,h0,f)πn,i𝟙{In,j=i}−⟨∇Ln(h0),f⟩ℍ)4|𝒟n].\displaystyle\quad=\frac{1}{s_{n}\varepsilon^{2}}\mathbb{E}\left[\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\pi_{n,i}}\mathbbm{1}_{\{I_{n,j}=i\}}-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}\right)^{4}\middle|{\mathcal{D}_{n}}\right].

Furthermore expanding the forth order moment yields

∑j=1sn𝔼[ηn,j2𝟙{|ηn,j|>ε}|𝒟n]\displaystyle\sum_{j=1}^{s_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\mathbbm{1}_{\{|\eta_{n,j}|>\varepsilon\}}\middle|{\mathcal{D}_{n}}\right]
≤1sn​ε2​(1n4​∑i=1nℒ′​(Zi,h0,f)4πn,i3−4​⟨∇Ln​(h0),f⟩ℍn3​∑i=1nℒ′​(Zi,h0,f)3πn,i2CLOSE\displaystyle\quad\leq\frac{1}{s_{n}\varepsilon^{2}}\Bigg(\frac{1}{n^{4}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{4}}{\pi_{n,i}^{3}}-4\frac{\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}}{n^{3}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{3}}{\pi_{n,i}^{2}}
+6⟨∇Ln​(h0),f⟩ℍ2n2∑i=1nℒ′​(Zi,h0,f)2πn,i−3⟨∇Ln(h0),f⟩ℍ4).\displaystyle\qquad\qquad+6\frac{\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}^{2}}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\pi_{n,i}}-3\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}^{4}\Bigg).

However by Assumption 5, for all δ>0\delta>0,

ℙ⁡(max1≤i≤n⁡{1n​πn,i}>δ)≤1δ​𝔼​[max1≤i≤n⁡{1n​πn,i}]≤1δ​𝔼⁡[max1≤i≤n⁡{1n​πn,i}2]=O⁡(1δ).\displaystyle\mathbb{P}\left(\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}>\delta\right)\leq\frac{1}{\delta}\mathbb{E}\left[\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}\right]\leq\frac{1}{\delta}\sqrt{\mathbb{E}\left[\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{2}\right]}=O\left(\frac{1}{\delta}\right).

Whence, max1≤i≤n⁡{n​πn,i}−1=Oℙ​(1)\max_{1\leq i\leq n}\left\{n\pi_{n,i}\right\}^{-1}=O_{\mathbb{P}}(1) and more specifically max1≤i≤n⁡{n​πn,i}−p=Oℙ​(1)\max_{1\leq i\leq n}\left\{n\pi_{n,i}\right\}^{-p}=O_{\mathbb{P}}(1) for any p∈{1,2,3}p\in\{1,2,3\}. Hence, using the fact that ⟨∇Ln​(h0),f⟩ℍ4=Oℙ​(1)\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}^{4}=O_{\mathbb{P}}(1),

1np+1​∑i=1n|ℒ′​(Zi,h0,f)|p+1πn,ip\displaystyle\frac{1}{n^{p+1}}\sum_{i=1}^{n}\frac{|\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)|^{p+1}}{\pi_{n,i}^{p}} ≤max1≤i≤n⁡{1np​πn,ip}​1n​∑i=1n|ℒ′​(Zi,h0,f)|p+1\displaystyle\leq\max_{1\leq i\leq n}\left\{\frac{1}{n^{p}\pi_{n,i}^{p}}\right\}\frac{1}{n}\sum_{i=1}^{n}|\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)|^{p+1}
=max1≤i≤n⁡{1n​πn,i}p​1n​∑i=1n|ℒ′​(Zi,h0,f)|p+1=Oℙ​(1).\displaystyle=\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{p}\frac{1}{n}\sum_{i=1}^{n}|\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)|^{p+1}=O_{\mathbb{P}}(1).

Thus ∑j=1sn𝔼[ηn,j2𝟙{|ηn,j|>ε}|𝒟n]⟶n→∞ℙ0\sum_{j=1}^{s_{n}}\mathbb{E}\left[\eta_{n,j}^{2}\mathbbm{1}_{\{|\eta_{n,j}|>\varepsilon\}}\middle|{\mathcal{D}_{n}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0. Whence, from Theorem A.7,

∏j=1sn𝔼⁡[ei​t​ηn,j|ℱn,j−1]​⟶n→∞ℙ​exp⁡(−12​t2​⟨ΣM∗​(ψ)​f,f⟩ℍ).\prod_{j=1}^{s_{n}}\mathbb{E}\left[e^{it\eta_{n,j}}\middle|{\mathcal{F}_{n,j-1}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\exp\left(-\frac{1}{2}t^{2}\langle\Sigma^{*}_{\mathrm{M}}(\psi)f,f\rangle_{\mathbb{H}}\right).

Finally, 𝔼⁡[ei​t​ηn,j|ℱn,j−1]=𝔼⁡[ei​t​ηn,j|𝒟n]\mathbb{E}\left[e^{it\eta_{n,j}}\middle|{\mathcal{F}_{n,j-1}}\right]=\mathbb{E}\left[e^{it\eta_{n,j}}\middle|{\mathcal{D}_{n}}\right] and conditionally to 𝒟n{\mathcal{D}_{n}}, ηn,1,…,ηn,sn\eta_{n,1},\dots,\eta_{n,s_{n}} are independent hence

𝔼⁡[ei​t​Ssn∗|𝒟n]=∏j=1sn𝔼⁡[ei​t​ηn,j|ℱn,j−1]​⟶n→∞ℙ​exp⁡(−12​t2​⟨ΣM∗​(ψ)​f,f⟩ℍ).∎\mathbb{E}\left[e^{itS_{s_{n}}^{*}}\middle|{\mathcal{D}_{n}}\right]=\prod_{j=1}^{s_{n}}\mathbb{E}\left[e^{it\eta_{n,j}}\middle|{\mathcal{F}_{n,j-1}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\exp\left(-\frac{1}{2}t^{2}\langle\Sigma^{*}_{\mathrm{M}}(\psi)f,f\rangle_{\mathbb{H}}\right).\qed

We can now prove the main theorem using the above intermediate results.

Proof of Theorem 3.2.

The fundamental theorem of calculus yields that

0=∇ℛsn∗​(hsn∗)=∇ℛsn∗​(h0)+∫01∇2ℛsn∗​(h¯n,t)​(hsn∗−h0)​𝑑t,0=\nabla{\mathcal{R}}^{*}_{s_{n}}({h^{*}_{s_{n}}})=\nabla{\mathcal{R}}^{*}_{s_{n}}({h_{0}})+\int_{0}^{1}\nabla^{2}{\mathcal{R}}^{*}_{s_{n}}(\bar{h}_{n,t})({h^{*}_{s_{n}}}-{h_{0}})\,\mathrm{d}t,

with h¯n,t=h0+t⁡(hsn∗−h0)\bar{h}_{n,t}={h_{0}}+t({h^{*}_{s_{n}}}-{h_{0}}). By Lemma A.10, one has

−sn∇ℛsn∗(h0)=sn∇2ℛ(h0)(hsn∗−h0)+oℙ(1).\displaystyle-\sqrt{s_{n}}\nabla{\mathcal{R}}^{*}_{s_{n}}({h_{0}})=\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}})+o_{\mathbb{P}}(1).

By definition of ℛsn∗​(h0){\mathcal{R}}^{*}_{s_{n}}({h_{0}}), the fact that L⁡(h0)=−λ0​h0{L}({h_{0}})=-{\lambda_{0}}{h_{0}} and adding and retrieving L⁡(h0){L}({h_{0}}) and Ln​(h0){L}_{n}({h_{0}}), one has

∇ℛsn∗​(h0)\displaystyle\nabla{\mathcal{R}}^{*}_{s_{n}}({h_{0}}) =∇Lsn∗​(h0)+λsn∗​h0\displaystyle=\nabla{L}^{*}_{s_{n}}({h_{0}})+{\lambda_{s_{n}}^{*}}{h_{0}}
=(Lsn∗​(h0)−∇Ln​(h0))+(∇Ln​(h0)−∇L​(h0))+(λsn∗−λ0)​h0.\displaystyle=({L}^{*}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}}))+(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}))+({\lambda_{s_{n}}^{*}}-{\lambda_{0}}){h_{0}}.

Whence

sn​∇2ℛ​(h0)​(hsn∗−h0)+oℙ​(1)\displaystyle\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}})+o_{\mathbb{P}}(1) =−sn​(∇Lsn∗​(h0)−∇Ln​(h0))\displaystyle=-\sqrt{s_{n}}(\nabla{L}^{*}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}}))
−snn​n​(∇Ln​(h0)−∇L​(h0))\displaystyle\qquad-\sqrt{\frac{s_{n}}{n}}\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}}))
−sn​(λsn∗−λ0)​h0.\displaystyle\qquad-\sqrt{s_{n}}({\lambda_{s_{n}}^{*}}-{\lambda_{0}}){h_{0}}.

First, sn​(λsn∗−λn)​h0​⟶n→∞ℙ​0\sqrt{s_{n}}({\lambda_{s_{n}}^{*}}-{\lambda_{n}}){h_{0}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0 by ’ ‣ Section 3. Applying A.12 with ℱn=σ⁡(𝒟n){\mathcal{F}_{n}}=\sigma({\mathcal{D}_{n}}) and Hn=sn​(∇Lsn∗​(h0)−∇Ln​(h0))H_{n}=\sqrt{s_{n}}(\nabla{L}^{*}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}})), together with Lemmas A.13 and A.11 yields

sn​∇2ℛ​(h0)​(hsn∗−h0)​⟶n→∞d​𝒢​(0,ΣM∗​(ψ)+c​Σ).∎\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma^{*}_{\mathrm{M}}(\psi)+c\Sigma).\qed

A.5 Proof of Theorem 3.3

Lemma A.14.

Under Assumptions 1, 2, 3 and 5, furthermore assume that sn/n​⟶n→∞​c∈[0,1]s_{n}/n\underset{n\rightarrow\infty}{\longrightarrow}c\in[0,1] and πn,i≤1/sn\pi_{n,i}\leq 1/s_{n} almost surely for all n>0n>0 and i∈{1,…,n}i\in\{1,\dots,n\}. Then for all t∈ℝt\in\mathbb{R} and f∈ℍf\in\mathbb{H},

𝔼⁡[exp⁡(i​t​Ssn∗)|𝒟n]​⟶n→∞ℙ​exp⁡(−12​t2​⟨ΣP,c∗​(ψ)​f,f⟩ℍ),\mathbb{E}\left[\exp\left(itS_{s_{n}}^{*}\right)\middle|{\mathcal{D}_{n}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\exp\left(-\frac{1}{2}t^{2}\langle\Sigma^{*}_{\mathrm{P},c}(\psi)f,f\rangle_{\mathbb{H}}\right),

with

Ssn∗​=def​sn​⟨(∇Lsn∗​(h0)−∇Ln​(h0)),f⟩ℍ,S_{s_{n}}^{*}\overset{\mathrm{def}}{=}\sqrt{s_{n}}\langle(\nabla{L}^{*}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}})),f\rangle_{\mathbb{H}},

and

ΣP,c∗​(ψ)​=def​𝔼​[𝔼⁡[ψ⁡(Z)]ψ⁡(Z)​ℓ′​(h0​(X),Y)2​KX⊗KX]−c​𝔼​[ℓ′​(h0​(X),Y)2​KX⊗KX].\Sigma^{*}_{\mathrm{P},c}(\psi)\overset{\mathrm{def}}{=}\mathbb{E}\left[\frac{\mathbb{E}\left[\psi(Z)\right]}{\psi(Z)}\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-c\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right].
Proof.

The goal is to apply Theorem A.7. Recall that

∇Lsn∗​(h0)=1n​∑i=1nℓ′​(h0​(Xi),Yi)sn​πn,i​KXi​δn,i,\displaystyle\nabla{L}^{*}_{s_{n}}({h_{0}})=\frac{1}{n}\sum_{i=1}^{n}\frac{\ell^{\prime}({h_{0}}(X_{i}),Y_{i})}{s_{n}\pi_{n,i}}K_{X_{i}}\delta_{n,i},

Let f∈ℍf\in\mathbb{H} and define Ssn∗​=def​⟨sn​(∇Lsn∗−∇Ln)​(h0),f⟩ℍS_{s_{n}}^{*}\overset{\mathrm{def}}{=}\langle\sqrt{s_{n}}(\nabla{L}^{*}_{s_{n}}-\nabla{L}_{n})({h_{0}}),f\rangle_{\mathbb{H}} a real-valued random variable and ℒ′​(Z,h,f)​=def​ℓ′​(h⁡(X),Y)​f​(X)\mathcal{L}^{\prime}(Z,h,f)\overset{\mathrm{def}}{=}\ell^{\prime}(h(X),Y)f(X), then

Ssn∗\displaystyle S_{s_{n}}^{*} =snn​∑i=1nℒ′​(Zi,h0,f)sn​πn,i​δn,i−snn​∑i=1nℒ′​(Zi,h0,f)\displaystyle=\frac{\sqrt{s_{n}}}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{s_{n}\pi_{n,i}}\delta_{n,i}-\frac{\sqrt{s_{n}}}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)
=∑i=1nℒ′​(Zi,h0,f)n​sn​πn,i​(δn,i−sn​πn,i)\displaystyle=\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{n\sqrt{s_{n}}\pi_{n,i}}(\delta_{n,i}-s_{n}\pi_{n,i})
=∑i=1nηn,i,\displaystyle=\sum_{i=1}^{n}\eta_{n,i},

where

ηn,i​=def​ℒ′​(Zi,h0,f)n​sn​πn,i​(δn,i−sn​πn,i),\eta_{n,i}\overset{\mathrm{def}}{=}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{n\sqrt{s_{n}}\pi_{n,i}}(\delta_{n,i}-s_{n}\pi_{n,i}),

for all n∈ℕn\in\mathbb{N} and i∈{1,…,n}i\in\{1,\dots,n\}. Moreover, define the filtration array (ℱn,i)n∈ℕ,1≤i≤n({\mathcal{F}_{n,i}})_{n\in\mathbb{N},1\leq i\leq n} such that ℱn,i{\mathcal{F}_{n,i}} is the σ\sigma-algebra generated by 𝒟n{\mathcal{D}_{n}} and δn,1,…,δn,i\delta_{n,1},\dots,\delta_{n,i} for 1≤i≤n1\leq i\leq n and n∈ℕn\in\mathbb{N}. Notice that for all n∈ℕn\in\mathbb{N} and i≤ni\leq n the conditional distributions of ηn,i\eta_{n,i} with respect to 𝒟n{\mathcal{D}_{n}} and ℱn,i−1{\mathcal{F}_{n,i-1}} are the same. Remark as well that, conditionally to 𝒟n{\mathcal{D}_{n}}, Ssn∗S_{s_{n}}^{*} is a sum of independent random variables such that 𝔼⁡[ηn,i|𝒟n]=0\mathbb{E}\left[\eta_{n,i}\middle|{\mathcal{D}_{n}}\right]=0 since 𝔼⁡[δn,i|𝒟n]=sn​πn,i\mathbb{E}\left[\delta_{n,i}\middle|{\mathcal{D}_{n}}\right]=s_{n}\pi_{n,i}. Hence {ηn,i:n∈ℕ,1≤i≤n}\{\eta_{n,i}:n\in\mathbb{N},1\leq i\leq n\} is a martingale difference array for the filtration (ℱn,i)n∈ℕ,1≤i≤n({\mathcal{F}_{n,i}})_{n\in\mathbb{N},1\leq i\leq n}. Moreover, its conditional variance reads

∑i=1n𝔼⁡[ηn,i2|ℱn,i−1]\displaystyle\sum_{i=1}^{n}\mathbb{E}\left[\eta_{n,i}^{2}\middle|{\mathcal{F}_{n,i-1}}\right] =∑i=1nℒ′​(Zi,h0,f)2n2​sn​πn,i2​𝔼​[(δn,i−sn​πn,i)2|𝒟n].\displaystyle=\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{n^{2}s_{n}\pi_{n,i}^{2}}\mathbb{E}\left[(\delta_{n,i}-s_{n}\pi_{n,i})^{2}\middle|{\mathcal{D}_{n}}\right].

Since, conditionally to 𝒟n{\mathcal{D}_{n}}, δn,i\delta_{n,i} follows a Bernoulli distribution of parameter sn​πn,is_{n}\pi_{n,i}, the previous display reads

∑i=1n𝔼⁡[ηn,i2|ℱn,i−1]\displaystyle\sum_{i=1}^{n}\mathbb{E}\left[\eta_{n,i}^{2}\middle|{\mathcal{F}_{n,i-1}}\right] =∑i=1nsn​πn,i​(1−sn​πn,i)n2​sn​πn,i2​ℒ′​(Zi,h0,f)2\displaystyle=\sum_{i=1}^{n}\frac{s_{n}\pi_{n,i}(1-s_{n}\pi_{n,i})}{n^{2}s_{n}\pi_{n,i}^{2}}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}
=1n2​∑i=1nℒ′​(Zi,h0,f)2πn,i−snn2​∑i=1nℒ′​(Zi,h0,f)2.\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\pi_{n,i}}-\frac{s_{n}}{n^{2}}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}.

On the one hand

snn2​∑i=1nℒ′​(Zi,h0,f)2​⟶n→∞ℙ​c​𝔼​[ℒ′​(Z,h0,f)2],\frac{s_{n}}{n^{2}}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}c\mathbb{E}\left[\mathcal{L}^{\prime}(Z,{h_{0}},f)^{2}\right],

as it is assumed that sn/n​⟶n→∞​c∈[0,1]s_{n}/n\underset{n\rightarrow\infty}{\longrightarrow}c\in[0,1]. On the other hand, if one writes πn,i=ψ⁡(Zi)/∑j=1nψ⁡(Zj)\pi_{n,i}=\psi(Z_{i})/\sum_{j=1}^{n}\psi(Z_{j}), by the law of large numbers

1n2​∑i=1nℒ′​(Zi,h0,f)2πn,i\displaystyle\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\pi_{n,i}} =1n2​∑i=1n(∑j=1nψ⁡(Zj))​ℒ′​(Zi,h0,f)2ψ⁡(Zi)\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\left(\sum_{j=1}^{n}\psi(Z_{j})\right)\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\psi(Z_{i})}
=(1n​∑j=1nψ⁡(Zj))​(1n​∑i=1nℒ′​(Zi,h0,f)2ψ⁡(Zi))\displaystyle=\left(\frac{1}{n}\sum_{j=1}^{n}\psi(Z_{j})\right)\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\psi(Z_{i})}\right)
⟶n→∞ℙ​𝔼​[ψ⁡(Z)]​𝔼​[ℒ′​(Z,h0,f)2ψ⁡(Z)].\displaystyle\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}\left[\psi(Z)\right]\mathbb{E}\left[\frac{\mathcal{L}^{\prime}(Z,{h_{0}},f)^{2}}{\psi(Z)}\right].

Therefore

∑i=1n𝔼⁡[ηn,i2|ℱn,i−1]\displaystyle\sum_{i=1}^{n}\mathbb{E}\left[\eta_{n,i}^{2}\middle|{\mathcal{F}_{n,i-1}}\right] ⟶n→∞ℙ​𝔼​[𝔼​ψ​(Z)ψ⁡(Z)​ℒ′​(Z,h0,f)2]−c​𝔼​[ℒ′​(Z,h0,f)2]\displaystyle\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}\left[\frac{\mathbb{E}\psi(Z)}{\psi(Z)}\mathcal{L}^{\prime}(Z,{h_{0}},f)^{2}\right]-c\mathbb{E}\left[\mathcal{L}^{\prime}(Z,{h_{0}},f)^{2}\right]
=def​⟨ΣP,c∗​(ψ)​f,f⟩ℍ,\displaystyle\qquad\overset{\mathrm{def}}{=}\langle\Sigma^{*}_{\mathrm{P},c}(\psi)f,f\rangle_{\mathbb{H}},

where

ΣP,c∗​(ψ)​=def​𝔼​[𝔼​ψ​(Z)ψ⁡(Z)​ℓ′​(h0​(X),Y)2​KX⊗KX]−c​𝔼​[ℓ′​(h0​(X),Y)2​KX⊗KX].\Sigma^{*}_{\mathrm{P},c}(\psi)\overset{\mathrm{def}}{=}\mathbb{E}\left[\frac{\mathbb{E}\psi(Z)}{\psi(Z)}\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-c\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right].

Moreover, let us now show that the martingale difference array satisfies the conditional Lindeberg-Feller condition. Let ε>0\varepsilon>0,

∑i=1n𝔼[ηn,i2𝟙{|ηn,i|>ε}|𝒟n]\displaystyle\sum_{i=1}^{n}\mathbb{E}\left[\eta_{n,i}^{2}\mathbbm{1}_{\{|\eta_{n,i}|>\varepsilon\}}\middle|{\mathcal{D}_{n}}\right] ≤1ε2∑i=1n𝔼[ηn,i4𝟙{|ηn,i|>ε}|𝒟n]\displaystyle\leq\frac{1}{\varepsilon^{2}}\sum_{i=1}^{n}\mathbb{E}\left[\eta_{n,i}^{4}\mathbbm{1}_{\{|\eta_{n,i}|>\varepsilon\}}\middle|{\mathcal{D}_{n}}\right]
≤1ε2​∑i=1n𝔼⁡[ηn,i4|𝒟n]\displaystyle\leq\frac{1}{\varepsilon^{2}}\sum_{i=1}^{n}\mathbb{E}\left[\eta_{n,i}^{4}\middle|{\mathcal{D}_{n}}\right]
=1ε2​∑i=1nℒ′​(Zi,h0,f)4n4​sn2​πn,i4​𝔼​[(δn,i−sn​πn,i)4|𝒟n].\displaystyle=\frac{1}{\varepsilon^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{4}}{n^{4}s_{n}^{2}\pi_{n,i}^{4}}\mathbb{E}\left[(\delta_{n,i}-s_{n}\pi_{n,i})^{4}\middle|{\mathcal{D}_{n}}\right].

Furthermore

𝔼⁡[(δn,i−sn​πn,i)4|𝒟n]=p⁡(1−p)​(1−3​p​(1−p))≤4​p,\mathbb{E}\left[(\delta_{n,i}-s_{n}\pi_{n,i})^{4}\middle|{\mathcal{D}_{n}}\right]=p(1-p)(1-3p(1-p))\leq 4p,

where p​=def​sn​πn,i∈[0,1]p\overset{\mathrm{def}}{=}s_{n}\pi_{n,i}\in[0,1], since 1−p≤11-p\leq 1 and 3​p2−3​p≤33p^{2}-3p\leq 3. Hence bounding the forth order moment yields

∑i=1n𝔼[ηn,i2𝟙{|ηn,i|>ε}|𝒟n]\displaystyle\sum_{i=1}^{n}\mathbb{E}\left[\eta_{n,i}^{2}\mathbbm{1}_{\{|\eta_{n,i}|>\varepsilon\}}\middle|{\mathcal{D}_{n}}\right] ≤1n4​ε2​∑i=1np⁡(1−p)​(1−3​p​(1−p))p2​πn,i2​ℒ′​(Zi,h0,f)4\displaystyle\leq\frac{1}{n^{4}\varepsilon^{2}}\sum_{i=1}^{n}\frac{p(1-p)(1-3p(1-p))}{p^{2}\pi_{n,i}^{2}}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{4}
≤4n4​ε2​∑i=1n1p​πn,i2​ℒ′​(Zi,h0,f)4\displaystyle\leq\frac{4}{n^{4}\varepsilon^{2}}\sum_{i=1}^{n}\frac{1}{p\pi_{n,i}^{2}}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{4}
=4sn​ε2​max1≤i≤n​{1n​πn,i}3​(1n​∑i=1nℒ′​(Zi,h0,f)4).\displaystyle=\frac{4}{s_{n}\varepsilon^{2}}\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{3}\left(\frac{1}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{4}\right).

However, by Assumption 5 there exists M>0M>0 and N∈ℕN\in\mathbb{N} such that for all n≥Nn\geq N,

𝔼⁡[max1≤i≤n⁡{1n​πn,i}2]≤M2,\mathbb{E}\left[\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{2}\right]\leq M^{2},

hence for all ε>0\varepsilon>0,

ℙ(max1≤i≤n{1n​πn,i}3>M3/2ε−3/2)\displaystyle\mathbb{P}\left(\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{3}>M^{3/2}\varepsilon^{-3/2}\right) =ℙ⁡(max1≤i≤n⁡{1n​πn,i}2>M​ε−1)\displaystyle=\mathbb{P}\left(\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{2}>M\varepsilon^{-1}\right)
≤εM2​𝔼​[max1≤i≤n⁡{1n​πn,i}2]\displaystyle\leq\frac{\varepsilon}{M^{2}}\mathbb{E}\left[\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{2}\right]
≤ε.\displaystyle\leq\varepsilon.

Therefore max1≤i≤n⁡{n​πn,i}−3=Oℙ​(1)\max_{1\leq i\leq n}\left\{n\pi_{n,i}\right\}^{-3}=O_{\mathbb{P}}(1). Moreover, by Assumption 3

1n​∑i=1nℒ′​(Zi,h0,f)4=Oℙ​(1),\frac{1}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{4}=O_{\mathbb{P}}(1),

thus

∑i=1n𝔼[ηn,i2𝟙{|ηn,i|>ε}|𝒟n]≤4sn​εmax1≤i≤n{1n​πn,i}3(1n∑i=1nℒ′(Zi,h0,f)4)⟶n→∞ℙ0,\sum_{i=1}^{n}\mathbb{E}\left[\eta_{n,i}^{2}\mathbbm{1}_{\{|\eta_{n,i}|>\varepsilon\}}\middle|{\mathcal{D}_{n}}\right]\leq\frac{4}{s_{n}\varepsilon}\max_{1\leq i\leq n}\left\{\frac{1}{n\pi_{n,i}}\right\}^{3}\left(\frac{1}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{4}\right)\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0,

and from Theorem A.7

∏i=1n𝔼⁡[ei​t​ηn,i|ℱn,i−1]​⟶n→∞ℙ​e−12​t2​⟨ΣP,c∗​(ψ)​f,f⟩ℍ.\prod_{i=1}^{n}\mathbb{E}\left[e^{it\eta_{n,i}}\middle|{\mathcal{F}_{n,i-1}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}e^{-\frac{1}{2}t^{2}\langle\Sigma^{*}_{\mathrm{P},c}(\psi)f,f\rangle_{\mathbb{H}}}.

Finally, 𝔼⁡[ei​t​ηn,i|ℱn,i−1]=𝔼⁡[ei​t​ηn,i|𝒟n]\mathbb{E}\left[e^{it\eta_{n,i}}\middle|{\mathcal{F}_{n,i-1}}\right]=\mathbb{E}\left[e^{it\eta_{n,i}}\middle|{\mathcal{D}_{n}}\right] and conditionally to 𝒟n{\mathcal{D}_{n}}, ηn,1,…,ηn,n\eta_{n,1},\dots,\eta_{n,n} are independent hence

𝔼⁡[exp⁡(i​t​Ssn∗)|𝒟n]=∏i=1n𝔼⁡[exp⁡(i​t​ηn,i)|ℱn,i−1]​⟶n→∞ℙ​exp⁡(−12​t2​⟨ΣP,c∗​(ψ)​f,f⟩ℍ).∎\mathbb{E}\left[\exp\left(itS_{s_{n}}^{*}\right)\middle|{\mathcal{D}_{n}}\right]=\prod_{i=1}^{n}\mathbb{E}\left[\exp\left(it\eta_{n,i}\right)\middle|{\mathcal{F}_{n,i-1}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\exp\left(-\frac{1}{2}t^{2}\langle\Sigma^{*}_{\mathrm{P},c}(\psi)f,f\rangle_{\mathbb{H}}\right).\qed

We can now prove the main theorem using the above intermediate results.

Proof of Theorem 3.3.

Following the same steps as in the proof of Theorem 3.2, one has

sn​∇2ℛ​(h0)​(hsn∗−h0)+oℙ​(1)\displaystyle\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}})+o_{\mathbb{P}}(1) =−sn​(∇Lsn∗​(h0)−∇Ln​(h0))\displaystyle=-\sqrt{s_{n}}(\nabla{L}^{*}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}}))
−snn​n​(∇Ln​(h0)−∇L​(h0)).\displaystyle\qquad-\sqrt{\frac{s_{n}}{n}}\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})).

Applying A.12 with ℱn=σ⁡(𝒟n){\mathcal{F}_{n}}=\sigma({\mathcal{D}_{n}}) and Hn=sn​(∇Lsn∗​(h0)−∇Ln​(h0))H_{n}=\sqrt{s_{n}}(\nabla{L}^{*}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}})), together with Lemmas A.14 and A.11 yields

sn​∇2ℛ​(h0)​(hsn∗−h0)​⟶n→∞d​𝒢​(0,ΣP,c∗​(ψ)+c​Σ).∎\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h^{*}_{s_{n}}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma^{*}_{\mathrm{P},c}(\psi)+c\Sigma).\qed

A.6 Proof of Corollary 3.4 and Corollary 3.5

Proof.

First notice that taking a constant importance ψ\psi yields uniform probabilities and that both respectively verify Assumptions 5 and 6. Thus, apply Theorems 3.2 and 3.3 with constant ψ≡1\psi\equiv 1. This yields

ΣM∗​(ψ)=𝔼⁡[ℓ′​(h0​(X),Y)2​KX⊗KX]−∇L​(h0)⊗∇L​(h0)=Σ,\Sigma^{*}_{\mathrm{M}}(\psi)=\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right]-\nabla{L}({h_{0}})\otimes\nabla{L}({h_{0}})=\Sigma,

and

ΣP,c∗​(ψ)=(1−c)​𝔼​[ℓ′​(h0​(X),Y)2​KX⊗KX].\Sigma^{*}_{\mathrm{P},c}(\psi)=(1-c)\mathbb{E}\left[\ell^{\prime}({h_{0}}(X),Y)^{2}K_{X}\otimes K_{X}\right].

Which concludes the proof. ∎

A.7 Proof of Proposition 4.1

Proof.

Let ψ:𝒵→ℝ+∗\psi:\mathcal{Z}\rightarrow\mathbb{R}^{*}_{+}. By Cauchy-Schwarz, one has

tr⁡(ΣM∗​(ψ))\displaystyle\Tr(\Sigma^{*}_{\mathrm{M}}(\psi)) =𝔼⁡[ψ⁡(Z)]​𝔼​[1ψ⁡(Z)​ℓ′​(h0​(X),Y)2​k​(X,X)]−‖∇L​(h0)‖ℍ2\displaystyle=\mathbb{E}\left[\psi(Z)\right]\mathbb{E}\left[\frac{1}{\psi(Z)}\ell^{\prime}({h_{0}}(X),Y)^{2}k(X,X)\right]-\|\nabla{L}({h_{0}})\|_{\mathbb{H}}^{2}
≥𝔼​[ψ⁡(Z)ψ⁡(Z)​ℓ′​(h0​(X),Y)2​k​(X,X)]2−‖∇L​(h0)‖ℍ2\displaystyle\geq\mathbb{E}\left[\sqrt{\frac{\psi(Z)}{\psi(Z)}\ell^{\prime}({h_{0}}(X),Y)^{2}k(X,X)}\right]^{2}-\|\nabla{L}({h_{0}})\|_{\mathbb{H}}^{2}
=𝔼​[|ℓ′​(h0​(X),Y)|​k⁡(X,X)]2−‖∇L​(h0)‖ℍ2,\displaystyle=\mathbb{E}\left[|\ell^{\prime}({h_{0}}(X),Y)|\sqrt{k(X,X)}\right]^{2}-\|\nabla{L}({h_{0}})\|_{\mathbb{H}}^{2},

with equality if and only if ψ⁡(Z)∝ψ​(Z)−1​ℓ′​(h0​(X),Y)2​k​(X,X)\psi(Z)\propto\psi(Z)^{-1}\ell^{\prime}({h_{0}}(X),Y)^{2}k(X,X) or equivalently ψ⁡(Z)∝|ℓ′​(h0​(X),Y)|​k​(X,X)1/2\psi(Z)\propto|\ell^{\prime}({h_{0}}(X),Y)|k(X,X)^{1/2}. Thus, ψ⋆​(Z)​=def​|ℓ′​(h0​(X),Y)|​k⁡(X,X)\psi^{\star}(Z)\overset{\mathrm{def}}{=}|\ell^{\prime}({h_{0}}(X),Y)|\sqrt{k(X,X)} is a minimizer of ψ↦tr⁡(Σ∗​(ψ))\psi\mapsto\Tr(\Sigma^{*}(\psi)). ∎

A.8 Proof of Theorem 5.1

In this section, denote for all n>0n>0 and i∈{1,…,n}i\in\{1,\dots,n\},

ψi=|ℓ′​(h0​(Xi),Yi)|​k⁡(Xi,Xi)andψn,i=|ℓ′​(h^kn​(Xi),Yi)|​k⁡(Xi,Xi),\displaystyle\psi_{i}=|\ell^{\prime}({h_{0}}(X_{i}),Y_{i})|\sqrt{k(X_{i},X_{i})}\quad\text{and}\quad\psi_{n,i}=|\ell^{\prime}({\hat{h}_{k_{n}}}(X_{i}),Y_{i})|\sqrt{k(X_{i},X_{i})},

such that π~n,i∝ψn,i\tilde{\pi}_{n,i}\propto\psi_{n,i} and

π~n,iα=(1−α)​π~n,i+α​1n.\tilde{\pi}_{n,i}^{\alpha}=(1-\alpha)\tilde{\pi}_{n,i}+\alpha\frac{1}{n}.

As π~n,iα≥α​n−1\tilde{\pi}_{n,i}^{\alpha}\geq\alpha n^{-1} for all i∈{1,…,n}i\in\{1,\dots,n\} then

𝔼⁡[max1≤i≤n⁡{1n​π~n,iα}2]≤1α2,\mathbb{E}\left[\max_{1\leq i\leq n}\left\{\frac{1}{n\tilde{\pi}_{n,i}^{\alpha}}\right\}^{2}\right]\leq\frac{1}{\alpha^{2}},

hence the sequence of probability vectors (𝝅~nα)n>0(\tilde{\bm{\pi}}_{n}^{\alpha})_{n>0} verifies Assumption 5, thus we can deduce the consistency of hsn∗α{h_{s_{n}}^{*\alpha}} by application of Theorem 3.1. Therefore

‖hsn∗α−h0‖ℍ​⟶n→∞ℙ​0.\|{h_{s_{n}}^{*\alpha}}-{h_{0}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0. (A.15)

Moreover, the results of Lemmas A.10 and A.11 still apply, if replacing hsn∗{h^{*}_{s_{n}}} by hsn∗α{h_{s_{n}}^{*\alpha}} and ∇Lsn∗\nabla{L}^{*}_{s_{n}} by ∇Lsn∗α\nabla{L}^{*\alpha}_{s_{n}}, because (𝝅~nα)n>0(\tilde{\bm{\pi}}_{n}^{\alpha})_{n>0} verifies Assumption 5.

Lemma A.15.

Under Assumptions 1, 2, 3 and ’ ‣ 3, if h^kn​⟶n→∞ℙ​h0{\hat{h}_{k_{n}}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}{h_{0}}, one has for all t∈ℝt\in\mathbb{R} and f∈ℍf\in\mathbb{H},

𝔼[exp(itSsn∗α)|𝒟n,h^kn]⟶n→∞ℙexp(−12t2⟨ΣM∗(α)f,f⟩ℍ),\mathbb{E}\left[\exp\left(itS_{s_{n}}^{*\alpha}\right)\middle|{\mathcal{D}_{n}},{\hat{h}_{k_{n}}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\exp\left(-\frac{1}{2}t^{2}\langle\Sigma^{*}_{\mathrm{M}}(\alpha)f,f\rangle_{\mathbb{H}}\right),

with

Ssn∗α​=def​sn​⟨∇Lsn∗α​(h0)−∇Ln​(h0),f⟩ℍ,\displaystyle S_{s_{n}}^{*\alpha}\overset{\mathrm{def}}{=}\sqrt{s_{n}}\langle\nabla{L}^{*\alpha}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}},
∇Lsn∗α(h0)=1sn∑j=1sn∑i=1nOPENℓ′​(h0​(Xi),Yi))n​π~n,iαKXi𝟙{In,j=i},\displaystyle\nabla{L}^{*\alpha}_{s_{n}}({h_{0}})=\frac{1}{s_{n}}\sum_{j=1}^{s_{n}}\sum_{i=1}^{n}\frac{\ell^{\prime}({h_{0}}(X_{i}),Y_{i}))}{n\tilde{\pi}_{n,i}^{\alpha}}K_{X_{i}}\mathbbm{1}_{\{I_{n,j}=i\}},

and

ΣM∗​(α)​=def​𝔼​[𝔼⁡[ψ⋆​(Z)]​ℓ′​(h0​(X),Y)2(1−α)​ψ⋆​(Z)+α​𝔼​[ψ⋆​(Z)]​KX⊗KX]−∇L​(h0)⊗∇L​(h0).\Sigma^{*}_{\mathrm{M}}(\alpha)\overset{\mathrm{def}}{=}\mathbb{E}\left[\frac{\mathbb{E}\left[\psi^{\star}(Z)\right]\ell^{\prime}({h_{0}}(X),Y)^{2}}{(1-\alpha)\psi^{\star}(Z)+\alpha\mathbb{E}\left[\psi^{\star}(Z)\right]}K_{X}\otimes K_{X}\right]-\nabla{L}({h_{0}})\otimes\nabla{L}({h_{0}}).
Proof.

As per the proof of Lemma A.13, the goal is to apply Theorem A.7. The only differences lie in the sequence of filtration to handle a martingale difference array, the conditional variance and its limit. As the rest remains unchanged, this is what we will focus on in this proof. Let f∈ℍf\in\mathbb{H}. Define Ssn∗α​=def​⟨sn​(∇Lsn∗α−∇Ln)​(h0),f⟩ℍS_{s_{n}}^{*\alpha}\overset{\mathrm{def}}{=}\langle\sqrt{s_{n}}(\nabla{L}^{*\alpha}_{s_{n}}-\nabla{L}_{n})({h_{0}}),f\rangle_{\mathbb{H}} a real-valued random variable and ℒ′​(Z,h,f)​=def​ℓ′​(h⁡(X),Y)​f​(X)\mathcal{L}^{\prime}(Z,h,f)\overset{\mathrm{def}}{=}\ell^{\prime}(h(X),Y)f(X), then

Ssn∗α\displaystyle S_{s_{n}}^{*\alpha} =∑j=1sn1sn(1n∑i=1nℒ′​(Zi,h0,f)π~n,iα𝟙{In,j=i}−⟨∇Ln(h0),f⟩ℍ)\displaystyle=\sum_{j=1}^{s_{n}}\frac{1}{\sqrt{s_{n}}}\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\tilde{\pi}_{n,i}^{\alpha}}\mathbbm{1}_{\{I_{n,j}=i\}}-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}\right)
=∑j=1snη~n,j,\displaystyle=\sum_{j=1}^{s_{n}}\tilde{\eta}_{n,j},

where

η~n,j=def1sn(1n∑i=1nℒ′​(Zi,h0,f)π~n,iα𝟙{In,j=i}−⟨∇Ln(h0),f⟩ℍ),\tilde{\eta}_{n,j}\overset{\mathrm{def}}{=}\frac{1}{\sqrt{s_{n}}}\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\tilde{\pi}_{n,i}^{\alpha}}\mathbbm{1}_{\{I_{n,j}=i\}}-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}\right),

for all n∈ℕn\in\mathbb{N} and j∈{1,…,sn}j\in\{1,\dots,s_{n}\}. Moreover, define the filtrations (ℱ~n,j)n∈ℕ,0≤j≤sn({\tilde{\mathcal{F}}_{n,j}})_{n\in\mathbb{N},0\leq j\leq s_{n}} such that ℱ~n,j{\tilde{\mathcal{F}}_{n,j}} is the σ\sigma-algebra generated by 𝒟n{\mathcal{D}_{n}}, h^kn{\hat{h}_{k_{n}}} and In,1,…,In,jI_{n,1},\dots,I_{n,j} for 0≤j≤sn0\leq j\leq s_{n} and n∈ℕn\in\mathbb{N}. Notice that for all n∈ℕn\in\mathbb{N} and j∈{1,…,sn}j\in\{1,\dots,s_{n}\} the conditional distributions of η~n,j\tilde{\eta}_{n,j} with respect to (𝒟n,h^kn)({\mathcal{D}_{n}},{\hat{h}_{k_{n}}}) and ℱ~n,j−1{\tilde{\mathcal{F}}_{n,j-1}} are the same. Remark as well that, conditionally to 𝒟n{\mathcal{D}_{n}} and h^kn{\hat{h}_{k_{n}}}, Ssn∗S_{s_{n}}^{*} is a sum of i.i.d. random variables such that 𝔼[η~n,j|𝒟n,h^kn]=0\mathbb{E}\left[\tilde{\eta}_{n,j}\middle|{\mathcal{D}_{n}},{\hat{h}_{k_{n}}}\right]=0 since ℙ(In,j=i|𝒟n,h^kn)=π~n,iα\mathbb{P}\left(I_{n,j}=i\middle|{\mathcal{D}_{n}},{\hat{h}_{k_{n}}}\right)=\tilde{\pi}_{n,i}^{\alpha}. Hence {η~n,j:n∈ℕ,1≤j≤sn}\{\tilde{\eta}_{n,j}:n\in\mathbb{N},1\leq j\leq s_{n}\} is a martingale difference array for the filtration (ℱ~n,j)n∈ℕ,1≤j≤sn({\tilde{\mathcal{F}}_{n,j}})_{n\in\mathbb{N},1\leq j\leq s_{n}}. Moreover, its conditional variance reads

∑j=1sn𝔼⁡[η~n,j2|ℱ~n,j−1]\displaystyle\sum_{j=1}^{s_{n}}\mathbb{E}\left[\tilde{\eta}_{n,j}^{2}\middle|{\tilde{\mathcal{F}}_{n,j-1}}\right] =sn𝔼[η~n,12|𝒟n,h^kn]\displaystyle=s_{n}\mathbb{E}\left[\tilde{\eta}_{n,1}^{2}\middle|{\mathcal{D}_{n}},{\hat{h}_{k_{n}}}\right]
=𝔼[(1n∑i=1nℒ′​(Zi,h0,f)π~n,iα𝟙{In,j=i}−⟨∇Ln(h0),f⟩ℍ)2|𝒟n,h^kn].\displaystyle=\mathbb{E}\left[\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\tilde{\pi}_{n,i}^{\alpha}}\mathbbm{1}_{\{I_{n,j}=i\}}-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}\right)^{2}\middle|{\mathcal{D}_{n}},{\hat{h}_{k_{n}}}\right].

Since 𝔼[1n∑i=1nℒ′​(Zi,h0,f)π~n,iα𝟙{In,j=i}|𝒟n,h^kn]=⟨∇Ln(h0),f⟩ℍ\mathbb{E}\left[\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\tilde{\pi}_{n,i}^{\alpha}}\mathbbm{1}_{\{I_{n,j}=i\}}\middle|{\mathcal{D}_{n}},{\hat{h}_{k_{n}}}\right]=\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}, the previous display reads

∑j=1sn𝔼[η~n,j2|ℱ~n,j−1]=𝔼[(1n∑i=1nℒ′​(Zi,h0,f)π~n,iα𝟙{In,j=i})2|𝒟n,h^kn]−⟨∇Ln(h0),f⟩ℍ2.\sum_{j=1}^{s_{n}}\mathbb{E}\left[\tilde{\eta}_{n,j}^{2}\middle|{\tilde{\mathcal{F}}_{n,j-1}}\right]=\mathbb{E}\left[\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\tilde{\pi}_{n,i}^{\alpha}}\mathbbm{1}_{\{I_{n,j}=i\}}\right)^{2}\middle|{\mathcal{D}_{n}},{\hat{h}_{k_{n}}}\right]-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}^{2}.

However only one term in the sum is non-zero. Thus

∑j=1sn𝔼⁡[η~n,j2|ℱ~n,j−1]\displaystyle\sum_{j=1}^{s_{n}}\mathbb{E}\left[\tilde{\eta}_{n,j}^{2}\middle|{\tilde{\mathcal{F}}_{n,j-1}}\right] =1n2∑i=1n(ℒ′​(Zi,h0,f)π~n,iα)2ℙ(In,j=i|𝒟n,h^kn)−⟨∇Ln(h0),f⟩ℍ2\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\left(\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{\tilde{\pi}_{n,i}^{\alpha}}\right)^{2}\mathbb{P}\left(I_{n,j}=i\middle|{\mathcal{D}_{n}},{\hat{h}_{k_{n}}}\right)-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}^{2}
=1n2​∑i=1nℒ′​(Zi,h0,f)2π~n,iα−⟨∇Ln​(h0),f⟩ℍ2.\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\tilde{\pi}_{n,i}^{\alpha}}-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}^{2}.

Furthermore

π~n,iα=(1−α)​π~n,i+αn=(1−α)​ψn,i+αn​∑j=1nψn,j∑j=1nψn,j,\displaystyle\tilde{\pi}_{n,i}^{\alpha}=(1-\alpha)\tilde{\pi}_{n,i}+\frac{\alpha}{n}=\frac{(1-\alpha)\psi_{n,i}+\frac{\alpha}{n}\sum_{j=1}^{n}\psi_{n,j}}{\sum_{j=1}^{n}\psi_{n,j}},

hence

1n2​∑i=1nℒ′​(Zi,h0,f)2π~n,iα=(1n​∑j=1nψn,j)​(1n​∑i=1nℒ′​(Zi,h0,f)2(1−α)​ψn,i+αn​∑j=1nψn,j).\displaystyle\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\tilde{\pi}_{n,i}^{\alpha}}=\left(\frac{1}{n}\sum_{j=1}^{n}\psi_{n,j}\right)\left(\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{(1-\alpha)\psi_{n,i}+\frac{\alpha}{n}\sum_{j=1}^{n}\psi_{n,j}}\right).

Denote ψiα​=def​(1−α)​ψi+α​𝔼​ψ⋆​(Z)\psi_{i}^{\alpha}\overset{\mathrm{def}}{=}(1-\alpha)\psi_{i}+\alpha\mathbb{E}\psi^{\star}(Z) and ψn,iα​=def​(1−α)​ψn,i+αn​∑j=1nψn,j\psi_{n,i}^{\alpha}\overset{\mathrm{def}}{=}(1-\alpha)\psi_{n,i}+\frac{\alpha}{n}\sum_{j=1}^{n}\psi_{n,j}. Hence for all n>0n>0 and i∈{1,…,n}i\in\{1,\dots,n\},

ψiα≥α​𝔼​ψ⋆​(Z)andψn,iα≥αn​∑j=1nψn,j.\psi_{i}^{\alpha}\geq\alpha\mathbb{E}\psi^{\star}(Z)\quad\text{and}\quad\psi_{n,i}^{\alpha}\geq\frac{\alpha}{n}\sum_{j=1}^{n}\psi_{n,j}.

Therefore by the triangle inequality

|1ψn,iα−1ψiα|\displaystyle\left|\frac{1}{\psi_{n,i}^{\alpha}}-\frac{1}{\psi_{i}^{\alpha}}\right| =|ψn,iα−ψiα|ψn,iα​ψiα\displaystyle=\frac{|\psi_{n,i}^{\alpha}-\psi_{i}^{\alpha}|}{\psi_{n,i}^{\alpha}\psi_{i}^{\alpha}}
≤nα2​(∑j=1nψn,j)​𝔼​ψ​((1−α)​|ψn,i−ψi|+α​|1n​∑j=1nψn,j−𝔼​ψ⋆​(Z)|),\displaystyle\leq\frac{n}{\alpha^{2}(\sum_{j=1}^{n}\psi_{n,j})\mathbb{E}\psi}\left((1-\alpha)|\psi_{n,i}-\psi_{i}|+\alpha\left|\frac{1}{n}\sum_{j=1}^{n}\psi_{n,j}-\mathbb{E}\psi^{\star}(Z)\right|\right),

and consequently

|1n​∑i=1nℒ′​(Zi,h0,f)2ψn,iα−1n​∑i=1nℒ′​(Zi,h0,f)2ψiα|\displaystyle\left|\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\psi_{n,i}^{\alpha}}-\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\psi_{i}^{\alpha}}\right|
≤nα2​(∑j=1nψn,j)​𝔼​ψ​((1−α)​1n​∑i=1nℒ′​(Zi,h0,f)2​|ψn,i−ψi|CLOSE\displaystyle\quad\leq\frac{n}{\alpha^{2}(\sum_{j=1}^{n}\psi_{n,j})\mathbb{E}\psi}\Bigg((1-\alpha)\frac{1}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}|\psi_{n,i}-\psi_{i}|
OPEN+α​|1n​∑j=1nψn,j−𝔼​ψ⋆​(Z)|​(1n​∑i=1nℒ′​(Zi,h0,f)2)).\displaystyle\hskip 142.26378pt+\alpha\left|\frac{1}{n}\sum_{j=1}^{n}\psi_{n,j}-\mathbb{E}\psi^{\star}(Z)\right|\bigg(\frac{1}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}\bigg)\Bigg).

Moreover, for all n∈ℕn\in\mathbb{N}, and i∈{1,…,n}i\in\{1,\dots,n\},

|ψn,i−ψi|𝟙{∥h^kn−h0∥ℍ<1}\displaystyle|\psi_{n,i}-\psi_{i}|\mathbbm{1}_{\{\|{\hat{h}_{k_{n}}}-{h_{0}}\|_{\mathbb{H}}<1\}}
≤k⁡(Xi,Xi)|ℓ′(h^kn(Xi),Yi)−ℓ′(h0(Xi),Yi)|𝟙{∥h^kn−h0∥ℍ<1}\displaystyle\quad\leq\sqrt{k(X_{i},X_{i})}|\ell^{\prime}({\hat{h}_{k_{n}}}(X_{i}),Y_{i})-\ell^{\prime}({h_{0}}(X_{i}),Y_{i})|\mathbbm{1}_{\{\|{\hat{h}_{k_{n}}}-{h_{0}}\|_{\mathbb{H}}<1\}}
≤κϕ(Yi)|h^kn(Xi)−h0(Xi)|𝟙{∥h^kn−h0∥ℍ<1}\displaystyle\quad\leq\kappa\phi(Y_{i})|{\hat{h}_{k_{n}}}(X_{i})-{h_{0}}(X_{i})|\mathbbm{1}_{\{\|{\hat{h}_{k_{n}}}-{h_{0}}\|_{\mathbb{H}}<1\}}
≤κ2​‖h^kn−h0‖ℍ​ϕ​(Yi),\displaystyle\quad\leq\kappa^{2}\|{\hat{h}_{k_{n}}}-{h_{0}}\|_{\mathbb{H}}\phi(Y_{i}),

using Assumption 2. Thus, together with Assumption 3 and h^kn{\hat{h}_{k_{n}}}’s consistency, the previous inequality yields

1n∑i=1nℒ′(Zi,h0,f)2|ψn,i−ψi|𝟙{∥h^kn−h0∥ℍ<1}⟶n→∞ℙ0.\displaystyle\frac{1}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}|\psi_{n,i}-\psi_{i}|\mathbbm{1}_{\{\|{\hat{h}_{k_{n}}}-{h_{0}}\|_{\mathbb{H}}<1\}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.

Whence applying Lemma A.6 with En={∥h^kn−h0∥≥1}E_{n}=\{\|{\hat{h}_{k_{n}}}-{h_{0}}\|\geq 1\} along with the previous display yields

1n​∑i=1nℒ′​(Zi,h0,f)2​|ψn,i−ψi|​⟶n→∞ℙ​0.\displaystyle\frac{1}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}|\psi_{n,i}-\psi_{i}|\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.

Similarly n−1​∑i=1n|ψn,i−ψi|​⟶n→∞ℙ​0n^{-1}\sum_{i=1}^{n}|\psi_{n,i}-\psi_{i}|\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0, which implies that n−1​∑i=1nψn,i​⟶n→∞ℙ​𝔼​ψ⋆​(Z)n^{-1}\sum_{i=1}^{n}\psi_{n,i}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}\psi^{\star}(Z). Hence

|1n​∑i=1nℒ′​(Zi,h0,f)2ψn,iα−1n​∑i=1nℒ′​(Zi,h0,f)2ψiα|​⟶n→∞ℙ​0.\left|\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\psi_{n,i}^{\alpha}}-\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\psi_{i}^{\alpha}}\right|\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.

However

1n​∑i=1nℒ′​(Zi,h0,f)2ψiα​⟶n→∞ℙ​𝔼​[ℒ′​(Z,h0,f)2(1−α)​ψ⋆​(Z)+α​𝔼​[ψ⋆​(Z)]],\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\psi_{i}^{\alpha}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}\left[\frac{\mathcal{L}^{\prime}(Z,{h_{0}},f)^{2}}{(1-\alpha)\psi^{\star}(Z)+\alpha\mathbb{E}\left[\psi^{\star}(Z)\right]}\right],

which yields

∑j=1sn𝔼⁡[η~n,j2|ℱ~n,j−1]\displaystyle\sum_{j=1}^{s_{n}}\mathbb{E}\left[\tilde{\eta}_{n,j}^{2}\middle|{\tilde{\mathcal{F}}_{n,j-1}}\right] =1n2​∑i=1nℒ′​(Zi,h0,f)2π~n,iα−⟨∇Ln​(h0),f⟩ℍ2\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\tilde{\pi}_{n,i}^{\alpha}}-\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}^{2}
⟶n→∞ℙ​𝔼​[𝔼⁡[ψ⋆​(Z)]​ℒ′​(Z,h0,f)2(1−α)​ψ⋆​(Z)+α​𝔼​[ψ⋆​(Z)]]−⟨∇L​(h0),f⟩ℍ2.\displaystyle\quad\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}\left[\frac{\mathbb{E}\left[\psi^{\star}(Z)\right]\mathcal{L}^{\prime}(Z,{h_{0}},f)^{2}}{(1-\alpha)\psi^{\star}(Z)+\alpha\mathbb{E}\left[\psi^{\star}(Z)\right]}\right]-\langle\nabla{L}({h_{0}}),f\rangle_{\mathbb{H}}^{2}.

Which concludes the proof. ∎

Proof of Theorem 5.1.

Since Assumption 5 is verified, by application of A.10 and following the proof of Theorem 3.2, one gets

sn​∇2ℛ​(h0)​(hsn∗α−h0)+oℙ​(1)\displaystyle\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h_{s_{n}}^{*\alpha}}-{h_{0}})+o_{\mathbb{P}}(1) =−sn​(∇Lsn∗α​(h0)−∇Ln​(h0))\displaystyle=-\sqrt{s_{n}}(\nabla{L}^{*\alpha}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}}))
−snn​n​(∇Ln​(h0)−∇L​(h0)).\displaystyle\qquad-\sqrt{\frac{s_{n}}{n}}\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})).

Applying A.12 with ℱn=σ⁡(𝒟n,h^kn){\mathcal{F}_{n}}=\sigma({\mathcal{D}_{n}},{\hat{h}_{k_{n}}}) and Hn=sn​(∇Lsn∗α​(h0)−∇Ln​(h0))H_{n}=\sqrt{s_{n}}(\nabla{L}^{*\alpha}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}})), together with Lemmas A.11 and A.15 yields

sn​∇2ℛ​(h0)​(hsn∗α−h0)​⟶n→∞d​𝒢​(0,ΣM∗​(α)+c​Σ).∎\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h_{s_{n}}^{*\alpha}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma^{*}_{\mathrm{M}}(\alpha)+c\Sigma).\qed

A.9 Proof of Theorem 5.2

In this section, as of the previous one, denote for all n>0n>0 and i∈{1,…,n}i\in\{1,\dots,n\},

ψi=|ℓ′​(h0​(Xi),Yi)|​k⁡(Xi,Xi)andψn,i=|ℓ′​(h^kn​(Xi),Yi)|​k⁡(Xi,Xi),\displaystyle\psi_{i}=|\ell^{\prime}({h_{0}}(X_{i}),Y_{i})|\sqrt{k(X_{i},X_{i})}\quad\text{and}\quad\psi_{n,i}=|\ell^{\prime}({\hat{h}_{k_{n}}}(X_{i}),Y_{i})|\sqrt{k(X_{i},X_{i})},

such that π~n,i∝ψn,i\tilde{\pi}_{n,i}\propto\psi_{n,i} and

π~n,iα=(1−α)​π~n,i+α​1n.\tilde{\pi}_{n,i}^{\alpha}=(1-\alpha)\tilde{\pi}_{n,i}+\alpha\frac{1}{n}.

As π~n,iα≥α​n−1\tilde{\pi}_{n,i}^{\alpha}\geq\alpha n^{-1} for all i∈{1,…,n}i\in\{1,\dots,n\} then π~n,iα∧sn−1≥(α​n−1)∧sn−1≥α​n−1\tilde{\pi}_{n,i}^{\alpha}\wedge s_{n}^{-1}\geq(\alpha n^{-1})\wedge s_{n}^{-1}\geq\alpha n^{-1} since α∈(0,1)\alpha\in(0,1) and n≥snn\geq s_{n}. Therefore

𝔼⁡[max1≤i≤n⁡{1n⁡(π~n,iα∧sn−1)}2]≤1α2,\mathbb{E}\left[\max_{1\leq i\leq n}\left\{\frac{1}{n(\tilde{\pi}_{n,i}^{\alpha}\wedge s_{n}^{-1})}\right\}^{2}\right]\leq\frac{1}{\alpha^{2}},

hence the sequence of vectors (𝝅~nα∧sn−1)n>0(\tilde{\bm{\pi}}_{n}^{\alpha}\wedge s_{n}^{-1})_{n>0} verifies Assumption 5, thus we can deduce the consistency of hsn∗α{h_{s_{n}}^{*\alpha}} by application of Theorem 3.1. Therefore

‖hsn∗α−h0‖ℍ​⟶n→∞ℙ​0.\|{h_{s_{n}}^{*\alpha}}-{h_{0}}\|_{\mathbb{H}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0. (A.16)

Moreover, the results of Lemmas A.10 and A.11 still apply, if replacing hsn∗{h^{*}_{s_{n}}} by hsn∗α{h_{s_{n}}^{*\alpha}} and ∇Lsn∗\nabla{L}^{*}_{s_{n}} by ∇Lsn∗α\nabla{L}^{*\alpha}_{s_{n}}, because (𝝅~nα)n>0(\tilde{\bm{\pi}}_{n}^{\alpha})_{n>0} verifies Assumption 5.

Lemma A.16.

Under Assumptions 1, 2, 3 and ’ ‣ 3, if h^kn​⟶n→∞ℙ​h0{\hat{h}_{k_{n}}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}{h_{0}}, one has for all t∈ℝt\in\mathbb{R} and f∈ℍf\in\mathbb{H},

𝔼[exp(itSsn∗α)|𝒟n,h^kn]⟶n→∞ℙexp(−12t2⟨ΣP,c∗(α)f,f⟩ℍ),\mathbb{E}\left[\exp\left(itS_{s_{n}}^{*\alpha}\right)\middle|{\mathcal{D}_{n}},{\hat{h}_{k_{n}}}\right]\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\exp\left(-\frac{1}{2}t^{2}\langle\Sigma^{*}_{\mathrm{P},c}(\alpha)f,f\rangle_{\mathbb{H}}\right),

with

Ssn∗α​=def​sn​⟨∇Lsn∗α​(h0)−∇Ln​(h0),f⟩ℍ,\displaystyle S_{s_{n}}^{*\alpha}\overset{\mathrm{def}}{=}\sqrt{s_{n}}\langle\nabla{L}^{*\alpha}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}},
∇Lsn∗α​(h0)=1n​∑i=1nℓ′​(h0​(Xi),Yi)(sn​π~n,iα)∧1​KXi​δn,i,\displaystyle\nabla{L}^{*\alpha}_{s_{n}}({h_{0}})=\frac{1}{n}\sum_{i=1}^{n}\frac{\ell^{\prime}({h_{0}}(X_{i}),Y_{i})}{(s_{n}\tilde{\pi}_{n,i}^{\alpha})\wedge 1}K_{X_{i}}\delta_{n,i},

and

ΣP,c∗​(α)​=def​𝔼​[𝔼⁡[ψ⋆​(Z)]​ℓ′​(h0​(X),Y)2Ψα⋆​(Z)∧(c−1​𝔼​[ψ⋆​(Z)])​KX⊗KX]−c​𝔼​[ℓ′​(h0,(X),Y)2​KX⊗KX],\Sigma^{*}_{\mathrm{P},c}(\alpha)\overset{\mathrm{def}}{=}\mathbb{E}\left[\frac{\mathbb{E}\left[\psi^{\star}(Z)\right]\ell^{\prime}({h_{0}}(X),Y)^{2}}{\Psi^{\star}_{\alpha}(Z)\wedge(c^{-1}\mathbb{E}\left[\psi^{\star}(Z)\right])}K_{X}\otimes K_{X}\right]-c\mathbb{E}\left[\ell^{\prime}({h_{0}},(X),Y)^{2}K_{X}\otimes K_{X}\right],

where Ψα⋆​(Z)​=def​(1−α)​ψ⋆​(Z)+α​𝔼​ψ⋆​(Z)\Psi^{\star}_{\alpha}(Z)\overset{\mathrm{def}}{=}(1-\alpha)\psi^{\star}(Z)+\alpha\mathbb{E}\psi^{\star}(Z).

Proof.

As in the proof of Lemma A.14, the goal is to apply Theorem A.7. The only differences lie in the sequence of filtration to handle a martingale difference array, the conditional variance and its limit. As the rest remains unchanged, this is what we will focus on in this proof. Let f∈ℍf\in\mathbb{H}. Define Ssn∗α​=def​⟨sn​(∇Lsn∗α−∇Ln)​(h0),f⟩ℍS_{s_{n}}^{*\alpha}\overset{\mathrm{def}}{=}\langle\sqrt{s_{n}}(\nabla{L}^{*\alpha}_{s_{n}}-\nabla{L}_{n})({h_{0}}),f\rangle_{\mathbb{H}} a real-valued random variable and ℒ′​(Z,h,f)​=def​ℓ′​(h⁡(X),Y)​f​(X)\mathcal{L}^{\prime}(Z,h,f)\overset{\mathrm{def}}{=}\ell^{\prime}(h(X),Y)f(X), then

Ssn∗α\displaystyle S_{s_{n}}^{*\alpha} =snn​∑i=1nℒ′​(Zi,h0,f)(sn​π~n,iα)∧1​δn,i−sn​⟨∇Ln​(h0),f⟩ℍ\displaystyle=\frac{\sqrt{s_{n}}}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{(s_{n}\tilde{\pi}_{n,i}^{\alpha})\wedge 1}\delta_{n,i}-\sqrt{s_{n}}\langle\nabla{L}_{n}({h_{0}}),f\rangle_{\mathbb{H}}
=∑j=1snη~n,i,\displaystyle=\sum_{j=1}^{s_{n}}\tilde{\eta}_{n,i},

where

η~n,i​=def​ℒ′​(Zi,h0,f)n​sn​πˇn,iα​(δn,i−sn​πˇn,iα),\tilde{\eta}_{n,i}\overset{\mathrm{def}}{=}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{n\sqrt{s_{n}}\check{\pi}_{n,i}^{\alpha}}(\delta_{n,i}-s_{n}\check{\pi}_{n,i}^{\alpha}),

for all n∈ℕn\in\mathbb{N} and i∈{1,…,n}i\in\{1,\dots,n\}, with πˇn,iα=π~n,iα∧sn−1\check{\pi}_{n,i}^{\alpha}=\tilde{\pi}_{n,i}^{\alpha}\wedge s_{n}^{-1}. Moreover, define the filtrations (ℱ~n,i)n∈ℕ,0≤i≤n({\tilde{\mathcal{F}}_{n,i}})_{n\in\mathbb{N},0\leq i\leq n} such that ℱ~n,i{\tilde{\mathcal{F}}_{n,i}} is the σ\sigma-algebra generated by 𝒟n{\mathcal{D}_{n}}, h^kn{\hat{h}_{k_{n}}} and δn,1,…,δn,i\delta_{n,1},\dots,\delta_{n,i} for 0≤i≤n0\leq i\leq n and n∈ℕn\in\mathbb{N}. Notice that for all n∈ℕn\in\mathbb{N} and i∈{1,…,n}i\in\{1,\dots,n\} the conditional distributions of η~n,i\tilde{\eta}_{n,i} with respect to (𝒟n,h^kn)({\mathcal{D}_{n}},{\hat{h}_{k_{n}}}) and ℱ~n,i−1{\tilde{\mathcal{F}}_{n,i-1}} are the same. Remark as well that, conditionally to 𝒟n{\mathcal{D}_{n}} and h^kn{\hat{h}_{k_{n}}}, Ssn∗S_{s_{n}}^{*} is a sum of independent random variables such that 𝔼[η~n,j|𝒟n,h^kn]=0\mathbb{E}[\tilde{\eta}_{n,j}|{\mathcal{D}_{n}},{\hat{h}_{k_{n}}}]=0 since ℙ⁡(δn,j=i|𝒟n,h^kn)=sn​πˇn,iα\mathbb{P}(\delta_{n,j}=i|{\mathcal{D}_{n}},{\hat{h}_{k_{n}}})=s_{n}\check{\pi}_{n,i}^{\alpha}. Hence {η~n,i:n∈ℕ,1≤i≤n}\{\tilde{\eta}_{n,i}:n\in\mathbb{N},1\leq i\leq n\} is a martingale difference array for the filtration (ℱ~n,i)n∈ℕ,0≤i≤n({\tilde{\mathcal{F}}_{n,i}})_{n\in\mathbb{N},0\leq i\leq n}. Moreover, its conditional variance reads

∑i=1n𝔼⁡[η~n,i2|ℱ~n,i−1]\displaystyle\sum_{i=1}^{n}\mathbb{E}\left[\tilde{\eta}_{n,i}^{2}\middle|{\tilde{\mathcal{F}}_{n,i-1}}\right] =∑i=1n𝔼⁡[(ℒ′​(Zi,h0,f)n​sn​πˇn,iα​(δn,i−sn​πˇn,iα))2|ℱ~n,i−1]\displaystyle=\sum_{i=1}^{n}\mathbb{E}\left[\left(\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)}{n\sqrt{s_{n}}\check{\pi}_{n,i}^{\alpha}}(\delta_{n,i}-s_{n}\check{\pi}_{n,i}^{\alpha})\right)^{2}\middle|{\tilde{\mathcal{F}}_{n,i-1}}\right]
=1n2​∑i=1n(1−sn​πˇn,iα)πˇn,iα​ℒ′​(Zi,h0,f)2\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{(1-s_{n}\check{\pi}_{n,i}^{\alpha})}{\check{\pi}_{n,i}^{\alpha}}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}
=1n2​∑i=1nℒ′​(Zi,h0,f)2πˇn,iα−snn2​∑i=1nℒ′​(Zi,h0,f)2.\displaystyle=\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\check{\pi}_{n,i}^{\alpha}}-\frac{s_{n}}{n^{2}}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}.

By the law of large number and the assumption that sn/n​⟶n→∞​c∈[0,1]s_{n}/n\underset{n\rightarrow\infty}{\longrightarrow}c\in[0,1], the second term of the right hand side converges in probability to c​𝔼​[ℒ′​(Z,h0,f)2]c\mathbb{E}\left[\mathcal{L}^{\prime}(Z,{h_{0}},f)^{2}\right]. For the first term, denote

πiα​=def​(1−α)​ψi𝔼​ψ⋆​(Z)+α,\pi_{i}^{\alpha}\overset{\mathrm{def}}{=}(1-\alpha)\frac{\psi_{i}}{\mathbb{E}\psi^{\star}(Z)}+\alpha,

and bound the following quantity

|1n​πˇn,iα−1πiα∧(n/sn)|\displaystyle\left|\frac{1}{n\check{\pi}_{n,i}^{\alpha}}-\frac{1}{\pi^{\alpha}_{i}\wedge(n/s_{n})}\right| =|n​πˇn,iα−πiα∧(n/sn)|n​πˇn,iα​(πiα∧(n/sn))\displaystyle=\frac{|n\check{\pi}_{n,i}^{\alpha}-\pi^{\alpha}_{i}\wedge(n/s_{n})|}{n\check{\pi}_{n,i}^{\alpha}(\pi^{\alpha}_{i}\wedge(n/s_{n}))}
=|(n​π~n,iα)∧(n/sn)−πiα∧(n/sn)|n​πˇn,iα​(πiα∧(n/sn))\displaystyle=\frac{|(n\tilde{\pi}_{n,i}^{\alpha})\wedge(n/s_{n})-\pi^{\alpha}_{i}\wedge(n/s_{n})|}{n\check{\pi}_{n,i}^{\alpha}(\pi^{\alpha}_{i}\wedge(n/s_{n}))}
≤|n​π~n,iα−πiα|n​πˇn,iα​(πiα∧(n/sn)),\displaystyle\leq\frac{|n\tilde{\pi}_{n,i}^{\alpha}-\pi^{\alpha}_{i}|}{n\check{\pi}_{n,i}^{\alpha}(\pi^{\alpha}_{i}\wedge(n/s_{n}))},

Using the inequality |a∧c−b∧c|≤|a−b||a\wedge c-b\wedge c|\leq|a-b| for a,b,c≥0a,b,c\geq 0. However, π~n,iα≥α/n\tilde{\pi}_{n,i}^{\alpha}\geq\alpha/n, πiα≥α\pi_{i}^{\alpha}\geq\alpha and α≤n/sn\alpha\leq n/s_{n} hence

|1n​πˇn,iα−1πiα∧(n/sn)|≤1α2​|n​π~n,iα−πiα|,\left|\frac{1}{n\check{\pi}_{n,i}^{\alpha}}-\frac{1}{\pi^{\alpha}_{i}\wedge(n/s_{n})}\right|\leq\frac{1}{\alpha^{2}}|n\tilde{\pi}_{n,i}^{\alpha}-\pi^{\alpha}_{i}|,

and

|1n2​∑i=1nℒ′​(Zi,h0,f)2πˇn,iα−1n​∑i=1nℒ′​(Zi,h0,f)2πiα∧(n/sn)|≤1α2​∑i=1nℒ′​(Zi,h0,f)2​|n​π~n,iα−πiα|.\left|\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\check{\pi}_{n,i}^{\alpha}}-\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\pi_{i}^{\alpha}\wedge(n/s_{n})}\right|\leq\frac{1}{\alpha^{2}}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}|n\tilde{\pi}_{n,i}^{\alpha}-\pi^{\alpha}_{i}|.

Furthermore

|n​π~n,iα−πiα|\displaystyle|n\tilde{\pi}_{n,i}^{\alpha}-\pi^{\alpha}_{i}| =(1−α)​|n∑j=1nψn,j​ψn,i−ψi⋆𝔼​ψ⋆|\displaystyle=(1-\alpha)\left|\frac{n}{\sum_{j=1}^{n}\psi_{n,j}}\psi_{n,i}-\frac{\psi_{i}^{\star}}{\mathbb{E}\psi^{\star}}\right|
≤(1−α)​n∑j=1nψn,j​|ψn,i−ψi⋆|+(1−α)​ψi⋆​|n∑j=1nψn,j−1𝔼​ψ⋆|.\displaystyle\leq(1-\alpha)\frac{n}{\sum_{j=1}^{n}\psi_{n,j}}|\psi_{n,i}-\psi_{i}^{\star}|+(1-\alpha)\psi_{i}^{\star}\left|\frac{n}{\sum_{j=1}^{n}\psi_{n,j}}-\frac{1}{\mathbb{E}\psi^{\star}}\right|.

We showed in the proof of Lemma A.15 that 1n​∑i=1n|ψn,i−ψi⋆|​⟶n→∞ℙ​0\frac{1}{n}\sum_{i=1}^{n}|\psi_{n,i}-\psi_{i}^{\star}|\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0,

1n​∑j=1nψn,j​⟶n→∞ℙ​𝔼​ψ⋆​(Z)and1n​∑i=1nℒ′​(Zi,h0,f)2​|ψn,i−ψi⋆|​⟶n→∞ℙ​0,\frac{1}{n}\sum_{j=1}^{n}\psi_{n,j}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}\psi^{\star}(Z)\quad\text{and}\quad\frac{1}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}|\psi_{n,i}-\psi_{i}^{\star}|\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0,

by Assumptions 1, 2 and 3 and the assumption that h^kn{\hat{h}_{k_{n}}} is consistent. Hence

(1−α)​n∑j=1nψn,j​(1n​∑i=1nℒ′​(Zi,h0,f)2​|ψn,i−ψi⋆|)​⟶n→∞ℙ​0,(1-\alpha)\frac{n}{\sum_{j=1}^{n}\psi_{n,j}}\left(\frac{1}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}|\psi_{n,i}-\psi_{i}^{\star}|\right)\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0,

and

(1−α)​|n∑j=1nψn,j−1𝔼​ψ⋆​(Z)|​(1n​∑i=1nℒ′​(Zi,h0,f)2​ψi⋆)​⟶n→∞ℙ​0.(1-\alpha)\left|\frac{n}{\sum_{j=1}^{n}\psi_{n,j}}-\frac{1}{\mathbb{E}\psi^{\star}(Z)}\right|\left(\frac{1}{n}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}\psi_{i}^{\star}\right)\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.

Therefore

|1n​∑i=1nℒ′​(Zi,h0,f)2n​πˇn,iα−1n​∑i=1nℒ′​(Zi,h0,f)2πiα∧(n/sn)|​⟶n→∞ℙ​0.\left|\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{n\check{\pi}_{n,i}^{\alpha}}-\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\pi_{i}^{\alpha}\wedge(n/s_{n})}\right|\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.

Now define the functions

gn:𝒛↦ℒ′​(𝒛,h0,f)2πα​(𝒛)∧(n/sn)andg:𝒛↦ℒ′​(𝒛,h0,f)2πα​(𝒛)∧c−1,g_{n}:\bm{z}\mapsto\frac{\mathcal{L}^{\prime}(\bm{z},{h_{0}},f)^{2}}{\pi^{\alpha}(\bm{z})\wedge(n/s_{n})}\quad\text{and}\quad g:\bm{z}\mapsto\frac{\mathcal{L}^{\prime}(\bm{z},{h_{0}},f)^{2}}{\pi^{\alpha}(\bm{z})\wedge c^{-1}},

for n>0n>0 with πα​(𝒛)​=def​(1−α)​ψ⋆​(𝒛)/𝔼⁡[ψ⋆​(Z)]+α\pi^{\alpha}(\bm{z})\overset{\mathrm{def}}{=}(1-\alpha)\psi^{\star}(\bm{z})/\mathbb{E}\left[\psi^{\star}(Z)\right]+\alpha. Note that even though cc may be null here, the function gg is well defined as πα​(𝒛)∧c−1\pi^{\alpha}(\bm{z})\wedge c^{-1} would simply be equal to πα​(𝒛)\pi^{\alpha}(\bm{z}). One has that the sequence of functions (gn)n>0(g_{n})_{n>0} is dominated by the integrable function 𝒛↦α−1​ℒ′​(𝒛,h0,f)2\bm{z}\mapsto\alpha^{-1}\mathcal{L}^{\prime}(\bm{z},{h_{0}},f)^{2} and converges pointwise towards gg. Thus

𝔼⁡[|1n​∑i=1ngn​(Zi)−1n​∑i=1ng⁡(Zi)|]\displaystyle\mathbb{E}\left[\left|\frac{1}{n}\sum_{i=1}^{n}g_{n}(Z_{i})-\frac{1}{n}\sum_{i=1}^{n}g(Z_{i})\right|\right] ≤1n​∑i=1n𝔼⁡[|gn​(Zi)−g⁡(Zi)|]\displaystyle\leq\frac{1}{n}\sum_{i=1}^{n}\mathbb{E}\left[|g_{n}(Z_{i})-g(Z_{i})|\right]
=𝔼⁡[|gn​(Z)−g⁡(Z)|]​⟶n→∞​0,\displaystyle=\mathbb{E}\left[\left|g_{n}(Z)-g(Z)\right|\right]\underset{n\rightarrow\infty}{\longrightarrow}0,

by the dominated convergence theorem. Therefore

|1n​∑i=1nℒ′​(Zi,h0,f)2πiα∧(n/sn)−1n​∑i=1nℒ′​(Zi,h0,f)2πiα∧c−1|​⟶n→∞ℙ​0.\left|\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\pi_{i}^{\alpha}\wedge(n/s_{n})}-\frac{1}{n}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\pi_{i}^{\alpha}\wedge c^{-1}}\right|\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}0.

and

1n2​∑i=1nℒ′​(Zi,h0,f)2πˇn,iα​⟶n→∞ℙ​𝔼​[𝔼​ψ⋆​(Z)Ψα⋆​(Z)∧(c−1​𝔼​ψ⋆​(Z))​ℒ′​(Z,h0,f)2].\frac{1}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{\check{\pi}_{n,i}^{\alpha}}\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}\left[\frac{\mathbb{E}\psi^{\star}(Z)}{\Psi^{\star}_{\alpha}(Z)\wedge(c^{-1}\mathbb{E}\psi^{\star}(Z))}\mathcal{L}^{\prime}(Z,{h_{0}},f)^{2}\right].

Which finally yields

∑i=1n𝔼⁡[η~n,i2|ℱ~n,i−1]\displaystyle\sum_{i=1}^{n}\mathbb{E}\left[\tilde{\eta}_{n,i}^{2}\middle|{\tilde{\mathcal{F}}_{n,i-1}}\right] =snn2​∑i=1nℒ′​(Zi,h0,f)2sn​πˇn,iα−snn2​∑i=1nℒ′​(Zi,h0,f)2\displaystyle=\frac{s_{n}}{n^{2}}\sum_{i=1}^{n}\frac{\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}}{s_{n}\check{\pi}_{n,i}^{\alpha}}-\frac{s_{n}}{n^{2}}\sum_{i=1}^{n}\mathcal{L}^{\prime}(Z_{i},{h_{0}},f)^{2}
⟶n→∞ℙ​𝔼​[𝔼​ψ⋆​(Z)Ψα⋆​(Z)∧(c−1​𝔼​[ψ⋆​(Z)])​ℒ′​(Z,h0,f)2]−c​𝔼​[ℒ′​(Z,h0,f)2],\displaystyle\overset{\mathbb{P}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathbb{E}\left[\frac{\mathbb{E}\psi^{\star}(Z)}{\Psi^{\star}_{\alpha}(Z)\wedge(c^{-1}\mathbb{E}\left[\psi^{\star}(Z)\right])}\mathcal{L}^{\prime}(Z,{h_{0}},f)^{2}\right]-c\mathbb{E}\left[\mathcal{L}^{\prime}(Z,{h_{0}},f)^{2}\right],

the wanted result. ∎

Proof of Theorem 5.2.

Since Assumption 5 is verified, by application of A.10 and following the proof of Theorem 3.2, one gets

sn​∇2ℛ​(h0)​(hsn∗α−h0)+oℙ​(1)\displaystyle\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h_{s_{n}}^{*\alpha}}-{h_{0}})+o_{\mathbb{P}}(1) =−sn​(∇Lsn∗α​(h0)−∇Ln​(h0))\displaystyle=-\sqrt{s_{n}}(\nabla{L}^{*\alpha}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}}))
−snn​n​(∇Ln​(h0)−∇L​(h0)).\displaystyle\qquad-\sqrt{\frac{s_{n}}{n}}\sqrt{n}(\nabla{L}_{n}({h_{0}})-\nabla{L}({h_{0}})).

Applying A.12 with ℱn=σ⁡(𝒟n,h^kn){\mathcal{F}_{n}}=\sigma({\mathcal{D}_{n}},{\hat{h}_{k_{n}}}) and Hn=sn​(∇Lsn∗α​(h0)−∇Ln​(h0))H_{n}=\sqrt{s_{n}}(\nabla{L}^{*\alpha}_{s_{n}}({h_{0}})-\nabla{L}_{n}({h_{0}})), together with Lemmas A.16 and A.11 yields

sn​∇2ℛ​(h0)​(hsn∗α−h0)​⟶n→∞d​𝒢​(0,ΣP,c∗​(α)+c​Σ).∎\sqrt{s_{n}}\nabla^{2}{\mathcal{R}}({h_{0}})({h_{s_{n}}^{*\alpha}}-{h_{0}})\overset{\mathrm{d}}{\underset{n\rightarrow\infty}{\longrightarrow}}\mathcal{G}(0,\Sigma^{*}_{\mathrm{P},c}(\alpha)+c\Sigma).\qed

Appendix B Additional numerical results

In the first paragraph of Section 6.2, we present a study of the impact of the smoothing hyperparameter α∈(0,1]\alpha\in(0,1] on the generalization error. Since our framework is based on the consistency of hsn∗α{h_{s_{n}}^{*\alpha}}, it is also of interest to analyze L2L^{2}, L∞L^{\infty} or ℍ\mathbb{H}-distances between hsn∗α{h_{s_{n}}^{*\alpha}} and h0{h_{0}}. These distances are represented (with respect to α\alpha) in Figures B.2 and B.1, respectively for the synthetic classification and regression tasks. Let us remark that, in practice, since h0{h_{0}} is unreachable, it is approximated by the ERM h^n{\hat{h}_{n}} computed on the full dataset (n=105n=10^{5}) with a very good Nyström approximation. The results are similar than those depicted in Figure 3 and show that a value of α\alpha between 0.10.1 and 0.40.4 leads to a better SRM estimator than uniform subsampling. This means that, in this setting, statistical and learning performances are in line with each other.

(a) L2L^{2}-distance.
(b) L∞L^{\infty}-distance.
(c) ℍ\mathbb{H}-distance.
Figure B.1: Approximated distances between the SRM hsn∗α{h_{s_{n}}^{*\alpha}} and the target h0{h_{0}} for the synthetic classification task (n=105n=10^{5} and bn/n=0.02b_{n}/n=0.02).
(a) L2L^{2}-distance.
(b) L∞L^{\infty}-distance.
(c) ℍ\mathbb{H}-distance.
Figure B.2: Approximated distances between the SRM hsn∗α{h_{s_{n}}^{*\alpha}} and the target h0{h_{0}} for the synthetic regression task (n=105n=10^{5} and bn/n=0.01b_{n}/n=0.01).

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